Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Creating New Functions Out of Old Ones - Intermediate Algebra | MATH 1334, Exams of Algebra

Material Type: Exam; Class: Intermediate Algebra; Subject: MATH; University: University of Texas - Pan American; Term: Spring 2006;

Typology: Exams

Pre 2010

Uploaded on 08/16/2009

koofers-user-j5n
koofers-user-j5n 🇺🇸

10 documents

1 / 3

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Creating New Functions out of Old Ones
Written by Frances E.M. Alvarado
January 28, 2006
Okay now we are going to create new functions by combining two or more
functions that are known to us. Don’t panic most of this will look familiar to
you.
First we are going to find new functions by Adding, Subtracting, Multiplying,
and Dividing 2 functions.
Adding, Subtracting, Multiplying, and Dividing 2 or more Functions
The following example represents how a question may look on a test paper.
Example : Using
2x3xf
and
2xx3xg
2
and
12xxh
Find the following:
1.)
xgf
________________
2.)
xgf
________________
3.)
xgf
__________________
4.)
x
g
f
________________
5.)
xhgf
_____________
Now for how to work them out – basically this is another game of notation.
You need to understand what the problem is asking you to do. So we will first
work with a known value of x and then figure out what has truly been asked.
(well that’s what I am hoping for anyway)
SO let us begin with problem number 1 – the addition of two
functions.
2x3xf
and
Find
xgf
means to find
xgxf
which means what?????
Okay let’s go into an example with some values for x first. Let’s explore
1.)
3gf
3g3f
= ????
well remember what f(3) means??? It means go find the y value that works in
the f-function when x = 3
pf3

Partial preview of the text

Download Creating New Functions Out of Old Ones - Intermediate Algebra | MATH 1334 and more Exams Algebra in PDF only on Docsity!

Creating New Functions out of Old Ones

Written by Frances E.M. Alvarado

January 28, 2006

Okay now we are going to create new functions by combining two or more

functions that are known to us. Don’t panic most of this will look familiar to

you.

First we are going to find new functions by Adding, Subtracting, Multiplying,

and Dividing 2 functions.

Adding, Subtracting, Multiplying, and Dividing 2 or more Functions

The following example represents how a question may look on a test paper.

Example : Using

f  x  3 x 2 and g^ ^ x^3 x x^2

2

   and

h  x  x 2  1

Find the following:

1.) ^ f^ ^ g^ ^ x^ ________________

 f  g  x 

________________

3.) ^ f^ g^ ^ x^ __________________

4.) ^ ^  

x

g

f

________________

 f  gh  x 

_____________

Now for how to work them out – basically this is another game of notation.

You need to understand what the problem is asking you to do. So we will first

work with a known value of x and then figure out what has truly been asked.

(well that’s what I am hoping for anyway)

SO let us begin with problem number 1 – the addition of two

functions.

f  x  3 x (^2) and g x 3 x x 2

2   

Find ^ f^ ^ g^ ^ x^  means to find f^ ^ x^ ^ g^ x which means what?????

Okay let’s go into an example with some values for x first. Let’s explore

 f  g  3   f  3   g 3 

well remember what f(3) means??? It means go find the y value that works in

the f-function when x = 3

so f(3) = 3(3) + 2 = 11

Based on this g 3  3  3  3 2 22

2    

So then

 f  g  3  f  3   g 3 

Let’s try another value for x

 f  g   2   f   2  g  2 

well remember what f( - 2) means??? It means go find the y value that

works in the f-function when x = - 2

so f( - 2) = 3( - 2) + 2 = - 4

Based on this g^ ^2 ^3 ^2 ^ ^2 ^212

2       

So then ^ f^ ^ g^ ^ ^2 ^ f^ ^ ^2 ^ g^ ^2  = - 4 + 12 = 8

KEWL!! Having fun yet. Let’s try it without the value of x known to us.

3.) ^ f^ ^ g^ ^ x^  f^ ^ x^ ^ g^ x = ????

well remember what f( x ) means??? It means go find the y value that works

in the f-function when x = x (huh??? – well keep on going)

so f( x) = 3( x) + 2 = 3x + 2 ( okay guess that’s it)

Based on this g x 3 x x 2

2   

So then

 f  g  x  f  x  g x

= ^3 x^2 ^ ^3 x x^2 

2

Wait doesn’t this look familiar to something we learned in Math 1334.

The addition of two polynomials means combine like terms – so start

combining.

 f  g  x  f  x  g x =^  3 x 2   3 x x 2 

2    

3 x 2 x

2 

Using this new function found in question 3 recalculate

 f  g  3  

and

 f  g   2  

by plugging in the x value to the equation found in question

number 3. Compare you answers.

What you have just created is a new function which will enable you to find

new ordered pairs and given enough ordered pairs enable you to graph the

new function. This new function is based on you combining certain parts of

the old ordered pairs to create a new set of ordered pairs – study the

examples above and see if you can figure out what part of the 2 original

functions’ ordered pairs you combined and how to create the new function.

Be prepared to use the following example and tell me what the new

ordered pairs would be.