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Derivative of Logarithmic Functions: Proof and Examples, Lecture notes of Algebra

An explanation of how to find the derivative of logarithmic functions using the exponential form and the logarithm derivative rule. It includes examples and solutions for various logarithmic functions.

Typology: Lecture notes

2021/2022

Uploaded on 09/12/2022

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Differentiation of Logarithmic Functions
The rule for finding the derivative of a logarithmic function is given as:
If loga
y
x= then
()
1
ln
dy or y
dx a x
=.
This rule can be proven by rewriting the logarithmic function in exponential form and then using
the exponential derivative rule covered in the last section.
loga
y
x= Begin with logarithmic function
Convert into exponential form
y
ax=
Differentiate both sides of the equation
()
ln 1
y
aa y
⋅⋅=
Substitute x for the exponential function ay
()
ln 1axy
⋅⋅ =
()
1
ln
yax
= Solve for y´ by dividing each side by “(ln a)x”
As with the exponential rules, the derivative of a logarithmic function can be simplified if the
base of the logarithm is “e”.
log ln
e
y
xx== Logarithmic function with base “e”
()
1
ln
yex
= Apply the logarithm derivative rule above
()
1
1
y
x
= Use properties of logarithms to simplify
1
y
x
=
Gerald Manahan
SLAC, San Antonio College, 2008
1
pf3
pf4
pf5

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Differentiation of Logarithmic Functions

The rule for finding the derivative of a logarithmic function is given as:

If log a

y = x then

ln

dy

or y

dx a x

This rule can be proven by rewriting the logarithmic function in exponential form and then using

the exponential derivative rule covered in the last section.

log a

y = x Begin with logarithmic function

Convert into exponential form

y a = x

( ln ) 1 Differentiate both sides of the equation

y aay ′=

Substitute x for the exponential function a

y

( ln^ a^ )⋅^ x^ ⋅^ y ′=^1

ln

y

a x

′ = Solve for y´ by dividing each side by “(ln a)x”

As with the exponential rules, the derivative of a logarithmic function can be simplified if the

base of the logarithm is “e”.

log ln e

y = x = x Logarithmic function with base “e”

ln

y

e x

′ = Apply the logarithm derivative rule above

y

x

′ = Use properties of logarithms to simplify

y

x

Example 1: Find the derivative of ( )

6

f x =log x

Solution:

6

log

ln 6

f x x

f x

x

Example 2: Find the derivative of ( )

2 f x =log 4 x

Solution:

Right now the only derivative rule we have for logarithms is for “log x”. So in

order to take the derivative of this function we must first use the properties of

logarithms to rewrite the function.

First use the product property of log ( xy )= log x + log y

2

2

log 4

log 4 log

f x x

x

Next use the exponent property of

( ) (^ )

log log

r x = rx

2 log 4 log

log 4 2 log

f x x

x

Now we can find the derivative.

log 4 2 log

ln

ln

f x x

f x

x

x

Even though we were able to find the derivative of this function, it would be easier to find the

derivative if we had a rule that dealt with the situation where a function is equal to the log of

another function. In order to do this, we would have to combine the chain rule with the

logarithm rule.

Example 3: Find the derivative of ( )

2 f x =log 4 x

Solution:

Note: Remember if a base is not shown it is understood to be 10.

2

2

2

2

log 4

ln10 4

ln10 4

ln

ln

x

f x x

D x

f x

x

x

x

x

x

As you can see we get the same derivative as before but in an shorter and easier

process.

Example 4: Find the derivative of

3 4 4 y = ln t + 5 t

Solution:

In this problem we can simplify the derivative process by first applying the

properties of logarithms to move the exponent out in front of the function as a

coefficient.

3 4 4

4

ln 5

ln 5

y t t

t t

Now we can find the derivative

4

ln 5

y = t + t

4

ln 5

x

y D t t

′ = ⎡^ ⎤

Example 4 (Continued):

4

4

x

D t t

y

t t

3

4

t

y

t t

Now lets look at a more complex function that will require the use of several derivative rules.

Remember when finding the derivative of a complex function take it step by step. Don’t try to

do it all at once.

Example 5: Find the derivative of

2 2 1

ln 5 3

x x e

y

x

Solution:

Since the function is in the form of a fraction we must begin by applying the

quotient rule. When you go to find the derivative of the numerator you are will

have to use both the product and exponential rules. The derivative of the

denominator will require the use of the logarithm rule.

First, apply the quotient rule.

2 2

2 2 2 2

2

ln 5 3

ln 5 3 1 1 ln 5 3

ln 5 3

x

x x

x x

x e

y

x

x D x e x e D x

y

x

Example 5 (Continued):

( ) (^ )^ ( )

( )(^ )^ (^ )^ ( )

2 2 2 2 2

2

2 2 2 2

2

2 2 2 2

2

2 2 2

2

ln 5 3 1 2 2 1

ln 5 3

2 1 ln 5 3 1

ln 5 3

2 1 5 3 ln 5 3 1 5

5 3 ln 5 3

2 1 5 3 ln 5 3 5 1

5 3 ln 5 3

x x x

x x

x x

x

x x e xe x e

x

y

x

e x x x x e

x

x

e x x x x x e

x x

e x x x x x

x x

+ ⋅ ⎡^ + + ⎤− + ⋅