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Solving Systems of Equations: Gaussian Elimination and LU Decomposition, Schemes and Mind Maps of Calculus for Engineers

A comprehensive guide to solving systems of linear equations using two fundamental methods: gaussian elimination and lu decomposition. It demonstrates the step-by-step procedures for both methods, including the construction of upper and lower triangular matrices, and provides detailed examples to illustrate the application of these techniques. Particularly valuable for students studying linear algebra, as it offers a clear and practical approach to solving complex systems of equations.

Typology: Schemes and Mind Maps

2022/2023

Uploaded on 04/03/2025

emre-unal
emre-unal 🇹🇷

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Q1:
a)
Using augmented form
10 2 −1 25
−3 −6 2 −60
1 1 5 −20
Step 1:
Multiply the first row by -3/10 and substract from the second line,
Multiply the first row by 1/10 and substract from the third line,
10 2 −1 25
0 −5.4 1.7 −52.5
0 0.8 5.1 −22.5
Step 2:
Multiply the second row by 0.8/-5.4 and substract from the third line,
10 2 −1 25
0 −5.4 1.7 −52.5
0 0 5.352 −30.278
x3 = (-30.278/5.352) = -5.657
x2 = (-52.5-1.7*(-5.657))/(-5.4) = 7.941
x1 = (25-2*7.941-(-1)*(-5.657))/10 = 0.346
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a) Using augmented form ൥

Step 1: Multiply the first row by -3/10 and substract from the second line, Multiply the first row by 1/10 and substract from the third line, ൥

Step 2: Multiply the second row by 0.8/-5.4 and substract from the third line, ൥

x3 = (-30.278/5.352) = -5. x2 = (-52.5-1.7(-5.657))/(-5.4) = 7. x1 = (25-27.941-(-1)*(-5.657))/10 = 0.

b) [A] = ൥

൩ b = ൭

Construct the upper and lower triangular matrices. [U] = ൥

൩ [L] = ൥

[L] {d}={b} and [U] {x}={d} ൥

d1 = 25, d2 = -52.5, d=-30. {d} = ൭

[U] = ൥

x3 = -5.656, x2 = 7.942, x1 = 0. {x} = ൭

c) [L] [U] ቌ

(𝑎ି ଵ^ )ଵଵ

(𝑎ି ଵ^ )ଶଵ

(𝑎ି ଵ^ )ଷଵ

൱ [L]{d}={I 1 } = ൭

[L] [U] ቌ

(𝑎ି ଵ^ )ଵଶ

(𝑎ି ଵ^ )ଶଶ

(𝑎ି ଵ^ )ଷଶ

൱ [L]{d}={I 2 } = ൭

[L] [U] ቌ

(𝑎ି ଵ^ )ଵଷ

(𝑎ି ଵ^ )ଶଷ

(𝑎ି ଵ^ )ଷଷ

൱ [L]{d}={I 3 } = ൭

[U]{x}={d} ቌ

(𝑎ି ଵ^ )ଵଵ

(𝑎ି ଵ^ )ଶଵ

(𝑎ି ଵ^ )ଷଵ

[U]{x}={d} ቌ

(𝑎ି ଵ^ )ଵଶ

(𝑎ି ଵ^ )ଶଶ

(𝑎ି ଵ^ )ଷଶ

[U]{x}={d} ቌ

(𝑎ି ଵ^ )ଵଷ

(𝑎ି ଵ^ )ଶଷ

(𝑎ି ଵ^ )ଷଷ

[A]-1^ = ൥

a) Using augmented form ൥

Step 1: Multiply the first row by -3/10 and substract from the second line, Multiply the first row by 1/10 and substract from the third line, ൥

Step 2: Multiply the second row by 0.8/-5.4 and substract from the third line, ൥

x3 = (-43.75/26.666) = -1. x2 = (0-12.5(-1.640666))/(30) = 0. x1 = (50-15(-1.640666)-20*(0.6836108))/8 = 7. b) [A] = ൥

൩ b = ൭

൱ [U] = ൥

൩ [L] = ൥

[L] {d}={b} and [U] {x}={d} ൥

d1 = 50, d2 = 0, d=-43.75; {d} = ൭

[U] = ൥

x3 = -1.6406, x2= 0.6836, x1=7. {x} = ൭