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Chapter 6 Conceptual Reivew | PHYS 1111 - Trig PHYS IA, Quizzes of Physics

Conceptual review questions from the book Class: PHYS 1111 - Trig PHYS IA; Subject: PHYS Physics; University: Georgia Southern University; Term: Fall 2010;

Typology: Quizzes

2009/2010

Uploaded on 11/01/2010

braves32
braves32 🇺🇸

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TERM 1
A ball whirls on a string attached to a rotating
peg in the center of a frictionless table.
Suddenly, the string breaks, releasing the
raial force on the ball. What will happen and
why?
DEFINITION 1
No net force now acts on the ball, so it obeys Newton's First
Law-- it moves straight at a constate velocity.
TERM 2
A small car with mass m and a large car with
mass 2m drive around a highway curve of
radius R with the same speed v. As they
travel around the curve their accelerations
are...
DEFINITION 2
A. Equal B. Aling the directios of motion C. in the ratio of 2 to
1 D. Zero Answer A) because acceleration depends only on
the spped and the radius. Both cars have the same speekd
and the same radius
TERM 3
A frictional force of Fs provides the centripetal
force as a car goes around an unbanked
curve of radius R at speed v. if the driver
speeds up on this curve until the speed of the
car is tripled to 3v, and if the car still follows
the curved path the frictional force must now
be...
DEFINITION 3
A. 3Fs B. (1/3)Fs C. 9Fs D.(1/9)Fs Answer C) because when
the speed increases by a factor of 3, the force needed
increases by a factor of 3^2=9.
TERM 4
A stone of mass m is attached to a strong
string and whirled in a vertical circle of radius
R. At the lowest point of the path the tension
in the string is six times the stone's weight.
The stone's speed at this point is given by...
DEFINITION 4
A. 5 sqrt(gR) B. sqrt(gR) C. sqrt(5gR) Answer C. BecauseThe
net upward force has magnitude 5mg and must equal the
mass m times the magnitude of the centripetal acceleration
v^2 / R Thus, 5mg =mv^2/ R and it folloes that v =
sqrt(5gR)
TERM 5
A satellite in a curcular orbit travels at constat
speed because
DEFINITION 5
A. The net force acting on it is zero B . The pull of gravity is balance
by the centrifugal force C. There is n o component of forcealong its
direction of motion Answer C. Bec ause the net force is NOT zero
and there is no such thing as a balanc e of centrifugal force. It has
no component along the direction of the satellite's motion; if it did,
the speed of the satellite would chan ge
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TERM 1 A ball whirls on a string attached to a rotating peg in the center of a frictionless table. Suddenly, the string breaks, releasing the raial force on the ball. What will happen and why? DEFINITION 1 No net force now acts on the ball, so it obeys Newton's First Law-- it moves straight at a constate velocity. TERM 2 A small car with mass m and a large car with mass 2m drive around a highway curve of radius R with the same speed v. As they travel around the curve their accelerations are... DEFINITION 2 A. Equal B. Aling the directios of motion C. in the ratio of 2 to 1 D. Zero Answer A) because acceleration depends only on the spped and the radius. Both cars have the same speekd and the same radius TERM 3 A frictional force of Fs provides the centripetal force as a car goes around an unbanked curve of radius R at speed v. if the driver speeds up on this curve until the speed of the car is tripled to 3v, and if the car still follows the curved path the frictional force must now be... DEFINITION 3 A. 3Fs B. (1/3)Fs C. 9Fs D.(1/9)Fs Answer C) because when the speed increases by a factor of 3, the force needed increases by a factor of 3^2=9. TERM 4 A stone of mass m is attached to a strong string and whirled in a vertical circle of radius R. At the lowest point of the path the tension in the string is six times the stone's weight. The stone's speed at this point is given by... DEFINITION 4 A. 5 sqrt(gR) B. sqrt(gR) C. sqrt(5gR) Answer C. BecauseThe net upward force has magnitude 5mg and must equal the mass m times the magnitude of the centripetal acceleration v^2 / R Thus, 5mg =mv^2/ R and it folloes that v = sqrt(5gR) TERM 5 A satellite in a curcular orbit travels at constat speed because DEFINITION 5 A. The net force acting on it is zero B. The pull of gravity is balance by the centrifugal force C. There is no component of forcealong its direction of motion Answer C. Because the net force is NOT zero and there is no such thing as a balance of centrifugal force. It has no component along the direction of the satellite's motion; if it did, the speed of the satellite would change