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1 Solved Question on Clairaut Theorem - Quiz 4 | MATH 2203, Quizzes of Advanced Calculus

Material Type: Quiz; Professor: Ellermeyer; Class: Calculus III; University: Kennesaw State University; Term: Spring 2008;

Typology: Quizzes

2010/2011

Uploaded on 06/03/2011

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MATH 2203 –Quiz 4 (Version 3) Solution
March 14, 2008
NAME________________________________
For the function
f(x; y) = x4y22xy5,
verify that fxy =fyx (as promised by Clairaut’s Theorem).
Solution:
fx= 4x3y22y5
fy= 2x4y10xy4
and hence
fxy =@
@y 4x3y22y5= 8x3y10y4
fyx =@
@x 2x4y10xy4= 8x3y10y4.
1

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MATH 2203 ñQuiz 4 (Version 3) Solution March 14, 2008

NAME________________________________

For the function f (x; y) = x 4 y 2 2 xy 5 ,

verify that fxy = fyx (as promised by Clairautís Theorem).

Solution:

fx = 4x 3 y 2 2 y 5

fy = 2x 4 y 10 xy 4

and hence

fxy =

@y

4 x 3 y 2 2 y 5

= 8x 3 y 10 y 4

fyx =

@x

2 x 4 y 10 xy 4

= 8x 3 y 10 y 4 .