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Chemical Equilibria: Calculating Constants & Missing Concentrations, Quizzes of Chemistry

A series of exercises on calculating equilibrium constants and missing concentrations for various chemical reactions. The exercises involve gaseous and aqueous reactions, and the given data includes partial pressures or concentrations of reactants and products. Students can practice their skills in applying the concepts of chemical equilibria and le chatelier's principle.

Typology: Quizzes

Pre 2010

Uploaded on 08/19/2009

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Chemical Equilibria Exercises Page 217
Calculate the equilibrium constants for the following equilibria.
1) N2(g) + 3H2(g) W 2NH3(g)
PN2 = 0.60 atm
PH2 = 0.42 atm
PNH3 = 0.11 atm
K = 0.27
2) 2SO2(g) + O2(g) W 2SO3(g)
PSO2= 0.344 atm
PO2= 0.172 atm
PSO3= 0.056 atm
K = 0.15
3) 2NH3(g) W N2(g) + 3H2(g)
PN2 = 0.60 atm
PH2 = 0.42 atm
PNH3 = 0.11 atm
K = 3.7
4) 2SO3(g) W 2SO2(g) + O2(g)
PSO2= 0.344 atm
PO2= 0.172 atm
PSO3= 0.056 atm
K = 6.5
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Calculate the equilibrium constants for the following equilibria.

1) N 2 (g) + 3H 2 (g) W 2NH 3 (g)

P N2 = 0.60 atm P H2 = 0.42 atm P NH3 = 0.11 atm

K = 0.

2) 2SO 2 (g) + O 2 (g) W 2SO 3 (g)

P SO2 = 0.344 atm P O2 = 0.172 atm P SO3 = 0.056 atm

K = 0.

3) 2NH 3 (g) W N 2 (g) + 3H 2 (g)

P N2 = 0.60 atm P H2 = 0.42 atm P NH3 = 0.11 atm

K = 3.

4) 2SO 3 (g) W 2SO 2 (g) + O 2 (g)

P SO2 = 0.344 atm P O2 = 0.172 atm P SO3 = 0.056 atm

K = 6.

5) CH 3 COOH(aq) + H 2 O W CH 3 COO

!

+ H 3 O

+ [CH 3 COOH] = 0.10 M [CH 3 COO!] = 0.10 M [H 3 O +] = 1.8 x 10!^5 M and water is the solvent

K = 1.8 x 10!^5

6) AgCl(s) W Ag

+

+ Cl

!

[Cl!]= 1.0 x 10!^3 M [Ag+]= 1.8 x 10!^7 M

K = 1.8 x 10!^10

7) [Cu(NH 3 ) 4 ]

2+

W Cu

2+

+ 4NH 3

[Cu2+]= 0.085 M [Cu(NH 3 ) 4 ] 2+] = 0.10 M [NH 3 ]= 1.0 x 10!^3 M

K = 8.5 x 10!^13

8) Fe 2 S 3 (s) W 2Fe

2+

+ 3S

2-

[Fe3+]= 1.2 x 10!^8 M [S^2 !]= 1.0 x 10!^26 M

K = 1.4 x 10!^94

13) H 2 SO 3 (aq) + H 2 O W HSO 3

!

+ H 3 O

+ [H 2 SO 3 ] = 0.10 M [H 3 O +] = [HSO3-^ ] K = 1.2 x 10!^2

[HSO 3 -^ ] = 3.5 x 10!^2

14) CH 3 COOH(aq) + H 2 O W CH 3 COO

!

+ H 3 O

+

[CH 3 COOH] = [CH 3 COO -^ ] K = 1.8 x 10-

[H 3 O +] = 1.8 x 10!^5

15) AgCl W Ag

+

+ Cl

! [Cl-^ ] = [Ag+] K = 1.8 x 10!^10

[Ag+] = 1.3 x 10!^5

  1. NH 3 (aq) + H 2 O W NH 4 +^ + OH! [NH 3 ] = [NH 4 +] K = 1.8 x 10!^5

[OH-^ ] = 1.8 x 10!^5

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