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Various types of limits in calculus, including one-sided limits, infinite limits, and limits at infinity. It covers examples and methods for calculating limits at infinity and infinite limits. Understand the concepts of left-hand and right-hand limits, and learn about horizontal and vertical asymptotes.
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Besides ordinary, two-sided limits, there are one-sided limits (left- hand limits and right-hand limits), infinite limits and limits at infinity.
Consider limx→ 5
x^2 − 4 x − 5.
One might think that since x^2 − 4 x − 5 → 0 as x → 5, it would follow that limx→ 5
x^2 − 4 x − 5 = 0.
But since x^2 − 4 x − 5 = (x − 5)(x + 1) < 0 when x is close to 5 but smaller than 5,
x^2 − 4 x − 5 is undefined for some values of x very close to 5 and the limit as x → 5 doesn’t exist.
But we would still like a way of saying
x^2 − 4 x − 5 is close to 0 when x is close to 5 and x > 5, so we say the Right-Hand Limit exists, write limx→ 5 +
x^2 − 4 x − 5 = 0 and say
x^2 − 4 x − 5 approaches 0 as x approaches 5 from the right.
Sometimes we have a Left-Hand Limit but not a Right-Hand Limit. Sometimes we have both Left-Hand and Right-Hand Limits and they’re not the same. Sometimes we have both Left-Hand and Right-Hand Limits and they’re equal, in which case the ordinary limit exists and is the same.
f (x) =
x^2 if x < 1 x^3 if 1 < x < 2 x^2 if x > 2. limx→ 1 − f (x) = limx→ 1 + f (x) = 1, so the left and right hand limits are equal and limx→ 1 f (x)1.
limx→ 2 −^ f (x) = 8 while limx→ 2 +^ f (x) = 4, so the left and right hand limits are different and limx→ 2 f (x) doesn’t exist.
Suppose we’re interested in estimating about how big
2 x x + 1
is when
x is very big. It’s easy to see that
2 x x + 1
2 x x(1 + (^1) x )
1 + (^) x^1
if x 6 = − 1
and thus
2 x x + 1
will be very close to 2 if x is very big. We write
limx→∞
2 x x + 1
and say the limit of
2 x x + 1
is 2 as x approaches ∞. 1
2
Similarly,
2 x x + 1
will be very close to 2 if x is very small and we write
limx→−∞
2 x x + 1
and say the limit of
2 x x + 1
is 2 as x approaches −∞. Here, small does
not mean close to 0, but it means that x is a negative number with a large magnitude (absolute value).
A convenient way to find a limit of a quotient at infinity (or minus infinity) is to factor out the largest term in the numerator and the largest term in the denominator and cancel what one can.
limx→∞
5 x^2 − 3 8 x^2 − 2 x + 1
= limx→∞
x^2 (5 − (^) x^32 ) x^2 (8 − (^2) x + (^) x^12 )
limx→∞
5 − (^) x^32 8 − (^2) x + (^) x^12
limx→∞
5 x − 3 8 x^2 − 2 x + 1
= limx→∞
x(5 − (^3) x ) x^2 (8 − (^2) x + (^) x^12 )
limx→∞
5 − (^3) x x(8 − (^2) x + (^) x^12 )
If x is close to 1, it’s obvious that
(x − 1)^2
is very big. We write
limx→ 1
(x − 1)^2
and say the limit of
(x − 1)^2
is ∞ as x approaches 1.
Similarly, limx→ 1 −
(x − 1)^2
Technically, a function with an infinite limit doesn’t actually have a limit. Saying a function has an infinite limit is a way of saying it doesn’t have a limit in a very specific way.