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Material Type: Exam; Professor: Condon; Class: General Chemistry I; Subject: Chemistry; University: Roane State Community College; Term: Unknown 1989;
Typology: Exams
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** (^) Bold lettering on a physical quantity indicate a molar quantity, i.e. per mole.
Do not hand in this work sheet. When you are ready, you will be given an examination over this material. Complete the examination by yourself and hand it in to receive credit.
In the following exercise you will need the following constants:
1 atm / 760 torr*^ R = 0.08206 L atm mol -^1 K -^1 VSTP = 22.4 L mol -^1 ** T/K = tEC /EC + 273.15 NA = 6.022 × 10^23
Humidity Table: Temperature in EC versus Water Vapor Pressure in torr 0 EC 4.6 torr 10 EC 9.2 torr 20 EC 17.5 torr 1 EC 4.9 torr 11 EC 9.8 torr 21 EC 18.7 torr 2 EC 5.3 torr 12 EC 10.5 torr 22 EC 19.8 torr 3 EC 5.7 torr 13 EC 11.2 torr 23 EC 21.1 torr 4 EC 6.1 torr 14 EC 12.0 torr 24 EC 22.4 torr 5 EC 6.5 torr 15 EC 12.8 torr 25 EC 23.8 torr 6 EC 7.0 torr 16 EC 13.6 torr 26 EC 25.2 torr 7 EC 7.5 torr 17 EC 14.5 torr 27 EC 26.7 torr 8 EC 8.0 torr 18 EC 15.5 torr 28 EC 28.3 torr 9 EC 8.6 torr 19 EC 16.5 torr 29 EC 30.0 torr
Vapor Pressure of some organic compounds: Compound Name Temperature EC for the pressures: 1 torr 10 torr 40 torr 100 torr 400 torr 760 torr Methanol -44.0 -16.2 +5.0 +21.6 +49.9 +64. Carbon disulfide -73.9 -44.7 -22.5 -5.1 + 28.0 +46. Acetic acid -17.2 +17.5 +43.0 +63.0 +99.0 +118. Ethanol -31.3 - 2.3 +19.0 + 34.9 + 63.5 + 78. Propanone -59.4 -31.1 - 9.4 + 7.7 + 39.5 + 56. 1-propanol -15.0 +14.7 +36.4 + 52.8 + 82.0 + 97. 2-propanol -26.1 + 2.4 +23.8 + 39.5 + 67.8 + 82.
Use the perfect gas law (PV = nRT) to answer the following questions:
ANS: 22 L of CO (^2)
ANS: 16.3 g of CO (^2)
ANS: 2.4 × 10^4 L of gas
ANS: 2.46 × 10^22 molecules
If you were unable to do the above problems, STOP. Go back and review stoichiometry. Proceeding beyond this point will be a waste of your time if you do not.
(Still referring to the equation: 2CO + O 2! 2CO 2 )
ANS: 2.00 mol of CO (^2)
ANS: 17 L of O 2
ANS: 45 L of CO (^2)
(Still referring to the equation: 2CO + O 2! 2CO 2 )
ANS: 53 L of CO (^2)
How many grams of CO would be consumed under these conditions?
ANS: 103 g of CO
You will need to review Dalton's Law in order to answer the following questions. (Ptotal = ΣPindividual)
ANS: 1.8 atm of CO 2
ANS: 0.0230 atm water
ANS: 0.977 atm air
ANS: 0.0217 atm water
ANS: 0.0526 atm ethanol
ANS: 0.926 atm air
ANS: 0.00 atm of CO ANS: 0.395 atm of CO 2
ANS: 0.368 atm of O 2 ANS: 0.0395 atm of H 2 O
ANS: 0.00888 mol ethanol
ANS: 0.408 g ethanol
ANS: 0.00888 mol
ANS: 57.4 g mol -^1