Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Calculus Series Tests Cheat Sheet, Cheat Sheet of Calculus

Divergence or nth Term Test, Geometric Series Test, p - Series Test, Alternating Series Test, Integral Test, Ratio Test, Root Test, Direct Comparison Test, Limit Comparison Test, Telescoping Series Test

Typology: Cheat Sheet

2020/2021

Uploaded on 04/23/2021

humaira
humaira 🇨🇫

4.8

(126)

274 documents

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
1
Series: 𝑎𝑛
𝑛=1
None. This test cannot be used to
show convergence.
Condition(s) of Divergence:
lim
𝑛→∞ 𝑎𝑛 0
2
Series: 𝑎𝑟𝑛
𝑛=0
Condition of Convergence:
|𝑟|< 1
Sum: 𝐒 = lim
𝑛→∞ 𝑎(1−𝑟𝑛)
1−𝑟 = 𝑎
1−𝑟
Condition of Divergence:
|𝑟| 1
3
Series: 1
𝑛𝑝
𝑛=1
Condition of Convergence:
𝑝 > 1
Condition of Divergence:
𝑝 1
4
Series: (−1)𝑛+1 𝑎𝑛
𝑛=1
Condition of Convergence:
0 < 𝑎𝑛+1 𝑎𝑛
lim
𝑛→∞ 𝑎𝑛= 0
or if |𝑎𝑛|
𝑛=0 is convergent
Condition of Divergence:
None. This test cannot be used
to show divergence.
* Remainder: |𝑅𝑛| 𝑎𝑛+1
5
Series: 𝑎𝑛
𝑛=1
when 𝑎𝑛= 𝑓(𝑛) 0
and 𝑓(𝑛) is continuous, positive and
decreasing
Condition of Convergence:
𝑓(𝑥)𝑑𝑥
1 converges
Condition of Divergence:
𝑓(𝑥)𝑑𝑥
1 diverges
* Remainder: 0 < 𝑅𝑁𝑓(𝑥)𝑑𝑥
𝑁
6
Series: 𝑎𝑛
𝑛=1
Condition of Convergence:
lim
𝑛→∞ |𝑎𝑛+1
𝑎𝑛| < 1
Condition of Divergence:
lim
𝑛→∞ |𝑎𝑛+1
𝑎𝑛| > 1
* Test inconclusive if
lim
𝑛→∞ |𝑎𝑛+1
𝑎𝑛| = 1
7
Series: 𝑎𝑛
𝑛=1
Condition of Convergence:
lim
𝑛→∞ |𝑎𝑛|
𝑛< 1
Condition of Divergence:
lim
𝑛→∞ |𝑎𝑛|
𝑛> 1
* Test inconclusive if
lim
𝑛→∞ |𝑎𝑛|
𝑛= 1
8
(𝑎𝑛,𝑏𝑛> 0)
Series: 𝑎𝑛
𝑛=1
Condition of Convergence:
0 < 𝑎𝑛 𝑏𝑛
and 𝑏𝑛
𝑛=0 is absolutely
convergent
Condition of Divergence:
0 < 𝑏𝑛 𝑎𝑛
and 𝑏𝑛
𝑛=0 diverges
9
({𝑎𝑛},{𝑏𝑛} > 0)
Series: 𝑎𝑛
𝑛=1
Condition of Convergence:
lim
𝑛→∞ 𝑎𝑛
𝑏𝑛= 𝐿 > 0
and 𝑏𝑛
𝑛=0 converges
Condition of Divergence:
lim
𝑛→∞ 𝑎𝑛
𝑏𝑛= 𝐿 > 0
and 𝑏𝑛
𝑛=0 diverges
10
Series: (𝑎𝑛+1 𝑎𝑛)
𝑛=1
Condition of Convergence:
lim
𝑛→∞ 𝑎𝑛= 𝐿
Condition of Divergence: None
NOTE:
1) May need to reformat with partial
fraction expansion or log rules.
2) Expand first 5 terms. n=1,2,3,4,5.
3) Cancel duplicates.
4) Determine limit L by taking the
limit as 𝑛 .
5) Sum: 𝑆 = 𝑎1𝐿
NOTE: These tests prove
convergence and divergence, not
the actual limit 𝐿 or sum S.
Sequence: lim
𝑛→∞ 𝑎𝑛= 𝐿
(𝑎𝑛,𝑎𝑛+1, 𝑎𝑛+2,)
Series: 𝑎𝑛
𝑛=1 = 𝐒
(𝑎𝑛+𝑎𝑛+1 + 𝑎𝑛+2 +)
Condition(s) of Convergence:
Geometric Series Test p - Series Test
Alternating Series Test
Integral Test Ratio Test
Root Test
Direct Comparison Test Limit Comparison Test
Telescoping Series Test
Divergence or nth Term Test
cheat sheet
pf2

Partial preview of the text

Download Calculus Series Tests Cheat Sheet and more Cheat Sheet Calculus in PDF only on Docsity!

Series:

𝑛

𝑛= 1

None. This test cannot be used to

show convergence.

Condition(s) of Divergence:

lim

𝑛→∞

𝑛

Series:

∞ 𝑛

𝑛= 0

Condition of Convergence:

Sum: 𝐒 = lim

𝑛→∞

𝑎( 1 −𝑟

𝑛

)

1 −𝑟

𝑎

1 −𝑟

Condition of Divergence:

Series: ∑

1

𝑛

𝑝

𝑛= 1

Condition of Convergence:

Condition of Divergence:

Series:

𝑛+ 1

𝑛

𝑛= 1

Condition of Convergence:

𝑛+ 1

𝑛

lim

𝑛→∞

𝑛

or if ∑ |𝑎

𝑛

𝑛= 0

is convergent

Condition of Divergence:

None. This test cannot be used

to show divergence.

  • Remainder: |𝑅

𝑛

𝑛+ 1

Series:

𝑛

𝑛= 1

when 𝑎

𝑛

and 𝑓(𝑛) is continuous, positive and

decreasing

Condition of Convergence:

1

converges

Condition of Divergence:

1

diverges

  • Remainder: 0 < 𝑅

𝑁

𝑁

Series:

𝑛

𝑛= 1

Condition of Convergence:

lim

𝑛→∞

𝑛+ 1

𝑛

Condition of Divergence:

lim

𝑛→∞

𝑛+ 1

𝑛

  • Test inconclusive if

lim

𝑛→∞

𝑛+ 1

𝑛

Series: ∑ 𝑎

𝑛

𝑛= 1

Condition of Convergence:

lim

𝑛→∞

𝑛

𝑛

Condition of Divergence:

lim

𝑛→∞

𝑛

𝑛

  • Test inconclusive if

lim

𝑛→∞

𝑛

𝑛

𝑛

𝑛

Series:

𝑛

𝑛= 1

Condition of Convergence:

𝑛

𝑛

and ∑ 𝑏

𝑛

𝑛= 0

is absolutely

convergent

Condition of Divergence:

𝑛

𝑛

and ∑ 𝑏

𝑛

𝑛= 0

diverges

𝑛

𝑛

Series:

𝑛

𝑛= 1

Condition of Convergence:

lim

𝑛→∞

𝑛

𝑛

and ∑ 𝑏

𝑛

𝑛= 0

converges

Condition of Divergence:

lim

𝑛→∞

𝑛

𝑛

and ∑ 𝑏

𝑛

𝑛= 0

diverges

Series: ∑ (𝑎

𝑛+ 1

𝑛

𝑛= 1

Condition of Convergence:

lim

𝑛→∞

𝑛

Condition of Divergence: None

NOTE:

  1. May need to reformat with partial

fraction expansion or log rules.

  1. Expand first 5 terms. n=1,2,3,4,5.

  2. Cancel duplicates.

  3. Determine limit L by taking the

limit as 𝑛 → ∞.

5) Sum: 𝑆 = 𝑎

1

NOTE: These tests prove

convergence and divergence, not

the actual limit 𝐿 or sum S.

Sequence: lim

𝑛→∞

𝑛

𝑛

𝑛+ 1

𝑛+ 2

Series: ∑ 𝑎

𝑛

𝑛= 1

𝑛

𝑛+ 1

𝑛+ 2

Condition(s) of Convergence:

Geometric Series Test p - Series Test

Alternating Series Test Integral Test Ratio Test

Root Test Direct Comparison Test Limit Comparison Test

Telescoping Series Test

Divergence or n th Term Test

cheat sheet

Do

the individual No

terms approach 0?

Series Diverges by

the Divergence Test

Yes

Does

the series

alternate

signs?

No

Yes

factorials or

exponentials?

No

Yes

Is individual term

easy to integrate?

No

Yes

Do individual terms

involve fractions with

powers of n?

No

Yes

Use Comparison Test

or Limit Comp. Test

(Look at dominating

terms)

Choosing a Convergence Test for Infinite Series

Do individual

terms have

Use

Alternating

Series Test

Use

Ratio Test

Use

Integral Test