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If, say, 50% of hfg is added then only 50% of the water will be changed into steam and the steam will be referred to as 50% dry. This is known as the “dryness ...
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Figure 1 Temperature/Enthalpy
This handout assumes the student is familiar with Steam Tables and the terms found therein. If required, please review Steam Tables before continuing. The heavy solid line in the above chart represents the transformation of 1 kg of water at 0˚C and atmospheric pressure into steam, with the addition of heat. From 0˚C to 100˚C, energy is added to the water in the form of sensible heat. This causes an increase in temperature while its state remains the same. This energy is referred to in steam tables as “hf”. The change from 1 kg of water at 0˚C into 1 kg of water at 100˚C requires the addition of 419.04 kJ of energy. Therefore, at atmospheric pressure: hf = 419.04 kJ/kg The saturation temperature of water at atmospheric pressure is 100˚C. The addition of more heat will not cause a temperature change but will, instead, cause a change of state. In this case, evaporation into steam at 100˚C. The change from 1 kg of water at 100˚C into dry saturated steam at 100˚C requires the addition of 2257.0 kJ of energy. Therefore, at atmospheric pressure: hfg = 2257.0 kJ/kg. Referring to the diagram, you will notice that hg = hf + hfg If not all of hfg is added to the water, then not all of the water can change into steam. If, say, 50% of hfg is added then only 50% of the water will be changed into steam and the steam will be referred to as 50% dry. This is known as the “dryness fraction” of the steam. Expanding on this, then, it can be seen that the total enthalpy content of steam of a certain dryness fraction, and made from water at 0˚C, can be found out by totalling hf and that portion of hfg which has been added (hfg multiplied by the dryness fraction). If the steam is 100% dry, then the entire amount of hfg has been added and the dryness fraction of the steam would be 100% or 1. Putting this into a formula we get: total enthalpy = hf + (dryness fraction) x (hfg) Using this formula and the information found in Steam Tables, one can determine the dryness fraction of steam at any pressure or temperature.
Example 1: One kilogram of steam at 1400 kPa has a total enthalpy content of 2202.09 kJ. Determine the dryness frac- tion of the steam. From the Steam Tables: hf = 830.30 kJ/kg hfg = 1959.7 kJ/kg h (^) g = 2790.0 kJ/kg Since it is given that the enthalpy of the steam is less than that of dry saturated steam at 1400 kPa (hg), one knows that the steam is “wet”. htotal = hf + (dryness fraction) x (hfg) _______htotal^ - hf (hfg) = (dryness fraction)
Then, substituting in the values, 2202.09 = 830.30 + (df)(1959.7) 2202.09 - 830.30/1959.7 = df df = 0. Therefore the dryness fraction of the steam is 0.7 or 70%
Example 2: Consider 5 kg of steam at 2000 kPa with a total enthalpy of 12571 kJ. What is the dryness fraction? First, the Steam Tables give figures that are “per kilogram”. So we have to determine the total enthalpy of 1 kg of the steam. 12571 ÷ 5 = 2514.2kJ/kg From the Steam Tables Steam at 2000 kPa: hf = 908.79 kJ/kg hfg = 1890.7 kJ/kg h (^) g = 2799.5 kJ/kg Comparing the actual total enthalpy of the steam and hg for steam at 2000 kPa, we know the steam is wet. Using the formula, substitute the values in and solve for the dryness fraction. htotal = hf + (dryness fraction) x (hfg) h_______total - hf (hfg ) = (dryness fraction)
Then, substituting in the values,
2514.2 = 908.79 + (df)(1890.7) _______________(2514.2 - 908.79) 1890.7 = df df = 0. Therefore the dryness fraction is 0.849 or 84.9%