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Calculating Surface Areas of Different Shapes: Prisms, Cylinders, and Cones, Slides of Analytical Geometry and Calculus

Formulas and examples for calculating the surface areas of various 3D shapes, including rectangular prisms, cylinders, and cones. It explains the concept of surface area as the total area of the outside of a shape and provides step-by-step instructions for calculating the surface areas of these shapes using their respective formulas. The document also discusses the importance of understanding units and offers examples for each shape.

What you will learn

  • How do you find the surface area of a cylinder, open or closed?
  • What is the formula for calculating the surface area of a cone, and how does it differ for an open or closed cone?
  • What is the formula for calculating the surface area of a rectangular prism?

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2021/2022

Uploaded on 09/12/2022

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CONNECT: Volume, Surface Area
2. SURFACE AREAS OF SOLIDS
If you need to know more about plane shapes, areas, perimeters, solids or
volumes of solids, please refer to CONNECT: Areas, Perimeters โ€“ 1. AREAS
OF PLANE SHAPES; CONNECT: Areas, Perimeters โ€“ 2. PERIMETERS OF
PLANE SHAPES and CONNECT: Volume, Surface Area โ€“ 1. VOLUMES OF
SOLIDS.
You may also need to review Pythagorasโ€™ Theorem โ€“ if so, please refer to
CONNECT: Pythagorasโ€™ Theorem
The surface area of a 3D shape is โ€œthe total area of the outsideโ€ of the shape
(De Klerk, 2007, p. 129). So, to work out the surface area of a prism, you
need to work out the area of each face and add these areas together. Before
we calculate the surface area of an example, have a think about the units we
will use to measure surface area.
Example: Calculate the surface area of this rectangular prism:
The faces are all rectangles and so each of their areas is A = l x w units2.
For each of the top and bottom faces, the area is 3cm x 4cm = 12cm2.
For each of the left and right faces, the area is 4cm x 12cm = 48cm2.
For each of the front and back faces, the area is 3cm x 12cm = 36cm2.
So the total surface area is 12 x 2 + 48 x 2 + 36 x 2 cm2
that is, 192cm2.
The units are square units because we are measuring area.
If we draw in the
edges that are
blocked from
sight by the
other faces, we
can see the
shapes of all the
faces:
pf3
pf4
pf5

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CONNECT: Volume, Surface Area

2. SURFACE AREAS OF SOLIDS

If you need to know more about plane shapes, areas, perimeters, solids or volumes of solids, please refer to CONNECT: Areas, Perimeters โ€“ 1. AREAS OF PLANE SHAPES; CONNECT: Areas, Perimeters โ€“ 2. PERIMETERS OF PLANE SHAPES and CONNECT: Volume, Surface Area โ€“ 1. VOLUMES OF SOLIDS.

You may also need to review Pythagorasโ€™ Theorem โ€“ if so, please refer to CONNECT: Pythagorasโ€™ Theorem

The surface area of a 3D shape is โ€œthe total area of the outsideโ€ of the shape (De Klerk, 2007, p. 129). So, to work out the surface area of a prism, you need to work out the area of each face and add these areas together. Before we calculate the surface area of an example, have a think about the units we will use to measure surface area.

Example: Calculate the surface area of this rectangular prism:

The faces are all rectangles and so each of their areas is A = l x w units^2.

For each of the top and bottom faces, the area is 3cm x 4cm = 12cm 2.

For each of the left and right faces, the area is 4cm x 12cm = 48cm 2.

For each of the front and back faces, the area is 3cm x 12cm = 36cm 2.

So the total surface area is 12 x 2 + 48 x 2 + 36 x 2 cm 2

that is, 192cm 2.

The units are square units because we are measuring area.

If we draw in the edges that are blocked from sight by the other faces, we can see the shapes of all the faces:

Surface area of a cylinder

Take an ordinary A4 sheet of paper. Now roll it into a cylinder so that the edges just meet. Do you realise that you have used a rectangle to make the curved surface of a cylinder? Place your cylinder so that it stands on its circular base. The length of the rectangle is now the circumference of the circle (base) and the width of the rectangle is now the height of the cylinder. (Or vice versa, depending on which way you rolled the cylinder, but that will not make any difference to our formula.)

So the area of the curved surface of the cylinder is

๐ด = 2๐œ‹๐‘Ÿ ร— โ„Ž units^2.

( 2 ๐œ‹๐‘Ÿ is the length of the circumference, which is the same as l , the length of

the rectangle.)

If the cylinder is open at both ends, the total surface area of the cylinder is just the area of the curved surface. If it is closed at one end, we need to add the area of that circle and if it is closed at both ends, we need to add the area of both circles. So, the total surface area of a cylinder could be any of the following:

๐ด = 2๐œ‹๐‘Ÿ ร— โ„Ž units^2 โ† open at both ends

OR ๐ด = 2๐œ‹๐‘Ÿ ร— โ„Ž + ๐œ‹๐‘Ÿ 2 units^2 โ† open at one end

OR ๐ด = 2๐œ‹๐‘Ÿ ร— โ„Ž + 2 ร— ๐œ‹๐‘Ÿ 2 units^2 โ† closed at both ends.

Example: Find the surface area of the closed cylinder over the page.

h

l

h

l

If we know the slant height of the cone, we can use the formula

๐ด = ๐œ‹๐‘Ÿ๐‘  units 2

to find the area of the curved surface. So for an open cone, this formula gives the total surface area of the cone.

But if we have a closed cone, we need to add the area of the circle as well.

So, the total surface area of a cone will be:

๐ด = ๐œ‹๐‘Ÿ๐‘  units 2 โ† open cone

๐ด = ๐œ‹๐‘Ÿ๐‘  + ๐œ‹๐‘Ÿ 2 units 2 โ† closed cone

Example: Find the surface area of the following closed cone:

Curved surface area = ๐œ‹๐‘Ÿ๐‘  cm 2

= ๐œ‹ x 5.1 x 8.1 cm 2

= 129.779 192 5โ€ฆ cm^2

Area of base = ๐œ‹๐‘Ÿ 2 cm 2

= ๐œ‹ x 5.1 2 cm 2

= 81.712 824 92โ€ฆ cm 2

So the total area = 129.779 192 5โ€ฆ + 81.712 824 92โ€ฆ cm 2

= 211.492 017 4โ€ฆ cm 2

Round this to approximately 211.5cm 2

r = 5.1cm

s = 8.1cm

But what if we have a cone and do not know s?

For example, find the total surface area of this closed cone:

We know the radius and the perpendicular height of the cone, but we need to know the slant height. You can see that the radius, vertical height and slant height form the sides of a right-angled triangle, where the slant height ( s ) is the hypotenuse.

By Pythagorasโ€™ Theorem, ๐‘  2 = ๐‘Ÿ 2 + โ„Ž 2

๐‘  2 = 3.2^2 + 4.1^2

To find s , take the square root of 27.05, so (^) โˆš27.05 = 5.200 961 45โ€ฆ

So, s is 5.200 961 45โ€ฆ mm. (To make the final answer as accurate as possible, donโ€™t round yet.)

Now, the curved surface area = ๐œ‹๐‘Ÿ๐‘  mm 2

= ๐œ‹ x 3.2 x 5.200 961 45โ€ฆ mm 2

= 52.285 767 3โ€ฆmm 2

and the area of the base = ๐œ‹๐‘Ÿ 2 mm 2

= ๐œ‹ ร— 3.2^2 mm 2

= 32.169 908 77โ€ฆmm 2

So the total surface area is 52.285 767 3โ€ฆ + 32.169 908 77โ€ฆmm 2

= 84.455 676 07โ€ฆmm 2

Only now do we round and so the area is approximately 84.5mm 2

r = 3.2mm

h = 4.1 mm s