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A comprehensive introduction to trigonometry, covering fundamental concepts, trigonometric ratios, formulas, and identities. It explores the relationship between sides and angles in right-angled triangles and delves into the application of trigonometry in various fields, including science and engineering. The document also includes solved examples and explanations to enhance understanding.
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Trigonometry is a branch of mathematics that studies the relationship between the sides and angles of a right-angled triangle. It uses trigonometric ratios to find the missing or unknown angles or sides of a triangle.
Trigonometric ratios
● Sine : The ratio of the opposite side to the hypotenuse ● ● Cosine : The ratio of the adjacent side to the hypotenuse ● ● Tangent : The ratio of the opposite side to the adjacent side ● ● Cosecant : The ratio of the hypotenuse to the opposite side ● ● Secant : The ratio of the hypotenuse to the adjacent side ● ● Cotangent : The ratio of the adjacent side to the opposite side
Trigonometric formulas
● sin θ = Opposite Side/Hypotenuse ● ● cos θ = Adjacent Side/Hypotenuse ● ● tan θ = Opposite Side/Adjacent Side ● ● sec θ = Hypotenuse/Adjacent Side ● ● cosec θ = Hypotenuse/Opposite Side ● ● cot θ = Adjacent Side/Opposite
Trigonometric functions are also used to find the length of an arc of a circ
Hipparchus (180–125 BC) is known as the "father of trigonometry".
He was a Greek astronomer, mathematician, and geographer.
S.no Property Mathematical value
1 sin A Perpendicular/Hypotenuse
2 cos A Base/Hypotenuse
4 sec A 1/cos A
● sin (-θ) = − sin θ ● ● cos (−θ) = cos θ ● ● tan (−θ) = − tan θ ● ● cosec (−θ) = − cosec θ ● ● sec (−θ) = sec θ ● ● cot (−θ) = − cot θ
● sin2A + cos2A = 1 ● ● tan2A + 1 = sec2A ● ● cot2A + 1 = cosec2A
● sin (3π/2 + θ) = – cos θ ● ● cos (3π/2 + θ) = sin θ ● ● sin (2π – θ) = – sin θ ● ● cos (2π – θ) = cos θ
● sin (A + B) = sin A cos B + cos A sin B ● ● sin (A − B) = sin A cos B – cos A sin B ● ● cos (A + B) = cos A cos B – sin A sin B ● ● cos (A – B) = cos A cos B + sin A sin B ● ● tan(A + B) = [(tan A + tan B) / (1 – tan A tan B)] ● ● tan(A – B) = [(tan A – tan B) / (1 + tan A tan B)]
● sin 2A = 2 sin A cos A = [2 tan A /(1 + tan2A)] ● ● cos 2A = cos2A – sin2A = 1 – 2 sin2A = 2 cos2A – 1 = [(1 – tan2A)/(1 + tan2A)] ● ● tan 2A = (2 tan A)/(1 – tan2A)
● sin 3A = 3 sinA – 4 sin3A ● ● cos 3A = 4 cos3A – 3 cos A ● ● tan 3A = [3 tan A – tan3A] / [1 − 3 tan2A]
Q1. If cot Q = tan P then prove that P + Q = 90°.
Ans. Given,
tan P = cot Q
As we know, cot(90° – A) = Tan A.
So, cot Q = cot(90° – P)
Therefore, Q = 90° – P
And
P + Q = 90°
Hence proved.
While these developments shifted trigonometry away from its original connection to triangles, the practical aspects of the subject were not neglected. The 17th and 18th centuries saw the invention of numerous mechanical devices—from accurate clocks and navigational tools to musical instruments of superior quality and greater tonal