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lecture notes and guides for engineering subjects
Typology: Lecture notes
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It states that the force F between two point charges Q 1 and Q 2 is
In Vector form
Or
If we have more than two point charges
If there is a continuous charge distribution say along a line, on a surface, or in a volume
The charge element dQ and the total charge Q due to these charge distributions can be obtained by
The electric field intensity due to each charge distribution ρL, ρS and
ρV may be given by the summation of the field contributed by the
numerous point charges making up the charge distribution.
For an infinite sheet the electric flux density D is given by
For a volume charge distribution the electric flux density D is given by
In both the above equations D is a function of charge and position only (independent of medium)
It states that the total electric flux ψ through any closed surface is equal to the total charge enclosed by that surface.
(i)
Electric Field intensity, E due to a charge distribution can be obtained from Coulomb’s Law. or using Gauss Law when the charge distribution is symmetric. We can obtain E without involving vectors by using the electric scalar potential V. From Coulomb’s Law the force on point charge Q is
The work done in displacing the charge by length dl is
The negative sign indicates that the work is being done by an external agent.
The total work done or the potential energy required in moving the point charge Q from A to B is
B
A
.
Dividing the above equation by Q gives the potential energy per unit charge.
A
. VAB
For n point charges Q 1 , Q 2 , Q 3 …..Qn located at points with position
vectors the potential at is
If there is continuous charge distribution instead of point charges then
the potential at becomes
r (^) 1 , r 2 , r 3 ..... r n r
n
k (^) k
k
r
The potential difference between points A and B is independent of the path taken
B
A
AB .
A
B
BA .
V (^) AB VBA E. dl 0
E. d^ l ^0
It means that the line integral of E along a closed path must be zero.
(i)
Also
It means Electric Field Intensity is the gradient of V.
The negative sign shows that the direction of is opposite to the direction in which V increases.
Consider an atom of the dielectric consisting of an electron cloud (-Q) and a positive nucleus (+Q).
When an electric field is applied, the positive charge is displaced
from its equilibrium position in the direction of by while
the negative charge is displaced by in the opposite
direction.
A dipole results from the displacement of charges and the dielectric is polarized. In polarized the electron cloud is distorted by the applied electric field.
The major effect of the electric field on the dielectric is the creation of dipole moments that align themselves in the direction of electric field.
This type of dielectrics are said to be non-polar. eg: H 2 , N 2 , O 2
Other types of molecules that have in-built permanent dipole moments are called polar. eg: H 2 O, HCl
When electric field is applied to a polar material then its permanent dipole experiences a torque that tends to align its dipole moment in the direction of the electric field.
Consider a dielectric material consisting of dipoles with Dipole moment per unit volume.
The potential dV at an external point O due to
where R^2 = (x-x’)^2 +(y-y’)^2 +(z-z’)^2 and R is the distance between volume element dv’ and the point O.
But
Applying the vector identity
= -
(i)