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by changing speed and wavelength of the wave, light can transmit across the boundary
Typology: Lab Reports
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The transmission of light across a boundary between two media is accompanied by a change in both the speed and wavelength of the wave. This can result in a change of direction at the boundary, a phenomenon known as refraction. In this experiment you measure the change in direction of light beams as they refract or reflect at a boundary to determine the index of refraction of a transparent object. The objectives of this experiment are as follows:
The index of refraction is a property of transparent substances that has been independently discovered several times, but is attributed to Willebrord Snellius whose name is associated with the law (you can't make this stuff up). Mathematically, Snell's law describes the relationship between the angle of incidence of a beam of light as it intersects a new transparent medium and the angle of refraction as enters that transparent medium.
Figure 6.1: Refraction overview Snell's law quantifies the relationship that is observed in Figure 6.1:
n 1 ∙ sin θ 1 = n 2 ∙ sin θ 2
where n 1 is the index of refraction of medium 1, n 2 is the index of refraction medium 2, θ 1 is the angle that the light ray makes with respect to the normal in medium 1, θ 2 is the angle that the light ray makes with respect to the normal in medium 2.
The index of refraction of any medium (ni) is the ratio of the speed of light in vacuum (c) to the speed of light in that medium (vi), as shown in equation 6.2.
𝑛𝑖 =
𝑐 𝑣𝑖 where c = 3.00×10^8 m/s (the accepted value for the speed of light in vacuum, a constant). A very good approximation for the refractive index of air is 1.00, i.e. nair=1.00.
On observation, it can easily be seen that as light travels from a lighter medium to a denser one (i.e. n 1 <n 2 ), the refracted light ray bends towards the normal. Conversely, when light travels from a denser medium to a lighter one (i.e. n 1 >n 2 ), the refracted light ray bends away from the normal. But
θ 1
θ 2
medium 1 refractive index n 1
medium 2 refractive index n 2
normal
incident ray
refracted ray
(6.1)
(6. 2 )
refracted ray internally reflected ray
incident ray
The critical angle, θc
normal
medium 1, n 1 > n 2 , medium 2
when you think about it, how much “away from the normal” is possible? One can only get as far as 90° without leaving the medium! When the refracted ray exceeds 90°, it’s not refraction anymore, instead light is reflected back into the same medium it started from, and this phenomenon is known as total internal reflection. Note that this only happens for light traveling from a denser medium to a lighter one (see figure 6.2 below).
Figure 6.2: Total internal reflection
The glass used in this experiment is made of Lucite. The accepted value for the refractive index of Lucite is 1.50. The mystery media have no accepted value for their refractive indices. It is up to the experimenter to determine their values!
Medium Measurement Magnitude^ (°)^ Refractive index
Air Angle of incidence (40°< θi < 60°) na= Glass Angle of refraction
Air Angle of incidence (60°< θi < 90°) nb= Glass Angle of refraction
Glass Critical Angle (θc) (^) nc=
Air Angle of incidence (θi) nA= Mystery Medium A Angle of refraction
Air Angle of incidence (θi) nB= Mystery Medium B Angle of refraction
The critical angle (θc) is the angle of incidence for which the angle of refraction is 90°. Beyond the critical angle, 100% of the incident light is reflected back into the same medium.
Click and drag out the protractor from the side panel on the bottom left corner of your screen.
Make sure the “Normal” is checked. The normal line is a line that is perpendicular to the surface where light is entering from one medium to another.
All angles are measured from the normal line.
The angle of incidence (θi or θ 1 ) is the angle of the incoming ray.
The angle of refraction (θr or θ 2 ) is the angle of the refracted (bent) ray.
You can turn the laser on by hitting the red switch on it. You can click and drag the body of the laser emitter to adjust the angles as needed (take the measurements according to what the data table states).
Here is an example of light with an angle of incidence of 50° and an angle of refraction that is 35°.
To calculate the refractive index of the second medium, we rearrange Snell’s Law to solve for n 2 :
𝑛 2 =
𝑛 1 sin 𝜃 1 sin 𝜃 2
=
(1) sin 50° sin 35°
= 1.
Now you have all the instructions you need to begin the experiment!