Download AMA Calculus 1 Prelim Exam and more Exams Calculus in PDF only on Docsity!
Home / My courses / UGRD-MATH6100-2013T / Week 10: Application of Derivatives / FINAL QUIZ 1
Question 1
Not yet answered Marked out of
Question 2
Not yet answered Marked out of
Question 3
Not yet answered Marked out of
Determine all the critical points for the function.
Select one:
a. 0
b. 0.
c. no correct answer
d. 0.
Clear my choice
f ( x ) = x^2 ln (3 x ) + 6
Determine all the critical points for the function
Select one:
a. 1.2217; 1.
b. 1.7991; 1.
c. 1.2217; 0.
d. 1.1991; 1.
Clear my choice
y = 6 x − 4 cos (3 x )
x =??? + 2 πn 3 , n = 0, ±1, ±2,...
x =??? + 2 πn 3 , n = 0, ±1, ±2,...
Use chain rule to calculate of
Select one:
a.
b.
c.
d.
Clear my choice
dy dx
y = (5 x^2 + 11 x )
= (−20)(5 + 11 x (10 x − 11)
dy
dx x
= (−20)(5 + 11 x (10 x + 11)
dy
dx x
= (20)(5 + 11 x (10 x + 11)
dy
dx x
= (20)(5 + 11 x (10 x − 11)
dy
dx x
Question 4
Not yet answered
Marked out of
Question 5
Not yet answered
Marked out of
Question 6
Not yet answered
Marked out of
For the function
on [-2,2]
Find the critical points and the absolute extreme values of f on the given interval.
Select one:
a. as the critical points
absolute maximum value of f:
absolute minimum value of f:
b. as the critical points
absolute maximum value of f:
absolute minimum value of f:
c. as the critical points
absolute maximum value of f:
absolute minimum value of f:
d. as the critical points
absolute maximum value of f:
absolute minimum value of f::
Clear my choice
f ( x ) = x ( x^2 +1^ )^2
x = ± (^23)
−− √
−3 √ 3 16 3 √ 3 16
x = (^13)
−− √
−3 (^) √ 3 16 −3 (^) √ 3 16
x = ± (^13)
−− √ 3 √ 3 16 3 √ 3 16
x = ± (^12)
−− √ 3 √ 3 16 3 √ 3 16
Find the local extreme values of the given function:
Select one:
a. Local minimum: (1.73, -9)
Local maximum: (-1.73, -9)
b. Local minimum: (-1.73, -9)
Local maximum:(1.73, -9)
c. Local minimum: (1.73, 9)
Local maximum: (-1.73, 9)
d. Local minimum: (-1.73, 9)
Local maximum: (1.73, 9)
Clear my choice
f ( x ) = x^4 − 6 x^2
Identify the absolute extrema and relative extrama for the following function.
on [-2,2]
Select one:
a. The function has an absolute maximum of 8 at x = 2 and absolute minimum of -8 at x = -2. The function
has no relative extrema.
b. The function has an absolute maximum of -8 at x = 2 and absolute minimum of 8 at x = -2. The function
has no relative extrema.
c. The function has an absolute maximum of 8 at x = 0 and absolute minimum of -8 at x = -1. The function
has a no relative extrema.
d. The function has an absolute maximum of 8 at x = -2 and absolute minimum of -8 at x = 2. The function
has a relative minimum of (0,0) and no relative maxmum.
l h
f ( x ) = x^3
◄ Lesson 10: Applications of Derivatives 1 Jump to... Lesson 11: Applications of Derivatives 2 ►
