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COMPUTER NETWORKING NOTES AND MCQ, Exams of Computer Networks

COMPUTER NETWORK EXAM SUFFICIENT SYALLABUS

Typology: Exams

2019/2020

Uploaded on 11/18/2020

naveen-nahar
naveen-nahar 🇮🇳

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For More Questions Click Here
1. A translation is applied to an object by
a) Repositioning it along with straight line path
b) Repositioning it along with circular path
c) Only b
d) All of the mentioned
View Answer
Answer: a
Explanation: A translation is applied to an object by repositioning it along with straight line
path from one location to another.
2. We translate a two-dimensional point by adding
a) Translation distances
b) Translation difference
c) X and Y
d) Only a
View Answer
Answer: d
Explanation: We can translate 2D point by adding translation distances dx and dy.
3. The translation distances (dx, dy) is called as
a) Translation vector
b) Shift vector
c) Both a and b
d) Neither a nor b
View Answer
Answer: c
Explanation: The translation distances (dx, dy) from its original position is called as
translation vector or shift vector.
4. In 2D-translation, a point (x, y) can move to the new position (x’, y’) by using the equation
a) x’=x+dx and y’=y+dx
b) x’=x+dx and y’=y+dy
c) X’=x+dy and Y’=y+dx
d) X’=x-dx and y’=y-dy
View Answer
Answer: b
Explanation: By adding translation distance dx and dy to its originsl position (x, y) we can
obtain a new position (x’, y’).
5.The two-dimensional translation equation in the matrix form is
a) P’=P+T
b) P’=P-T
c) P’=P*T
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For More Questions Click Here

  1. A translation is applied to an object by a) Repositioning it along with straight line path b) Repositioning it along with circular path c) Only b d) All of the mentioned View Answer

Answer: a Explanation: A translation is applied to an object by repositioning it along with straight line path from one location to another.

  1. We translate a two-dimensional point by adding a) Translation distances b) Translation difference c) X and Y d) Only a View Answer

Answer: d Explanation: We can translate 2D point by adding translation distances dx and dy.

  1. The translation distances (dx, dy) is called as a) Translation vector b) Shift vector c) Both a and b d) Neither a nor b View Answer

Answer: c Explanation: The translation distances (dx, dy) from its original position is called as translation vector or shift vector.

  1. In 2D-translation, a point (x, y) can move to the new position (x’, y’) by using the equation a) x’=x+dx and y’=y+dx b) x’=x+dx and y’=y+dy c) X’=x+dy and Y’=y+dx d) X’=x-dx and y’=y-dy View Answer

Answer: b Explanation: By adding translation distance dx and dy to its originsl position (x, y) we can obtain a new position (x’, y’).

5.The two-dimensional translation equation in the matrix form is a) P’=P+T b) P’=P-T c) P’=P*T

d) P’=p View Answer

Answer: a Explanation: The 2D translation equation is P’=P+T.

  1. _________ is a rigid body transformation that moves objects without deformation. a) Rotation b) Scaling c) Translation d) All of the mentioned View Answer

Answer: c Explanation: Translation a rigid body transformation that moves objects without deformation.

  1. A straight line segment is translated by applying the transformation equation a) P’=P+T b) Dx and Dy c) P’=P+P d) Only c View Answer

Answer: a Explanation: A straight line segment is translated by applying the transformation equation P’=P+T to each of line endpoints.

  1. Polygons are translated by adding __________ to the coordinate position of each vertex and the current attribute setting. a) Straight line path b) Translation vector c) Differences d) Only b View Answer

Answer: d Explanation: None.

  1. To change the position of a circle or ellipse we translate a) Center coordinates b) Center coordinates and redraw the figure in new location c) Outline coordinates d) All of the mentioned View Answer

Answer: b Explanation: By translating the center coordinates and redraw the figure in new location we can change the position of a circle or ellipse.