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Hardy-Weinberg equilibrium requires a) large isolated populations, c) genes that do not mutate, and no natural selection, which acts on the d) different phenotypes in a population (answers a, c, and d are requirements and therefore are not correct answers). Neither normal meiotic recombination nor b) the process of random fertilization changes allele frequencies, but they are not requirements for equilibrium as stated by Hardy and Weinbe
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These equations may be useful as a study guide. YOU ARE EXPECTED TO KNOW HOW TO USE THESE EQUATIONS AND UNDERSTAND THE MEANING OF ALL OF THE VARIABLES. There are a few simple equations presented in class that are not on this sheet (for example, how to calculate gene and allele frequencies-You will have to know these). HWE: Components of Variance p^2 +2pq+q^2 =1 VP=VG+VE VG=VA+VD Heritability: Measuring selection: Broad-sense: VG/VP S=t ¿ −¯t Narrow-sense: h^2 = VA/VP R = h^2 S Chi-square test:
(observed −exp ected )^2 exp ected Change in gene frequency from Stable equilibria with heterozygote advantage mutation alone: Dp=±mp Mutation-selection balance (recessive mut.):
^q= s s+ t Selection for dominant allele: ∆ p= p q 2 s 1 −q 2 s