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Vector calculus and parametrizations
Typology: Cheat Sheet
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Parametrize the Intersection Example
eq .1 y
2
− z
2
= x − 2 ∧ eq .2 y
2
2
y
2
2
2
y
2
9 − y
2
= x − 2
, then set y=t and solve for x
x = 2 t
2
, then find components to solve for intersection
x ( t )= 2 t
2
− 7 , y ( t )= t , z ( t )=
9 − t
2
Vector parametrization with sphere
r ⃗ ( t )=¿ 3 , 1 , − 4 >+ t ← 2 , − 2
( x − 1 )
2
+( y + 3 )
2
2
( 3 − 2 t )− 1
2
( 1 − 2 t ) + 3
( 2 − 2 t )
2
+( 4 − 2 t )
2
+(− 4 + 3 t
Parallel Vectors ⃗
λ
x
V x
λ
=¿ λ x
when A=(1,1) B=(3,4) P=(1,1) Q=(7,10)
PQ vectors
~ square root trick
2
3
2
( 27 s + 8 )
2
3
= 4 + 9 t
2
Volume of parallelopiped
V x
Points of intersection from graph
and equation in xy plane example
⃗ r ( t )=⟨ sin ( t ) , cos ( t ) , sin ( t ) cos ( 2 t )
x ( t )=sin ( t ) , y ( t )=cos ( t ) , z ( t )=si
0 =sin ( t )=¿ t = nπ ∧ 0 =cos ( 2 t )=
Simplify arc length
‖ r
'
( t )‖=
t
t
2
( 2 t + 1 )
2
t
2
2 t + 1
t
Simplifying during
arc length
‖
r
'
( t )‖=
( 2 t + 1 )
2
t
2
**Arc length parametrization always 0 to t
Example:
r
t
=⟨ cos
4 t
, sin
4 t
, 3 t ⟩
∫
0
t
2
2
2
dt =¿
∫
0
t
√
s = 5 t =¿ t =
s
and plug inverse
x = rcosθ = h + rcos
s
r
y = rsinθ = k + rsin
s
r
,
z = z
** if given speed,
A)
4 x
2
2
2
B)
Find components from
P=(3,2) and Q=(2,7)
e Vectors Equivalent ⃗
AB ∧
A=(1,1) B=(3,7) P=(4,-1) Q=(6,5)
⟨
⟩
**
Yes equivalent b/c same
Vector Parametrization Perpendicular to Plane Rules
Show two vectors define same line:
Parametrize the Intersection Example
eq .1 y
2
− z
2
= x − 2 ∧ eq .2 y
2
2
y
2
2
= 9 =¿ z =
9 − y
2
y
2
2
, then set
y=t and solve for x
Two Different Parametrizations Through Same
Line
Example: (no intersection)
r
1
r
2
x ( t )=¿ 1 =− 3 + 4 t =¿ t =
Time for meteor to hit ground in xy from
parametric:
r ⃗ ( t )=¿ 2 , 1 , 4 >+ t < 3 , 2 , − 1 >¿