



Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Community
Ask the community for help and clear up your study doubts
Discover the best universities in your country according to Docsity users
Free resources
Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors
Solutions to various related rates problems involving calculus concepts such as rates of change of volumes, distances, areas, and thicknesses. The problems cover topics like spherical snowball melting, train moving towards a camera, water tank, oil slick expansion, and hemispherical bowl. These problems help students understand the concept of related rates and its applications in physics and engineering.
Typology: Study notes
1 / 5
This page cannot be seen from the preview
Don't miss anything!
Mth 201 Related Rates Practice Problems
dV dt
= 4πr^2
dr dt
Plugging in r = 15 and dr/dt = − 0 .2, we get dv/dt = 4π(15)^2 (− 0 .2) ∼ − 565. 5 cm^3 /hr.
Train
Camera
0.8kn/hr
Theta z
x
0.5km
(a) Express z, the distance between the camera and the train as a function of x. Solution: Using Pythagoras Theorem, we have x^2 + (0.5)^2 = z^2 , so z =
x^2 +
(b) How fast is the distance from the camera to the train changing when the train is 1km from the camera? Give units. Solution:
x^2 +
= z^2.
2 x
dx dt
= 2z
dz dt giving dz dt
x z
dx dt
When z = 1, we have x =
3 /2 so dz/dt = 0. 8
(c) How fast is the camera rotating (in radians/min) at the moment when the train is 1km from the camera? Solution:
dθ dt
dx dt or dθ dt
= 2 cos^2 (θ)
dx dt
When z = 1 and x = 0 .5, then θ = π/3 (using simple trigonometry), so dθ/dt = 2 · (0.5)^2 · 0 .8 = 0. 4 rads/min.
2 π · r · T
dr dt
dT dt
or dT dt
r
dr dt
Evaluating when T = 0.2, r = 150 and dr/dt = 0.1, we have dT /dt = − 2 ∗ 0. 2 / 150 ∗ 0 .1 = − 0. 000267 cm/hr.
r^2 + (10 − h)^2 = r^2 + h^2 − 20 h + 100 = 10^2 = 100
or r =
(20h − h^2 ).
10−h
10
10
h
10
r
(b) The water level drops at a rate of 0.1cm per hour. At what rate is the radius of water decreasing when the depth is 5cm? Solution:
2 r
dr dt
dh dt
− 2 h
dh dt or dr dt
r
dh dt
h r
dh dt
When the depth is 5, we have h = 5 and r =
dr dt
(a) Is the distance between the between the car and truck increasing or decreasing? How fast? (Distance is measured along a straight line joining the car and truck). Solution: This question is almost identical to the one we did in class. (b) How does your answer change of the truck is going 70mph instead of 80mph? Solution: This question is almost identical to the one we did in class.