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BIOL 250 Final Exam Review: Questions and Answers on Key Biology Concepts, Exams of Biology

This biol 250 final exam review covers fundamental biology concepts, including contributions from Hooke, Leeuwenhoek, Linnaeus, Schleiden, Schwann, Pasteur, and Koch. Key concepts include cell theory, binomial nomenclature, and Koch's postulates. It also covers basic chemistry: atoms, molecules, compounds, chemical bonds, water properties, carbohydrates, lipids, proteins, and nucleic acids. Prokaryotic and eukaryotic cells, cell wall structures, metabolism, and enzyme function are also discussed. This review helps students prepare for their final exam by reinforcing core biological principles, providing a concise summary of essential topics.

Typology: Exams

2024/2025

Available from 05/28/2025

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BIOL 250 FINAL EXAM
Questions and Answers
Robert Hooke
Ans: developed the first microscope, used to look at plant cells, first to use
the term cells-- looked like what monks lived in
Anton Van Leeuwenhoek
Ans: father of microbiology
first to look at living material-- scraped his teeth and saw that sick people had
different microogranisms than his did
Carolus Linnaeus
Ans: binomial nomenclature
schleiden and schwann
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BIOL 250 FINAL EXAM

Questions and Answers

Robert Hooke Ans: developed the first microscope, used to look at plant cells, first to use the term cells-- looked like what monks lived in Anton Van Leeuwenhoek Ans: father of microbiology first to look at living material-- scraped his teeth and saw that sick people had different microogranisms than his did Carolus Linnaeus Ans: binomial nomenclature schleiden and schwann

Ans: formulated the cell theory-- cells are fundamental unit of life and carry out functions of all living things Louis Pasteur Ans: swan flask experiment-- if the flask was tipped then it would come in contact with particles and growth would occur immediately Koch's postulates Ans: When determining the causative agent of disease...

  1. specific causative agent must be fond in every case of the disease
  2. the disease organism must be isolated into pure culture
  3. inoculate a sample of the culture into a previously healthy individual-- must produce the same disease symptoms
  4. culture recovered from the inoculated animal must be the same as the original disease causing agent What did Koch identify the causative agents of Ans: cholera-- Vibrio cholerae

Ans: two or more atoms combied-- O compound Ans: multiple elements- C6H12O atomic weight Ans: sum of protons and neutrons atomic number Ans: sum of protons in the nucleus cations Ans: lose an electron when joined with another atom, become more positively charged anion Ans: gain an electron, become more negatively charged

isotopes Ans: atoms within elements that have different number on neutrons-- ex. carbon12,13, gram molecular weight Ans: adding based on atomic weights Avogadro's number Ans: 6.023x10^ ionic bond Ans: outermost electrons are transferred from one orbital to another covalent bond Ans: sharing on electrons between orbitals-- certain arrangements are favorable and can hold the structure of compounds together

  1. medium for most chemical reactions mixture Ans: two substances combined but not chemically bound-- sugar and salt solution Ans: two substances combined and not easily broken-- salt or sugar in water solute Ans: the substance that is dissolved-- the sugar solvent Ans: solutions in which substances are dissolved pH scales Ans: relates concentration to a numeric value

carbohydrates Ans: main source of energy for most living things levels of carbohydrates Ans: monosaccharides- glucose disaccharides- lactose polysaccharides- starch/glycogen common functional groups Ans: OH: hydroxyl groups CO: carbonyl groups COOH: carboxyl groups NH2: amino groups PO4: phosphate groups backbone of nucleic acid made up by which carbohydrates Ans: deoxyribose and ribose

Ans: sugar backbone, nitrogenous case high energy bonds--essential to enhance energy

  • purines and pyrimadines nucleotide make up Ans: 1. nitrogenous base --a. purine: double ring, larger, you want more gold "pure as gold" adenine and guanine b. pyrimidine: cytosine, thymine, ursine
  1. 5-carbon sugar of ribose/deoxyribose
  2. at least 2 phosphate DNA vs. RNA Ans: A, G, C present in both T in DNA, U in RNA DNA double stranded, RNA single stranded deoxyribose

characteristics of prokaryotes Ans: lack a nucleus lack membrane bound organelles-- endoplasmic reticulum, chloroplasts, golgi apparatus, mitochondria, etc. no membrane that surrounds and separate genetic info unicellular what are the two prokaryotic domains Ans: bacteria and archaea Eukaryotes Ans: have nucles and membrane bound organelles size shape and arrangement of eukaryotes Ans: small-- most around .5-2 mm can be cocci, bacilli, vibrioid (comma shaped) or spirrilium (squigly)

Ans: to evaluate differences in cell wall structure steps of gram staining Ans: thin smear on glass slide and heat fix it w/ flame to allow them to adhere to the slide

  1. crystal violent stain
  2. mordant: gram's iodine-- slide appear purpley golden
  3. alcohol-- decolorizing step, lipid layer is broken down
  4. counter stain w safranin-- allows to differentiate cell wall types acid fast bacteria Ans: do not have a classic gram positive or negative structure mycoplasmas Ans: lack cell walls

archae cell wall Ans: made up of pseudomurein-- made on sinsistent muramic acid, does not have alternating nags and nams cell membrane functions of archaea Ans: 1. regulate movement of materials in and out of cells

  1. can synthesize cell wall components
  2. assist w/ DNA replication
  3. captures ATP for energy
  4. serves as an anchor for flagella types of flagella Ans: monotrichous: 1 flagellum at one end amphitrichous: a flagellum at each end lophotrichous: many flagella at one end peritrichous: flagella over their entire surface atrichous: lack flagella

internal structure of prokaryotes Ans: cytoplasm, ribosomes, endospores cytoplasm Ans: makes up the aquatic environment of the cell, 4/5 water, 1/5 substance (salt, enzymes, proteins, lipids) ******ribosomes come back to this Ans: prok: 30s+50s=70s euk: 40s+60s=80s S stands for... Ans: svedburg units-- to describe molecular weight small subunit Ans: 16s rRNA+21 proteins= 1540 nt

large subunit Ans: 5s rRNA + 23s rRNA +31 proteins=120 nt endospores Ans: resting stage to enhance survival over significant time makeup of eukaryotic cells Ans: nucleus: rough er on outside, ribosomes making it rough smooth ER: inside-- lysosomes mitochondria: power house of cell, makes ATP chloroplast: photosynthesis endosymbiotic theory Ans: 1. strucutre of mitochondria and chloroplast are about the same size as prokaryote

  1. mitochondria and chloroplast have different DNA structures than their host

redox reaction Ans: 2H2+O2-->2H2O a reaction in which both reduction and oxidation take place denaturation of enzyme Ans: increase in temp-- enzymatic structure is denatured bc the temp is higher so enzyme can no longer work the same endoenzymes Ans: produced and maintained in cells exoenzymes Ans: made inside cell but live outside to do things coenzymes Ans: non-protein organic molecules that are synthesized from vitamins

feedback inhibition Ans: a kind of reversible noncompetitive inhibition that regulates the rate of many metabolic pathways non-competitive inhibitors Ans: attach to the enzyme at an allosteric site which distort the tertiary protein structure and alter the shape of the active site glycolysis Ans: an anaerobic metabolism four take homes of glycolysis Ans: 1. substrate level phosphorylation (ATP--glucose)

  1. breaking of 6-C glucose to 2x 3-C molecules
  2. transfer of 2e- to coenzyme NAD+
  3. capture of E in ATP