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How to find the sum of an arithmetic series using the formula sn = n(a1 + an), where sn is the sum of the first n terms, a1 is the first term, and an is the nth term. The document also provides an alternative formula and demonstrates how the two formulas can be derived.
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Arithmetic Sequence is a sequence in which every term after the first is obtained by adding a constant, called the common difference (d). To find the nth term of a an arithmetic sequence, we know an = a 1 + (n – 1)d The first term is a 1 , second term is a 1 + d, third term is a 1 + 2d, etc This leads up to finding the sum of the arithmetic series, Sn, by starting with the first term and successively adding the common difference. 1 st 2 nd 3 rd n th Sn = a 1 + (a 1 + d) + (a 1 + 2d) + … + [a 1 + (n–1)d] We could have also started with the n th term and successively subtracted the common difference, so Sn = an + (an – d) + (an– 2d) + … + [an – (n–1)d] You could find the sum of the arithmetic sequence either way. However, if you looked at that, you might see that if you added those two equations together, terms add out. Sn = a 1 + (a 1 + d) + (a 1 + 2d) + … + [a 1 + (n–1)d] Sn = an + (an – d) + (an – 2d) + … + [an – (n–1)d] 2Sn = (a 1 + an) + (a 1 + an) + (a 1 + an) + … + [a 1 + an] Notice all the d terms added out. So 2Sn = n (a 1 + an)
By substituting an = a 1 + ( n – 1)d into the last formula, we have Sn =
[ a 1 + a 1 + (n – 1)d] Simplifying Sn =
[ 2 a 1 + (n – 1)d] These two formulas allow us to find the sum of an arithmetic series quickly.