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Soil physics is the study of soil physical properties and processes. It is applied to management and prediction under natural and managed ecosystems. (Wikipedia). Keywords in this solved assignment are: Elevation, Pressure, Total Potential, Potential Difference, Daily Outflow, Density, Water, Components, Iron, Buoyance
Typology: Exercises
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Using this figure, give the elevation, pressure, and total potential at the labeled points A, B, C , and D. Assume that the outflow, at point “ D ”, has an elevation of 0 cm.
Using this figure, give the elevation, pressure, and total potential at the labeled points A, B, C , and D. Assume that the outflow, at point “ D ”, has an elevation of 0 cm.
The potential difference through the soil is 30 cm, but the distance through the soil is only 25 cm. The gradient is therefore 6/5. So 60% of the way up into the soil, the total potential must be 60% of 30, which is
15 cm soil
5 cm water
10 cm soil
15 cm soil
5 cm water
10 cm soil
25 cm soil
5 cm water A
B (^) C D
10 cm big pipe
10 cm big pipe 25 cm soil
5 cm water A
B (^) C D
10 cm big pipe
10 cm big pipe
A: Change in head (height + pressure) is 4 m; distance through soil is 7 m; so gradient = 4/7.
0.05 m/hr * 24 hr * 1 m^2 * (4/7) = 0.686 m^3
B: Change in head is m 4, distance through soil is 5 m, so gradient = 4/5.
0.07 m/hr * 24 hr * 1 m^2 * (4/5) = 1.344 m^3
(a) If the chunk is solid (has no bubbles) and I put it into a beaker that is full of water, how much water will spill out of the beaker?
A 1.1 kg chunk of pure iron has a volume (1.1 kg / 5.5 kg/L) = 0.2 L. So if it were placed in a beaker full of water, 0.2 L would spill out.
(b) I weigh the chunk suspended from my balance and submerged in a beaker of water (see diagram), and the balance reads a mass of 0. kg. Assuming that the only components are iron and (possibly) gas bubbles, what is its porosity?
If the chunk had no bubbles, then it would displace 0.2 L of water, so its mass in water would be reduced by 0.2 kg due to buoyancy. 1.1 kg – 0.2 kg = 0.9 kg, so the balance would read 0.9 kg if there were no bubbles.
Instead, the balance read 0.8 kg, so buoyancy decreased its apparent mass 1.5 times as much as expected (by 0.3 kg, rather than 0.2 kg). Therefore its volume is 1.5 times what it would be if it were pure iron. That extra
1 m water
3 m soil A
4 m soil A
5 m soil B
1 m water
3 m soil A
4 m soil A
5 m soil B