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The concept of colligative properties, focusing on how the presence of solutes affects the freezing and boiling points of solutions. Topics include particle arrangement during freezing and boiling, the effect of salt on the freezing and boiling points, and the relationship between concentration, dissociation, and colligative properties. The document also covers the van hoff factor and provides formulas for calculating freezing point depression and boiling point elevation.
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Mar 114:12 PM
Aim: To observe and explain the affect that a solute has on colligative properties (freezing and boiling points) Mar 114:18 PM
Mar 114:18 PM
Mar 114:18 PM
Which of these compounds would cause a greater change in the boiling point or freezing point of a substance, 1 M NaCl or 1 M C 6 H 12 O 6? Explain your answer in terms of particle quantities and concentrations. (Hint: Think about dissociation) The 1 M NaCl solution because it dissociates into ions and yields more particles in solution to cause more interference with the water boiling or freezing. Feb 2210:18 AM
The addition of any solute to a solution will increase the boiling point and decrease the freezing point. This is because the solute particles block the water molecules from escaping as a gas when boiling and from moving together to form a solid when freezing. As a result additional energy is required to boil (higher BP) and additional energy must be lost to freeze (lower FP).
Feb 2312:34 PM
The solutions freezing point is lowered to ‐12.72 °C. Feb 2312:34 PM
i = 3 (Ca+2^ + 2 Cl‐ ) m = molality= 0.89 m Kf=0.51°C/ m ∆T = i m Kb ∆T = (3)(0.89)(0.51)= 1.36°C The solutions boiling point is elevated 101.36 °C. m = moles of solute = 1.25 mol kg of solvent 1.4 kg