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Elastic and Inelastic Collisions, Study notes of Physics

In an ELASTIC collision, energy is conserved (KEbefore = KEafter or Ki = Kf). In an INELASTIC collision, energy is NOT conserved. (Ki > Kf). Example: A 1 kg ...

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D7
Elastic and Inelastic Collisions
In an ELASTIC collision, energy is conserved (KEbefore = KEafter or Ki = Kf).
In an INELASTIC collision, energy is NOT conserved. (Ki > Kf).
Example: A 1 kg block which is sliding at 10 m/s across a frictionless surface suddenly collides with a
stationary 2 kg block. They stick together and they move towards an inclined plane of angle
37o. How far up the incline will they move? Was the collision elastic or inelastic?
Example: A 10 kg pendulum bob is hanging at rest at the end of a 4 meter long rope. A 500 gram ball is
thrown horizontally at the pendulum bob with a speed of 5.0000 m/s. It strikes the pendulum
bob, and them bounces straight backward at a speed of 4.5238 m/s. What angle will the
pendulum bob swing through? Was the collision elastic or inelastic?
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D

Elastic and Inelastic Collisions

In an ELASTIC collision, energy is conserved (KEbefore = KEafter or Ki = Kf).

In an INELASTIC collision, energy is NOT conserved. (Ki > Kf).

Example: A 1 kg block which is sliding at 10 m/s across a frictionless surface suddenly collides with a stationary 2 kg block. They stick together and they move towards an inclined plane of angle 37 o. How far up the incline will they move? Was the collision elastic or inelastic?

Example: A 10 kg pendulum bob is hanging at rest at the end of a 4 meter long rope. A 500 gram ball is thrown horizontally at the pendulum bob with a speed of 5.0000 m/s. It strikes the pendulum bob, and them bounces straight backward at a speed of 4.5238 m/s. What angle will the pendulum bob swing through? Was the collision elastic or inelastic?

For ELASTIC, HEAD-ON, 1D Collisions

Conservation of Momentum:

m 1 v 1 i  m 2 v 2 i  m 1 v 1 f  m 2 v 2 f

If we know all but one velocity (or mass), we can find the missing velocity (or mass) .

Conservation of Energy:



1 2

m 1 v 1 i 2 

1 2

m 2 v 2 i 2 

1 2

m 1 v 1 f 2 

1 2

m 2 v 2 f 2

Put the two equations together (carefully and with many steps ) and you get the following equations.



v 1 f

m 1  m 2 m 1  m 2











 v 1 i ^

2 m 2 m 1  m 2











 v 2 i



v 2 f

2 m 1 m 1  m 2











 v 1 i ^

m 1  m 2 m 1  m 2











 v 2 i

With these equations, we can find BOTH velocities of the balls after the collision by just

using the initial velocity of the balls and the masses of the balls!     

Special Case: If v2i = 0, then what happens when …..

a) m 1 (^)  m 2 ___________________________________________________

b) m 1 (^)  m 2 ___________________________________________________

c) m 1 (^)  m 2 ___________________________________________________

d) m 1 (^)  m 2 ___________________________________________________

e) m 1 (^)  m 2 ___________________________________________________

BEFORE

v 1 i v 1 f

m 1 m 2 m 1 m 2

v2i

v2f

AFTER