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Experiment #7. Titration of Vinegar, Lab Reports of Chemistry

Density of vinegar which is 1.005 g/mL

Typology: Lab Reports

2020/2021

Uploaded on 05/11/2021

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Experiment #7. Titration of Vinegar
Goal
To determine the mass percent of acetic acid in a solution via titration.
Introduction
Vinegar is a common household item that is found in a number of products from salad dressing to cleaners.
Vinegar is a solution of acetic acid (CH3COOH or HC2H3O2) in water. The amount of acetic acid is usually 5% by mass in the
vinegar solution. In this experiment, you will determine the mass percent of acetic acid in vinegar by titration.
Titration is a common method used by chemists to find the concentration of a substance in a solution. Titration
involves two key components: the titrant and the analyte. The titrant is a solution of known concentration which is used
to find the concentration of the analyte, a solution of unknown concentration. Acid-base titrations are the most common
type of titration. If the analyte is an acid, then the titrant is a base. The titrant would be added to the analyte until all of
the acid is neutralized -- this is known as the equivalence point or end-point. At the equivalence point, the number of
moles of acid (H+) is equal to the number of moles of the base (OHโˆ’)(based on stoichiometry). By carefully measuring the
amount of titrant used, you can determine the number of moles of acid present.
The easiest way to determine the equivalence point of the reaction taking place is to use a visual indicator. Visual
indicators change color at different pH. For this titration the indicator is phenolphthalein, which changes from colorless
(pH < 8) to pink (pH > 8). The analyte for this experiment is the acetic acid in vinegar with pH less than 7. Our titrant will
be sodium hydroxide, a base. When enough titrant, NaOH, is added to neutralize the acetic acid, the solution will change
from colorless to just barely pink in color.
NaOH(aq) + HC2H3O2(aq) โ†’ H2O(l) + NaC2H3O2(aq)
In titrations, it is important that you measure all volumes precisely. You must know the exact amount (to 0.01 mL) of
NaOH(aq) required to react with the HC2H3O2 as well as the amount of HC2H3O2 you began with.
The reaction of NaOH with HC2H3O2 is 1:1 stoichiometrically. Since you will measure the volume of NaOH(aq)
added and be given the molar concentration of the NaOH, you can find the moles of NaOH. The moles of NaOH will be
equal to the moles of HC2H3O2 in the solution. To get percent by mass of HC2H3O2 in vinegar, you will need to know the
molar mass of the HC2H3O2 and the mass of the vinegar sample.
Laboratory Activity
Materials: 2 x 125 mL Erlenmeyer flasks vinegar deionized water
50 mL buret 200 or 250 mL beaker phenolphthalein
buret stand and holder funnel standardized sodium hydroxide (NaOH) (aq)
Procedure
1. This lab will be performed individually by all students. Each student will use their own buret.
2. Rinse a 50 mL buret two or three times with deionized water. Be sure to let the water run out of the tip.
3. Remove traces of water from the buret by rinsing with NaOH(aq): add two pipettesโ€™ worth (approximately 2 mL) of
NaOH(aq) to the buret. Drain some NaOH(aq) out of tip then pour the rest out of the top into the sink, rotating as
you pour to coat the sides with the solution. Repeat with another 2 mL portion of NaOH(aq).
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Experiment #7. Titration of Vinegar

Goal To determine the mass percent of acetic acid in a solution via titration. Introduction Vinegar is a common household item that is found in a number of products from salad dressing to cleaners. Vinegar is a solution of acetic acid (CH 3 COOH or HC 2 H 3 O 2 ) in water. The amount of acetic acid is usually 5% by mass in the vinegar solution. In this experiment, you will determine the mass percent of acetic acid in vinegar by titration. Titration is a common method used by chemists to find the concentration of a substance in a solution. Titration involves two key components: the titrant and the analyte. The titrant is a solution of known concentration which is used to find the concentration of the analyte, a solution of unknown concentration. Acid-base titrations are the most common type of titration. If the analyte is an acid, then the titrant is a base. The titrant would be added to the analyte until all of the acid is neutralized -- this is known as the equivalence point or end-point. At the equivalence point, the number of moles of acid (H+) is equal to the number of moles of the base (OHโˆ’)(based on stoichiometry). By carefully measuring the amount of titrant used, you can determine the number of moles of acid present. The easiest way to determine the equivalence point of the reaction taking place is to use a visual indicator. Visual indicators change color at different pH. For this titration the indicator is phenolphthalein, which changes from colorless (pH < 8) to pink (pH > 8). The analyte for this experiment is the acetic acid in vinegar with pH less than 7. Our titrant will be sodium hydroxide, a base. When enough titrant, NaOH, is added to neutralize the acetic acid, the solution will change from colorless to just barely pink in color. NaOH(aq) + HC 2 H 3 O 2 (aq) โ†’ H 2 O(l) + NaC 2 H 3 O 2 (aq) In titrations, it is important that you measure all volumes precisely. You must know the exact amount (to 0.01 mL) of NaOH(aq) required to react with the HC 2 H 3 O 2 as well as the amount of HC 2 H 3 O 2 you began with. The reaction of NaOH with HC 2 H 3 O 2 is 1:1 stoichiometrically. Since you will measure the volume of NaOH(aq) added and be given the molar concentration of the NaOH, you can find the moles of NaOH. The moles of NaOH will be equal to the moles of HC 2 H 3 O 2 in the solution. To get percent by mass of HC 2 H 3 O 2 in vinegar, you will need to know the molar mass of the HC 2 H 3 O 2 and the mass of the vinegar sample. Laboratory Activity Materials: 2 x 125 mL Erlenmeyer flasks vinegar deionized water 50 mL buret 200 or 250 mL beaker phenolphthalein buret stand and holder funnel standardized sodium hydroxide (NaOH) (aq) Procedure

  1. This lab will be performed individually by all students. Each student will use their own buret.
  2. Rinse a 50 mL buret two or three times with deionized water. Be sure to let the water run out of the tip.
  3. Remove traces of water from the buret by rinsing with NaOH(aq): add two pipettesโ€™ worth (approximately 2 mL) of NaOH(aq) to the buret. Drain some NaOH(aq) out of tip then pour the rest out of the top into the sink, rotating as you pour to coat the sides with the solution. Repeat with another 2 mL portion of NaOH(aq).
  1. Fill the buret with NaOH solution until the volume reads a little above the 0.00 mL line. Drain the buret into a waste beaker until the buret reads 0.00 mL. The tip of the buret should be completely filled with solution โ€“ any air bubbles present will interfere with your measurements. If there is an air bubble in the tip, continue draining until the bubble comes out then refill the buret to 0.00 mL.
  2. Record the molarity of standardized NaOH as written on the bottle (not 0.1M! This is the approximate value, you need more significant figures)
  3. Obtain an Erlenmeyer flask and rinse it well with deionized water (you do not need to dry it). Carefully measure 2.00 mL of vinegar in a 10 mL graduated cylinder and add it to one flask. Then add about 25 mL of deionized water and one drop ( only 1 drop ) of phenolphthalein to the flask.
  4. Titrate the vinegar solution by carefully adding NaOH(aq) from the buret into the Erlenmeyer flask containing the vinegar. Gently swirl the flask constantly to mix. Stop the titration when a faint pink color appears and persists for 30 seconds. Record the volume added to 0.01 mL. This is the equivalence point.
  5. Repeat from step 6 two more times for a total of three titrations.
  6. Pour unused sodium hydroxide from your buret into the recovery bottle. Rinse the buret several times (including the tip!) with deionized water before putting it back. Disposal โ— unused NaOH(aq) in the buret โ€“ pour back into the recovery bottle. โ— all other solutionsโ€“down the sink drain Calculations The percent by mass of acetic acid in the vinegar solution is: ๐‘”๐‘Ÿ๐‘Ž๐‘š๐‘  ๐ป๐ถ 2 ๐ป 3 ๐‘‚ 2 ๐‘”๐‘Ÿ๐‘Ž๐‘š๐‘  ๐‘ฃ๐‘–๐‘›๐‘’๐‘”๐‘Ž๐‘Ÿ x 100 Because the ratio of NaOH to HC 2 H 3 O 2 is 1:1, the moles of NaOH = (Vin liters) x (Molarity NaOH) = moles of HC 2 H 3 O 2. Grams of HC 2 H 3 O 2 = moles of HC 2 H 3 O 2 x Molar Mass of HC 2 H 3 O 2. The grams of vinegar can be calculated from the volume of vinegar titrated x density vinegar.

Concentration of NaOH (from the label on the bottle.) ________________________ Molar Mass of HC 2 H 3 O 2 ____________________________ Density of vinegar = 1.005 g/mL Run 1 Run 2 Run 3 Initial buret reading (mL) Final buret reading (mL) Color of end point Show in detail with units for each calculation. Round for correct significant figures at the end of each calculation prompt. Q1. Calculate the mass of each 2.00 mL vinegar sample. Q2. Calculate the mass of acetic acid ( HC 2 H 3 O 2 ) for each run.

Q3. Calculate the mass percent of acetic acid in vinegar for each run. Q4. Find the average the mass percent for your three runs. Use this average as your experimental value to calculate percent error. The actual mass percent is 5.0%. Note the numerator is absolute difference, so percent errors will always be positive. ๐‘ƒ๐‘’๐‘Ÿ๐‘๐‘’๐‘›๐‘ก ๐‘’๐‘Ÿ๐‘Ÿ๐‘œ๐‘Ÿ = (

Q5a. If a student gets a very dark pink end point, would you expect their mass percent calculation to be lower or higher than the actual mass percent? __________ Explain why. Q5b. Write the mass percent for your darkest and lightest pink endpoints. Does the expectation from Q5a hold true for your experiment?