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Density of vinegar which is 1.005 g/mL
Typology: Lab Reports
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Goal To determine the mass percent of acetic acid in a solution via titration. Introduction Vinegar is a common household item that is found in a number of products from salad dressing to cleaners. Vinegar is a solution of acetic acid (CH 3 COOH or HC 2 H 3 O 2 ) in water. The amount of acetic acid is usually 5% by mass in the vinegar solution. In this experiment, you will determine the mass percent of acetic acid in vinegar by titration. Titration is a common method used by chemists to find the concentration of a substance in a solution. Titration involves two key components: the titrant and the analyte. The titrant is a solution of known concentration which is used to find the concentration of the analyte, a solution of unknown concentration. Acid-base titrations are the most common type of titration. If the analyte is an acid, then the titrant is a base. The titrant would be added to the analyte until all of the acid is neutralized -- this is known as the equivalence point or end-point. At the equivalence point, the number of moles of acid (H+) is equal to the number of moles of the base (OHโ)(based on stoichiometry). By carefully measuring the amount of titrant used, you can determine the number of moles of acid present. The easiest way to determine the equivalence point of the reaction taking place is to use a visual indicator. Visual indicators change color at different pH. For this titration the indicator is phenolphthalein, which changes from colorless (pH < 8) to pink (pH > 8). The analyte for this experiment is the acetic acid in vinegar with pH less than 7. Our titrant will be sodium hydroxide, a base. When enough titrant, NaOH, is added to neutralize the acetic acid, the solution will change from colorless to just barely pink in color. NaOH(aq) + HC 2 H 3 O 2 (aq) โ H 2 O(l) + NaC 2 H 3 O 2 (aq) In titrations, it is important that you measure all volumes precisely. You must know the exact amount (to 0.01 mL) of NaOH(aq) required to react with the HC 2 H 3 O 2 as well as the amount of HC 2 H 3 O 2 you began with. The reaction of NaOH with HC 2 H 3 O 2 is 1:1 stoichiometrically. Since you will measure the volume of NaOH(aq) added and be given the molar concentration of the NaOH, you can find the moles of NaOH. The moles of NaOH will be equal to the moles of HC 2 H 3 O 2 in the solution. To get percent by mass of HC 2 H 3 O 2 in vinegar, you will need to know the molar mass of the HC 2 H 3 O 2 and the mass of the vinegar sample. Laboratory Activity Materials: 2 x 125 mL Erlenmeyer flasks vinegar deionized water 50 mL buret 200 or 250 mL beaker phenolphthalein buret stand and holder funnel standardized sodium hydroxide (NaOH) (aq) Procedure
Concentration of NaOH (from the label on the bottle.) ________________________ Molar Mass of HC 2 H 3 O 2 ____________________________ Density of vinegar = 1.005 g/mL Run 1 Run 2 Run 3 Initial buret reading (mL) Final buret reading (mL) Color of end point Show in detail with units for each calculation. Round for correct significant figures at the end of each calculation prompt. Q1. Calculate the mass of each 2.00 mL vinegar sample. Q2. Calculate the mass of acetic acid ( HC 2 H 3 O 2 ) for each run.
Q3. Calculate the mass percent of acetic acid in vinegar for each run. Q4. Find the average the mass percent for your three runs. Use this average as your experimental value to calculate percent error. The actual mass percent is 5.0%. Note the numerator is absolute difference, so percent errors will always be positive. ๐๐๐๐๐๐๐ก ๐๐๐๐๐ = (
Q5a. If a student gets a very dark pink end point, would you expect their mass percent calculation to be lower or higher than the actual mass percent? __________ Explain why. Q5b. Write the mass percent for your darkest and lightest pink endpoints. Does the expectation from Q5a hold true for your experiment?