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Material Type: Assignment; Class: Chemistry 1 - Introduction; Subject: Chemistry; University: Albright College; Term: Forever 1989;
Typology: Assignments
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Chemistry 105A - Chapter 10 Problems - DUE IN CLASS 12/2/
Show your work and complete the following problems. Work independently but take advantage
of your notes and textbook as necessary just no other human help.
constant temperature. Determine the pressure after the compression.
1 1 2 2
1 1
2
2
P V^ 4.00 atm 8.00 L
P = = 16 atm
V 2.00 L
weighing 9.49 g occupies what volume at 353 K and 2.00 atm.
1 1 2 2
1 2
2 2
2 1
1 1
P nT
PV = nRT =
R V
n T n T
=
V V
1 mole
9.49 g × 353.0 K
n T^ 2 g
V = V = × 100.0 L
n T (^) 1 mole
12.28 g × 400.0 K
2 g
You would not have to convert to mo
L atm
K mole
les since this cancels in the numerator and denominator.
OR with the use of the ideal gas constant:
1 mole
9.49 g × 0.08206 353.0 K
nRT 2.016 g
V = = 68.2 L
P 2 atm
rapid inflation: 2NaN 3 (s) 2Na(s) + 3N 2 (g)
Answers Chapter 10 problems 1
What mass (g) of NaN 3 is required to provide 40.0 L of N 2 at 25C and 763 torr?
l atm^2
K mole
3
2 3
2
3 3
3
n =
RT
1 atm
763 torr 40.0 L)
760 torr = = 1.64 mole N
0.0821 298.15 K
2 mole NaN
1.64 mole N = 1.09 mole NaN
3 mole N
65 g
1.09 mole NaN 71.1 g NaN
1 mole NaN
If the partial pressure of Ne is 2.75 atm, how many moles of Ar are in the mixture?
t
Ne
Ne
Ne
t
Ar Ar
t
t Ne Ar Ar
Ar
Ar
Ar
t
P = 4.00 atm
P = 2.75 atm
0.3125 16 mole = 5 mole Ar
P = 4.00 atm = P + P 2.75 + P
P = 1.25 atm
P 1.25 atm
Χ = = 0.
P 4 atm
0.3125 16 mole =
5 mole Ar
Answers Chapter 10 problems 2