Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Formula Mass and Molarity Calculations for Various Compounds, Slides of Chemistry

The formula mass calculations for various inorganic compounds such as ammonium chloride, sodium cyanide, magnesium hydroxide, calcium phosphate, lithium carbonate, hydrogen sulfite ion, potassium permanganate, sodium sulfate, hydrogen cyanide, potassium thiocyanate, ammonium oxalate, lithium acetate, chlorine gas, silver nitrate, aluminum chloride, calcium carbonate, iron(ii) sulfide, dinitrogen pentoxide, lead(ii) nitrate, ammonium phosphate, sulfuric acid, and potassium dichromate.

Typology: Slides

2021/2022

Uploaded on 09/12/2022

jannine
jannine 🇺🇸

4.9

(14)

240 documents

1 / 4

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
1. What is the formula mass of each species?
a. ammonium chloride : NH4Cl ; 14.01(N)+1.01(H)x4+35.45(Cl) = 53.5
b. sodium cyanide : NaCN ; 22.99 (Na) + 12.01 (C) + 14.01 (N) = 49.01
c. magnesium hydroxide : Mg(OH)2 ; 24.31 (Mg) + 2x (16.00 (O) + 1.01 (H)) = 58.33
d. calcium phosphate : Ca3(PO4)2 ; 3 x 40.08 (Ca) + 2x (30.97 (P) + 4x16.00(O)) = 310.18
e. lithium carbonate : Li2CO3 ; 2x 6.94 (Li) + 12.01 (C) + 3x 16.00 (O) = 73.89
f. hydrogen sulfite ion : HSO3 ; 1.01 (H) + 32.07 (S) + 3x 16.00 (O) = 81.08
2. What is the molecular or formula mass of each compound?
a. potassium permanganate : KMnO4 ; 39.1 (K) + 54.94 (Mn) + 4x 16.00 (O) = 158.04
b. sodium sulfate : Na2SO4 ; 2x 22.99 (Na) + 32.07 (S) + 4x 16.00 (O) = 142.05
c. hydrogen cyanide : HCN ; 1.01 (H) + 12.01 (C) + 14.01 (N) = 27.03
d. potassium thiocyanate : KSCN ; 39.1 (K) + 32.07 (S) + 12.01 (C) + 14.01 (N) = 97.19
e. ammonium oxalate : (NH)CO ; 2x (14.01 (N) + 4x 1.01 (H)) + 2x 12.01 (C) + 4x 16 (O) = 124.12
f. lithium acetate : C2H3LiO2 ; 2x 12.01 (C) + 3x 1.01 (H) + 6.94 (Li) + 2x 16 (O) = 65.99
3. How many moles are in each of the following?
a. 10.76 g of Si x 1 mol Si / 28.09 g Si = 0.383 mol Si
b. 8.6 g of Pb x 1 mol Pb / 207.20 g Pb = 0.042 mol Pb
c. 2.49 g of Mg x 1 mol Mg / 24.32 g Mg = 0.102 mol Mg
d. 0.94 g of La x 1 mol La / 138.91 g La = 0.00677 mol La
e. 2.68 g of chlorine gas x 1 mol Cl2 / 70.9 g Cl2 = 0.0378 mol Cl2
f. 0.089 g of As x 1 mol As / 74.92 g As = 0.00119 mol As
4. How many moles are in each of the following?
a. 8.6 g of CO2 x 1 mol CO2 / 44.01 g CO2 = 0.195 mol CO2
b. 2.7 g of CaO x 1 mol CaO / 56.08 g CaO = 0.048 mol CaO
c. 0.89 g of KCl x 1 mol KCl / 74.55 g KCl = 0.0119 mol KCl
d. 4.3 g of SrBr2 x 1 mol SrBr2 / 247.42 g SrBr2 = 0.0174 mol SrBr2
e. 2.5 g of NaOH x 1 mol NaOH / 40 g NaOH = 0.625 mol NaOH
f. 1.87 g of Ca(OH)2 x 1 mol Ca(OH)2 / 74.1 g Ca(OH)2 = 0.025 mol Ca(OH)2
5. Convert the following to moles (and millimoles).
a. 1.68 g of Ba(OH)2 x 1 mol Ba(OH)2 / 171.34 g Ba(OH)2 = 0.0098 mol (9.8 mmol) Ba(OH)2
b. 0.792 g of H3PO4 x 1 mol H3PO4 / 98 g H3PO4 = 0.008 mol (8.1mmol) H3PO4
c. 3.21 g of K2S x 1 mol K2S / 110.27 g K2S = 0.0291 mol K2S (29.1 mmol) K2S
pf3
pf4

Partial preview of the text

Download Formula Mass and Molarity Calculations for Various Compounds and more Slides Chemistry in PDF only on Docsity!

1. What is the formula mass of each species? a. ammonium chloride : NH 4 Cl ; 14.01(N)+1.01(H)x4+35.45(Cl) = 53. b. sodium cyanide : NaCN ; 22.99 (Na) + 12.01 (C) + 14.01 (N) = 49. c. magnesium hydroxide : Mg(OH) 2 ; 24.31 (Mg) + 2x (16.00 (O) + 1.01 (H)) = 58. d. calcium phosphate : Ca 3 (PO 4 ) 2 ; 3 x 40.08 (Ca) + 2x (30.97 (P) + 4x16.00(O)) = 310. e. lithium carbonate : Li 2 CO 3 ; 2x 6.94 (Li) + 12.01 (C) + 3x 16.00 (O) = 73. f. hydrogen sulfite ion : HSO 3 ; 1.01 (H) + 32.07 (S) + 3x 16.00 (O) = **81.

  1. What is the molecular or formula mass of each compound?** a. potassium permanganate : KMnO 4 ; 39.1 (K) + 54.94 (Mn) + 4x 16.00 (O) = 158. b. sodium sulfate : Na 2 SO 4 ; 2x 22.99 (Na) + 32.07 (S) + 4x 16.00 (O) = 142. c. hydrogen cyanide : HCN ; 1.01 (H) + 12.01 (C) + 14.01 (N) = 27. d. potassium thiocyanate : KSCN ; 39.1 (K) + 32.07 (S) + 12.01 (C) + 14.01 (N) = 97. e. ammonium oxalate : (NH₄)₂C₂O₄ ; 2x (14.01 (N) + 4x 1.01 (H)) + 2x 12.01 (C) + 4x 16 (O) = 124. f. lithium acetate : C 2 H 3 LiO 2 ; 2x 12.01 (C) + 3x 1.01 (H) + 6.94 (Li) + 2x 16 (O) = **65.
  2. How many moles are in each of the following?** a. 10.76 g of Si x 1 mol Si / 28.09 g Si = 0.383 mol Si b. 8.6 g of Pb x 1 mol Pb / 207.20 g Pb = 0.042 mol Pb c. 2.49 g of Mg x 1 mol Mg / 24.32 g Mg = 0.102 mol Mg d. 0.94 g of La x 1 mol La / 138.91 g La = 0.00677 mol La e. 2.68 g of chlorine gas x 1 mol Cl 2 / 70.9 g Cl 2 = 0.0378 mol Cl 2 f. 0.089 g of As x 1 mol As / 74.92 g As = **0.00119 mol As
  3. How many moles are in each of the following?** a. 8.6 g of CO 2 x 1 mol CO 2 / 44.01 g CO 2 = 0.195 mol CO 2 b. 2.7 g of CaO x 1 mol CaO / 56.08 g CaO = 0.048 mol CaO c. 0.89 g of KCl x 1 mol KCl / 74.55 g KCl = 0.0119 mol KCl d. 4.3 g of SrBr 2 x 1 mol SrBr 2 / 247.42 g SrBr 2 = 0.0174 mol SrBr 2 e. 2.5 g of NaOH x 1 mol NaOH / 40 g NaOH = 0.625 mol NaOH f. 1.87 g of Ca(OH) 2 x 1 mol Ca(OH) 2 / 74.1 g Ca(OH) 2 = **0.025 mol Ca(OH) 2
  4. Convert the following to moles (and millimoles).** a. 1.68 g of Ba(OH) 2 x 1 mol Ba(OH) 2 / 171.34 g Ba(OH) 2 = 0.0098 mol (9.8 mmol) Ba(OH) 2 b. 0.792 g of H 3 PO 4 x 1 mol H 3 PO 4 / 98 g H 3 PO 4 = 0.008 mol (8.1mmol) H 3 PO 4 c. 3.21 g of K 2 S x 1 mol K 2 S / 110.27 g K 2 S = 0.0291 mol K 2 S (29.1 mmol) K 2 S

d. 0.8692 g of Cu(NO 3 ) 2 x 1 mol Cu(NO 3 ) 2 / 187.57 g Cu(NO 3 ) 2 = 0.00463 mol (4.63 mmol) Cu(NO 3 ) 2 e. 10.648 g of Ba 3 (PO 4 ) 2 x 1 mol Ba 3 (PO 4 ) 2 / 601.9 g Ba 3 (PO 4 ) 2 = 0.0177 mol (17.7 mmol) Ba 3 (PO 4 ) 2 f. 5.79 g of (NH 4 ) 2 SO 4 x 1 mol (NH 4 ) 2 SO 4 / 132.17 g (NH 4 ) 2 SO 4 = 0.044 mol (44 mmol) (NH 4 ) 2 SO 4 g. 1.32 g of Pb(C 2 H 3 O 2 ) 2 x 1 mol Pb(C 2 H 3 O 2 ) 2 / 325.3 g Pb(C 2 H 3 O 2 ) 2 = 0.0041 mol (4.1 mmol) Pb(C 2 H 3 O 2 ) 2 h. 4.29 g of CaCl 2 ∙6H 2 O x 1 mol CaCl 2 ∙6H 2 O / 219.1 g CaCl 2 ∙6H 2 O = 0.0196 mol (19.6 mmol) CaCl 2 ∙6H 2 O

6. Convert the following to moles (and millimoles). a. 0.089 g of silver nitrate (AgNO 3 ) x 1 mol AgNO 3 / 169.88 g AgNO 3 = 5.24E-4 mol (5.24E-1 mmol) AgNO 3 b. 1.62 g of aluminum chloride (AlCl 3 ) x 1 mol AlCl 3 / 133.33 g AlCl 3 = 0.0122 mol (12.2 mmol) AlCl 3 c. 2.37 g of calcium carbonate (CaCO 3 ) x 1 mol CaCO 3 / 100.09 g CaCO 3 = 0.0237 mol (23.7 mmol) CaCO 3 d. 1.004 g of iron(II) sulfide (FeS) x 1 mol FeS/ 87.92 g FeS = 0.0114 mol (11.4 mmol) FeS e. 2.12 g of dinitrogen pentoxide (N 2 O 5 ) x 1 mol N 2 O 5 / 108.02 g N 2 O 5 = 0.0197 mol (19.7 mmol) N 2 O 5 f. 2.68 g of lead(II) nitrate (Pb(NO 3 ) 2 ) x 1 mol Pb(NO 3 ) 2 / 331.22 g Pb(NO 3 ) 2 = 0.0081 mol (8.1 mmol) Pb(NO 3 ) 2 g. 3.02 g of ammonium phosphate ((NH₄)₃PO₄) x 1 mol (NH₄)₃PO₄/ 149.12g (NH₄)₃PO₄ = 0.0203 mol (NH₄)₃PO₄ h. 5.852 g of sulfuric acid (H 2 SO 4 ) x 1 mol H 2 SO 4 / 98.09 g H 2 SO 4 = 0.0597 mol (59.7 mmol) H 2 SO 4 i. 4.735 g of potassium dichromate (K 2 Cr 2 O 7 ) x 1 mol K 2 Cr 2 O 7 /294.2 g K 2 Cr 2 O 7 = **0.0161 mol (16 mmol) K 2 Cr 2 O 7

  1. What is the mass of each substance in grams (and milligrams)?** a. 5.68 mol of Ag x 107.87 g Ag/ 1 mol Ag = 613 g (6.13E+5 mg) Ag b. 2.49 mol of Sn x 118.71 g Sn/ 1 mol Sn = 295.6 g (2.96E+5 mg) Sn c. 0.0873 mol of Os x 190.2 g Os/ 1 mol Os = 16.6 g (1.7E+4 mg) Os d. 1.74 mol of Si x 28.09 g Si/ 1 mol Si = 48.88 g (4.9E+4 mg) Si e. 0.379 mol of H2 x 2.02g H 2 / 1 mol H 2 = 0.766 g (7.7E+2 mg) H 2 f. 1.009 mol of Zr x 91.22g Zr/ 1 mol Zr = **92.04 g (9.2E+4 mg) Zr
  2. What is the mass of each substance in grams (and milligrams)?** a. 2.080 mol of CH 3 OH x 32.05 g CH 3 OH/ 1 mol CH 3 OH = 66.66 g (6.7E+4 mg) CH 3 OH b. 0.288 mol of P 4 x 123.88 g P 4 / 1 mol P 4 = 35.677 g (3.6E+4 mg) P 4 c. 3.89 mol of ZnCl 2 x 136.29g ZnCl 2 / 1 mol ZnCl 2 = 530.17 g (5.3E+5 mg) ZnCl 2 d. 1.800 mol of Fe(CO) 5 x 195.9g Fe(CO) 5 / 1 mol Fe(CO) 5 = 352.62 g (3.5E+5 mg) Fe(CO) 5 e. 0.798 mol of S 8 x 256.56g S 8 / 1 mol S 8 = 204.7 g (2.0E+5 mg) S 8 f. 4.01 mol of NaOH x 40g NaOH/ 1 mol NaOH = **160.4g (1.6E+5 mg) NaOH
  3. What is the mass of each compound in kilograms?** a. 6.38 mol of P 4 O 10 x 283.88g P 4 O 10 / 1 mol P 4 O 10 = 1811.15g x 1 kg/ 1000 g = 1.8 kg P 4 O 10 b. 2.26 mol of Ba(OH) 2 x 171.34g Ba(OH) 2 / 1 mol Ba(OH) 2 = 387.23 g x 1 kg/ 1000 g = 0.39 kg Ba(OH) 2