Docsity
Log inSign up
Docsity
Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity

Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan

Guidelines and tips
Guidelines and tips
Sell on Docsity
Sell on Docsity
Log inSign up

Prepare for your exams

Study with the several resources on Docsity

Find documents

Prepare for your exams with the study notes shared by other students like you on Docsity

Search Store documents

The best documents sold by students who completed their studies

Search through all study resources
Docsity AINEW

Summarize your documents, ask them questions, convert them into quizzes and concept maps

Explore questions

Clear up your doubts by reading the answers to questions asked by your fellow students

Earn points to download

Earn points by helping other students or get them with a premium plan

Share documents
download point icon20 Points

For each uploaded document

Answer questions
download point icon5 Points

For each given answer (max 1 per day)

All the ways to get free points
Get points immediately

Choose a premium plan with all the points you need

Study Opportunities

Choose your next study program

Get in touch with the best universities in the world. Search through thousands of universities and official partners

Community

Ask the community

Ask the community for help and clear up your study doubts

University Rankings

Discover the best universities in your country according to Docsity users

Free resources

Our save-the-student-ebooks!

Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors

From our blog

Exams and Study
Go to the blog

Calorimetry Worksheet 3 Questions with Solutions, Exercises of Chemistry

Evangelical SeminaryChemistry

Typology: Exercises

2020/2021
On special offer
30 Points
Discount

Limited-time offer

Uploaded on 04/20/2021

rothmans
rothmans 🇺🇸

4.7

(20)

252 documents

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Calorimetry Worksheet
W 337
Everett Community College Tutoring Center
Student Support Services Program
Cp (H2O) = 4.184 J / g0C
H = mCpT
1) A compound is burned in a bomb calorimeter that contains 3.00 L of water. If the
combustion of 0.285 moles of this compound causes the temperature of the water to
rise 36.00 C, what is the molar heat of combustion of the compound?
2) When 62.3g of a compound was burned in a bomb calorimeter that contained 0.500
L of water the temperature rise of the water in the calorimeter was 48.00 C. If the
heat of combustion of the compound is 1,160 kJ/mol, what is the molar mass of the
compound?
3) The molar heat of combustion of a compound is 1,350 kJ/mol. If 0.875 moles of this
compound was burned in a bomb calorimeter containing 1.70 L of water, what would
the increase in temperature be?
pf2
Discount

On special offer

Partial preview of the text

Download Calorimetry Worksheet 3 Questions with Solutions and more Exercises Chemistry in PDF only on Docsity!

Calorimetry Worksheet W 337

Everett Community College Tutoring Center Student Support Services Program

Cp (H 2 O) = 4.184 J / g^0 C

H = mCpT

  1. A compound is burned in a bomb calorimeter that contains 3.00 L of water. If the combustion of 0.285 moles of this compound causes the temperature of the water to rise 36.0^0 C, what is the molar heat of combustion of the compound?

  2. When 62.3g of a compound was burned in a bomb calorimeter that contained 0. L of water the temperature rise of the water in the calorimeter was 48.0^0 C. If the heat of combustion of the compound is 1,160 kJ/mol, what is the molar mass of the compound?

  3. The molar heat of combustion of a compound is 1,350 kJ/mol. If 0.875 moles of this compound was burned in a bomb calorimeter containing 1.70 L of water, what would the increase in temperature be?

  1. A compound is burned in a bomb calorimeter that contains 3.00 L of water. If the combustion of 0.285 moles of this compound causes the temperature of the water to rise 36.0^0 C, what is the molar heat of combustion of the compound? 3.00 L H 2 O = 3000mL H 2 O = 3.00 x 10^3 g H 2 O

H = (3.00 x 10^3 g H 2 O)(4.184 J/g^0 C)(36.0^0 C) = 452000 J H = 452 kJ We now have the heat generated by the combustion of the compound so to find the molar heat of combustion we need only divide this by the number of moles of compound burned.

452 kJ = 1590 kJ/mol 0.285 mol

  1. When 62.3 g of a compound was burned in a bomb calorimeter that contained 0. L of water the temperature rise of the water in the calorimeter was 48.0^0 C. If the heat of combustion of the compound is 1,160 kJ/mol, what is the molar mass of the compound? 0.500 L H 2 O = 500 mL H 2 O = 5.00 x 10^2 g H 2 O H = (5.00 x 10^2 g H 2 O)(4.184 J/g^0 C)(48.0^0 C) = 100000 J H = 100 kJ

Now that we have the heat generated by the combustion of the compound we divide it by the given molar heat of combustion to find the number of moles of the compound that was burned.

  1. kJ = 0.0862 mol 1160 kJ/mol Since we know that 62.3 g of the compound was combusted and that this is equal to the number of moles burned we can divide the mass by the moles to get the molar mass of the compound. 62.3 g = 723 g/mol 0.0862 mol
  1. The molar heat of combustion of a compound is 1,350 kJ/mol. If 0.875 moles of this compound was burned in a bomb calorimeter containing 1.70 L of water, what would the increase in temperature be?

We are given both the number of moles of compound and the molar heat of combustion so by multiplying them together we can find the heat generated. (0.875 mol)(1350 kJ/mol) = 1180 kJ = 118000 J Plug this value into our equation and then rearrange to find the change in the temperature.

118000 J = (1.70 x 10^3 g H 2 O)(4.184 J/g^0 C)( T) T = 118000 J = 16.6 0 C (1.70 x 10^3 g H 2 O)(4.184 J/g^0 C)