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The answer key for quiz 2 of chem 1020 summer 2007 course. It includes the answers for various questions related to electron configurations, lewis structures, and ion pair formulas for different compounds.
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Chem 1020 Summer 2007 Name: ___Answer key_______________________
Quiz 2 Form A
[Xe] 6s
2
4f
14
5d
10
6p
2
ion.
1s
2
2s
2
2p
6
3s
2
3p
6
4s
1
(Many of you just wrote neutral calcium’s configuration. The
Ca
ion has one fewer electron.)
Is this a stable ion? Why or why not?
NO! Stable ions have a noble gas electron configuration. We would never see a Ca
ion in a compound.
central atom! Make sure the correct total number of valence electrons is shown.)
Total # ve = 5 + 6 + 7 = 18 ve (all of which must be accounted for in the structure!)
Even with the hint in the question, many of you put oxygen as the central atom.
Remember, the central atom is the first element in the formula (but not hydrogen).
This is a neutral molecule, so all atoms will make their normal number of bonds.
The central N has 3 bonds, O has two and F has one. So, if we put it together and
complete the octets, this is the structure:
Name Type (I, II, or III) Ion pair Formula
calcium nitride I Ca
2+
/N
3 –
Ca 3
2
titanium (IV) sulfide II Ti
4+
/S
2 –
Ti 2 S 4 → TiS 2
Formula Type (I, II, or III) Ion pair Name
Cu 2 O II Cu
/O
2!
copper (I) oxide
N 2 Cl 4 III none dinitrogen tetrachloride
Name Type (I, II, or III) Ion pair Formula
aluminum oxide I Al
3+
/O
2 –
Al 2 O 3
chromium (VI) phosphide II Cr
6+
/P
3 –
Cr 3 P 6 → CrP 2
Formula Type (I, II, or III) Ion pair Name
4+
/ S
2! tungsten (IV) sulfide
2
4
III none diphosphorus tetroxide