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Control Systems: Time Response of 2nd-Order Systems, Study notes of Engineering

A lecture note from Michigan State University's ME451: Control Systems course. It covers the time response of second-order systems, including step response, transfer function poles, and the influence of pole location on step response. Topics include electrical, mechanical, and electromechanical systems, block diagrams, linearization, modeling, analysis, design, and stability. The lecture also includes examples and Matlab simulations.

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2021/2022

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ME451: Control Systems
ME451: Control Systems
Prof. Clark Radcliffe and Prof.
Prof. Clark Radcliffe and Prof. Jongeun Choi
Jongeun Choi
Department of Mechanical Engineering
Department of Mechanical Engineering
Michigan State University
Michigan State University
Lecture
Lecture 12
12
Time response of 2nd-order systems
Time response of 2nd-order systems
2
Course roadmap
Course roadmap
Laplace transformLaplace transform
Transfer functionTransfer function
Models for systemsModels for systems
electrical electrical
mechanical mechanical
electromechanical electromechanical
Block diagramsBlock diagrams
LinearizationLinearization
Modeling
Modeling Analysis
Analysis Design
Design
Time responseTime response
Transient Transient
Steady state Steady state
Frequency responseFrequency response
Bode plot Bode plot
StabilityStability
Routh-HurwitzRouth-Hurwitz
Nyquist Nyquist
Design specsDesign specs
Root locusRoot locus
Frequency domainFrequency domain
PID & Lead-lagPID & Lead-lag
Design examplesDesign examples
(
(Matlab
Matlab simulations &) laboratories
simulations &) laboratories
3
2
2nd
nd Order Systems
Order Systems
0
0thth Order Systems: 1 parameter
Order Systems: 1 parameter
Strength of response
Strength of response
called
called
Gain
Gain
1
1stst Order Systems: 2 parameters
Order Systems: 2 parameters
Strength of response
Strength of response
called
called
Gain
Gain
Time to respond
Time to respond
called
called
Time Constant
Time Constant
2
2ndnd Order Systems: 3 parameters
Order Systems: 3 parameters
Strength of response
Strength of response
called
called
Gain
Gain
Time to respond
Time to respond
called
called
Time Constant
Time Constant
Oscillation rate
Oscillation rate
called
called
Frequency
Frequency
4
Second-order systems
Second-order systems
A
A standard form
standard form of the second-order system
of the second-order system
DC motor position control example
DC motor position control example
Closed-loop TF
Closed-loop TF
MotorMotorAmplifierAmplifier
G(s)=k
!
n
2
s2+2
"!
n
( )
s+
!
n
2
"
: damping ratio
!
n:undamped natural frequency
#
$
%
&
%
Note: the book does not include gain k in its standard form
5
Step response for 2nd-order system
Step response for 2nd-order system
Input a
Input a unit step function
unit step function to a 2nd-order system.
to a 2nd-order system.
What is the output?
What is the output?
00
11
u(t)u(t) y(t)y(t)
00
DC gain for a unit step (if
DC gain for a unit step (if G(s)
G(s) is stable)
is stable)
lim
t!" y(t)
( )
=lim
s!0sG(s)U(s)
( )
=lim
s!0sG(s)1
s
#
$
%&
'
(=lim
s!0G(s)
( )
=G(0) =k
k
!
n
2
s2+2
"!
n
( )
s+
!
n
2
6
Step response for 2nd-order system
Step response for 2nd-order system
for various damping ratio
for various damping ratio
Undamped
Undamped
Underdamped
Underdamped
Critically damped
Critically damped
Overdamped
Overdamped
0 5 10 15
0
0.5
1
1.5
2
y(t)
k
pf3
pf4
pf5

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1

ME451: Control SystemsME451: Control Systems

Prof. Clark Radcliffe and Prof.Prof. Clark Radcliffe and Prof. Jongeun ChoiJongeun Choi

Department of Mechanical EngineeringDepartment of Mechanical Engineering

Michigan State University Michigan State University

Lecture

Lecture

Time response of 2nd-order systems

Time response of 2nd-order systems

2

Course roadmap

Course roadmap

Laplace transformLaplace transform

Transfer functionTransfer function

Models for systemsModels for systems

  • • electricalelectrical
  • • mechanicalmechanical
  • • electromechanicalelectromechanical

Block diagramsBlock diagrams

LinearizationLinearization

ModelingModeling AnalysisAnalysis DesignDesign

Time responseTime response

  • • TransientTransient
  • • Steady stateSteady state

Frequency responseFrequency response

  • • Bode plotBode plot

StabilityStability

  • • Routh-HurwitzRouth-Hurwitz
  • • NyquistNyquist

Design specsDesign specs

Root locusRoot locus

Frequency domainFrequency domain

PID & Lead-lagPID & Lead-lag

Design examplesDesign examples

((MatlabMatlab simulations &) laboratoriessimulations &) laboratories

3

nd

nd

Order Systems

Order Systems

thth

Order Systems: 1 parameterOrder Systems: 1 parameter

 ““Strength of responseStrength of response”” calledcalled ““GainGain””

stst

Order Systems: 2 parametersOrder Systems: 2 parameters

 ““Strength of responseStrength of response”” calledcalled ““GainGain””

 ““Time to respondTime to respond”” calledcalled ““Time ConstantTime Constant””

ndnd

Order Systems: 3 parametersOrder Systems: 3 parameters

 ““Strength of responseStrength of response”” calledcalled ““GainGain””

 ““Time to respondTime to respond”” calledcalled ““Time ConstantTime Constant””

 ““Oscillation rateOscillation rate”” calledcalled ““FrequencyFrequency””

4

Second-order systemsSecond-order systems

 AA standard formstandard form of the second-order systemof the second-order system

 DC motor position control exampleDC motor position control example

Closed-loop TFClosed-loop TF

AmplifierAmplifier MotorMotor

G ( s ) =

k!

n

2

s

2

  • 2 "!

n

( )

s +!

n

2

" : damping ratio

n

: undamped natural frequency

Note: the book does not include gain “ k ” in its standard form

5

Step response for 2nd-order systemStep response for 2nd-order system

  Input aInput a unit step functionunit step function to a 2nd-order system.to a 2nd-order system.

What is the output?

What is the output?

00

11

u(t)u(t) y(t)y(t)

00

DC gain for a unit step (ifDC gain for a unit step (if G(s)G(s) is stable)is stable)

lim

t !"

( y ( t )) = lim

s! 0

( s G ( s ) U ( s )) = lim

s! 0

sG ( s )

s

= lim

s! 0

( G ( s )) = G ( 0 ) = k

k! n

2

s

2

n

( ) s +! n

2

6

Step response for 2nd-order systemStep response for 2nd-order system

for various damping ratiofor various damping ratio

 UndampedUndamped

 UnderdampedUnderdamped

 Critically dampedCritically damped

 OverdampedOverdamped

0 5 10 15

0

0. 5

1

1. 5

2

y ( t )

k

7

Step response for 2nd-order systemStep response for 2nd-order system

Underdamped Underdamped casecase

Math expression of y(t) for

Math expression of y(t) for

underdamped

underdamped

case

case

Damped natural frequencyDamped natural frequency

Y ( s ) = G ( s ) U ( s ) =

k!

n

2

s

2

  • 2 "!

n

s +!

n

2

s

y ( t ) = k 1!

e

! "# n

t

2

sin

d

( t + $)

! = tan

" 1

2

8

Step response for 2nd-order systemStep response for 2nd-order system

UnderdampedUnderdamped casecase

Math expression of y(t) for

Math expression of y(t) for

underdamped

underdamped

case

case

 Damped response frequencyDamped response frequency

Response time constant

Response time constant

y ( t ) = k 1!

e

! "# n

t

2

sin

d

( t + $)

! = tan

" 1

2

n

9

Transfer Function Poles

Transfer Function Poles

 For the 2nd order transfer functionFor the 2nd order transfer function

 The denominator ==> Characteristic PolynomialThe denominator ==> Characteristic Polynomial

 The Characteristic Polynomial roots areThe Characteristic Polynomial roots are thethe ““polespoles””

 2nd order ==> 2 roots ==> two poles2nd order ==> 2 roots ==> two poles

G ( s ) =

k!

n

2

s

2

n

s +!

n

2

s

1 , 2

n

± j

n

2

s

2

n

s + "

n

2

10

Transfer Function Poles Transfer Function Poles

Poles for the 2nd order transfer function

Poles for the 2nd order transfer function

Step Response

Step Response

  The system poles set the response characteristicsThe system poles set the response characteristics

  Re(Re( ss

1,21,

) =1/) =1/ττ andand ImIm(( ss

1,21,

dd

G ( s ) =

k!

n

2

s

2

n

( ) s +!

n

2

s

1 , 2

n

± j

n

2

y ( t ) = k 1!

e

! "# n

t

2

sin

d

( t + $)

n

11

Step response for 2nd-order systemStep response for 2nd-order system

for various damping ratiosfor various damping ratios

  UndampedUndamped

  UnderdampedUnderdamped

  Critically dampedCritically damped

  OverdampedOverdamped

0 5 10 15

0

0. 5

1

1. 5

2

y ( t )

k

s

1 , 2

n

± j

n

2

= 0 ± j

n

2

= ± j

n

Complex conjugate imaginary poles

12

Step response for 2nd-order systemStep response for 2nd-order system

for various damping ratiosfor various damping ratios

 UndampedUndamped

 UnderdampedUnderdamped

 Critically dampedCritically damped

 OverdampedOverdamped

0 5 10 15

0

0. 5

1

1. 5

2

y ( t )

k

s

1 , 2

n

± j

n

2

Complex conjugate complex poles

19

Settling Time

Settling Time

Measures how long it takes to stay within a set

Measures how long it takes to stay within a set

percentage of steady statepercentage of steady state

Example 2% = 0.

Example 2% = 0.

  So a system settlesSo a system settles

within 2% of final valuewithin 2% of final value

in about tin about t ≅≅ 44 ττ

2% settling time =

2% settling time = 4

τ

τ

y ( t ) = k 1!

e

! "# n

t

2

sin #

d

t + $

0.02 = e

! "# n

t

= e

! t $

t $ =! ln 0.

( )

20

Properties of 2nd-order system

Properties of 2nd-order system

21

Influence of real part of poles

Influence of real part of poles

Settling time

Settling time

ts

ts

decreases.

decreases.

tsts

22

Influence ofInfluence of imagimag. part of poles. part of poles

 Oscillation frequencyOscillation frequency ωω

dd

increases.increases.

23

Influence of angle of polesInfluence of angle of poles

  Over/under-shoot decreases.Over/under-shoot decreases.

24

An exampleAn example

 Require 5% settling timeRequire 5% settling time tsts << tsmtsm (given):(given):

ReRe

ImIm

25

An example (cont

An example (cont

d)

d)

Require PO <

Require PO <

POm

POm

(given):

(given):

ReRe

ImIm

26

An example (cont

An example (cont

d)

d)

Combination of two requirements

Combination of two requirements

ReRe

ImIm

&&

27

Some remarks

Some remarks

Percent overshoot depends on

Percent overshoot depends on

, but NOT

, but NOT

ωnn

From 2nd-order transfer function, analytic

From 2nd-order transfer function, analytic

expressions of delay & rise time are hard to expressions of delay & rise time are hard to

obtain. obtain.

 Time constant is 1/(Time constant is 1/(ζωζωnn), indicating), indicating

convergence speed. convergence speed.

 ForFor ζζ>1, we cannot define peak time, peak>1, we cannot define peak time, peak

value, percent overshoot. value, percent overshoot.

28

Performance measures (review)Performance measures (review)

 Transient responseTransient response

  Peak valuePeak value

  Peak timePeak time

Percent overshoot

Percent overshoot

  Delay timeDelay time

Rise time

Rise time

  Settling timeSettling time

 Steady state responseSteady state response

  Steady state gainSteady state gain

Next, we will connectNext, we will connect

these measuresthese measures

with s-domain.

with s-domain.

(Today(Today’’s lecture)s lecture)

29

Summary Summary

  Transient response of 2nd-order system isTransient response of 2nd-order system is

characterized by

characterized by

 Damping ratioDamping ratio ζζ && undampedundamped natural frequencynatural frequency ωωnn

 Pole locationsPole locations

  Delay time and rise time are not so easy toDelay time and rise time are not so easy to

characterize, and thus not covered in this course.characterize, and thus not covered in this course.

  For transient responses of high order systems,For transient responses of high order systems,

we need computer simulations.

we need computer simulations.