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Scientific Notation and The Speed of Light: Calculating Distances and Time of Radio Waves, Lecture notes of Science education

An explanation of scientific notation and its application in calculating the distance traveled by radio waves at the speed of light and the time it takes to cover those distances. It includes examples and problems to practice the concepts.

Typology: Lecture notes

2021/2022

Uploaded on 09/12/2022

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ACTIVITY 1-1 Scientific Notation and The Speed of Light
Radio waves, like all electromagnetic waves, travel at the speed of light – 300 000 000 meters
per second (3 hundred million meters per second). The speed of light is obviously a large
number. In working with this number, and other large numbers, it is convenient to express it in
scientific notation. In scientific notation, powers of ten are used to represent the zeroes in large
numbers. The following table shows how this is done.
Number
Name
Power of ten
1
one
100
10
ten
101
100
hundred
102
1000
thousand
103
10000
ten thousand
104
100000
hundred thousand
105
1000000
million
106
10000000
ten million
107
100000000
hundred million
108
1000000000
billion
109
If you examine the first and last columns, you can see that the power of ten is the same as the
number of zeroes in the number. So the speed of light, which is 3 followed by 8 zeroes, becomes
3 x 108 meters per second. The standard symbol for the speed of light is c, so we can write:
c = 3 x 108 m/s
Since radio waves travel at a constant speed, the distance traveled is given by:
distance = speed times time
or d = c t
where d = distance in meters
t = time in seconds
c = 3 x 108 meters per second
Example Problem: How far does a radio wave travel in 5 minutes?
t = 5 min = 5(60) = 300 s = 3 x 102 s
c = 3 x 108 m/s
d = ? m
d = c t
d = (3 x 108) (3 x 102)
d = (3 x 3) x 108+2
d = 9 x 1010 m
RULE: to multiply,
MULTIPLY the numbers,
ADD the powers of ten
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ACTIVITY 1 - 1 Scientific Notation and The Speed of Light Radio waves, like all electromagnetic waves, travel at the speed of light – 300 000 000 meters per second (3 hundred million meters per second). The speed of light is obviously a large number. In working with this number, and other large numbers, it is convenient to express it in scientific notation. In scientific notation, powers of ten are used to represent the zeroes in large numbers. The following table shows how this is done. Number Name Power of ten 1 one 100 10 ten 101 100 hundred 102 1000 thousand 103 10000 ten thousand 104 100000 hundred thousand 105 1000000 million 106 10000000 ten million 107 100000000 hundred million 108 1000000000 billion 109 If you examine the first and last columns, you can see that the power of ten is the same as the number of zeroes in the number. So the speed of light, which is 3 followed by 8 zeroes, becomes 3 x 108 meters per second. The standard symbol for the speed of light is c , so we can write: c = 3 x 10^8 m/s Since radio waves travel at a constant speed, the distance traveled is given by: distance = speed times time or d = c t where d = distance in meters t = time in seconds c = 3 x 10^8 meters per second Example Problem: How far does a radio wave travel in 5 minutes? t = 5 min = 5(60) = 300 s = 3 x 10^2 s c = 3 x 10^8 m/s d =? m d = c t d = (3 x 10^8 ) (3 x 10^2 ) d = (3 x 3) x 108+ d = 9 x 10^10 m RULE: to multiply, MULTIPLY the numbers, ADD the powers of ten

Problems:

  1. How far does light travel in 20 seconds?
  2. How far does light travel in 30 minutes?
  3. How far does light travel in 4 hours?
  4. How far does light travel in 2 days? If you know the distance and the speed (c), you can find the time it takes for radio waves to travel that distance using: d = c t where d = distance in meters (m) c = speed of light (3 x 10^8 m/s) t = time in seconds (s) Example Problem: How long does it take radio waves to travel from Earth to the moon, a distance of 400 000 kilometers? d = 400 000 km = 400 000 000 m = 4 x 10^8 m c = 3 x 10^8 m/s t =? t = 1.33 x 10^0 (NOTE: 100 = 1) t = 1.33 s t = d c t = d c RULE: to divide, DIVIDE the numbers and SUBTRACT the powers of ten. (Subtract the bottom power from the top) t = 4 x 10^8 3 x 10^8 t =

x 108 -^8

Use the following table for Problems 5-8. Planet Radius of orbit Mercury 57,910,000 km Venus 108,200,000 km Earth 149,600,000 km Mars 227,940,000 km Jupiter 778,330,000 km Saturn 1,429,400,000 km In the following problems, assume that the planets are on the same side of the sun (as close to one another as possible). Problems:

  1. How long would it take radio waves to travel from Jupiter to Mars?
  2. How long would it take radio waves to travel from Jupiter to Venus? On these last two problems, be careful when you subtract the distances that they have the same power of ten. (HINT: one distance will not be in standard form.)
  3. How long would it take radio waves to travel from Jupiter to Saturn?
  4. How long would it take radio waves to travel from Mercury to Mars? Answer key for Activity 1.
  5. 6 x 10^9 m
  6. 5.4 x 10^11 m
  7. 4.32 x 10^12 m
  8. 5.18 x 10^13 m
  9. 1.83 x 10^3 s (30.6 minutes)
  10. 2.23 x 10^3 s (37 minutes)
  11. 2.17 x 10^3 s (36 minutes)
  12. 5.6 x 10^2 s (9.4 minutes)