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Final Exam Questions for Gas Law Exercise - General Chemistry I | CHEM 1110, Exams of Chemistry

Material Type: Exam; Professor: Condon; Class: General Chemistry I; Subject: Chemistry; University: Roane State Community College; Term: Unknown 1989;

Typology: Exams

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Gas Law Exercise Page 128
* The definition of the torr. The definition of an atmosphere is 1 atm / 101.325 kPa.
** Bold lettering on a physical quantity indicate a molar quantity, i.e. per mole.
Gas Law Exercises
Do not hand in this work sheet. When you are ready, you will be given an examination
over this material. Complete the examination by yourself and hand it in to receive
credit.
In the following exercise you will need the following constants:
1 atm / 760 torr*R = 0.08206 L atm mol-1 K-1VSTP = 22.4 L mol-1 **
T/K = tEC /EC + 273.15 NA = 6.022 × 1023
Humidity Table:
Temperature in EC versus Water Vapor Pressure in torr
0EC 4.6 torr 10EC 9.2 torr 20EC 17.5 torr
1EC 4.9 torr 11EC 9.8 torr 21EC 18.7 torr
2EC 5.3 torr 12EC 10.5 torr 22EC 19.8 torr
3EC 5.7 torr 13EC 11.2 torr 23EC 21.1 torr
4EC 6.1 torr 14EC 12.0 torr 24EC 22.4 torr
5EC 6.5 torr 15EC 12.8 torr 25EC 23.8 torr
6EC 7.0 torr 16EC 13.6 torr 26EC 25.2 torr
7EC 7.5 torr 17EC 14.5 torr 27EC 26.7 torr
8EC 8.0 torr 18EC 15.5 torr 28EC 28.3 torr
9EC 8.6 torr 19EC 16.5 torr 29EC 30.0 torr
Vapor Pressure of some organic compounds:
Compound Name Temperature EC for the pressures:
1 torr 10 torr 40 torr 100 torr 400 torr 760 torr
Methanol -44.0 -16.2 +5.0 +21.6 +49.9 +64.7
Carbon disulfide -73.9 -44.7 -22.5 -5.1 + 28.0 +46.5
Acetic acid -17.2 +17.5 +43.0 +63.0 +99.0 +118.1
Ethanol -31.3 - 2.3 +19.0 + 34.9 + 63.5 + 78.4
Propanone -59.4 -31.1 - 9.4 + 7.7 + 39.5 + 56.5
1-propanol -15.0 +14.7 +36.4 + 52.8 + 82.0 + 97.8
2-propanol -26.1 + 2.4 +23.8 + 39.5 + 67.8 + 82.5
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  • (^) The definition of the torr. The definition of an atmosphere is 1 atm / 101.325 kPa.

** (^) Bold lettering on a physical quantity indicate a molar quantity, i.e. per mole.

Gas Law Exercises

Do not hand in this work sheet. When you are ready, you will be given an examination over this material. Complete the examination by yourself and hand it in to receive credit.

In the following exercise you will need the following constants:

1 atm / 760 torr*^ R = 0.08206 L atm mol -^1 K -^1 VSTP = 22.4 L mol -^1 ** T/K = tEC /EC + 273.15 NA = 6.022 × 10^23

Humidity Table: Temperature in EC versus Water Vapor Pressure in torr 0 EC 4.6 torr 10 EC 9.2 torr 20 EC 17.5 torr 1 EC 4.9 torr 11 EC 9.8 torr 21 EC 18.7 torr 2 EC 5.3 torr 12 EC 10.5 torr 22 EC 19.8 torr 3 EC 5.7 torr 13 EC 11.2 torr 23 EC 21.1 torr 4 EC 6.1 torr 14 EC 12.0 torr 24 EC 22.4 torr 5 EC 6.5 torr 15 EC 12.8 torr 25 EC 23.8 torr 6 EC 7.0 torr 16 EC 13.6 torr 26 EC 25.2 torr 7 EC 7.5 torr 17 EC 14.5 torr 27 EC 26.7 torr 8 EC 8.0 torr 18 EC 15.5 torr 28 EC 28.3 torr 9 EC 8.6 torr 19 EC 16.5 torr 29 EC 30.0 torr

Vapor Pressure of some organic compounds: Compound Name Temperature EC for the pressures: 1 torr 10 torr 40 torr 100 torr 400 torr 760 torr Methanol -44.0 -16.2 +5.0 +21.6 +49.9 +64. Carbon disulfide -73.9 -44.7 -22.5 -5.1 + 28.0 +46. Acetic acid -17.2 +17.5 +43.0 +63.0 +99.0 +118. Ethanol -31.3 - 2.3 +19.0 + 34.9 + 63.5 + 78. Propanone -59.4 -31.1 - 9.4 + 7.7 + 39.5 + 56. 1-propanol -15.0 +14.7 +36.4 + 52.8 + 82.0 + 97. 2-propanol -26.1 + 2.4 +23.8 + 39.5 + 67.8 + 82.

Use the perfect gas law (PV = nRT) to answer the following questions:

  1. How many liters of CO 2 gas would one have at STP if one started with 15.0 L at 200.0EC and 2.5 atm?

ANS: 22 L of CO (^2)

  1. How many grams of CO 2 gas is contained in a 12.0 L volume which is at 115EC and 745 torr?

ANS: 16.3 g of CO (^2)

  1. What is the volume of 3.0 mol of gas at 2.35 torr and 25EC?

ANS: 2.4 × 10^4 L of gas

  1. How many molecules of CO 2 gas are contained in a volume of 1.00 L at 25EC and 760.0 torr?

ANS: 2.46 × 10^22 molecules

If you were unable to do the above problems, STOP. Go back and review stoichiometry. Proceeding beyond this point will be a waste of your time if you do not.

(Still referring to the equation: 2CO + O 2! 2CO 2 )

  1. If one starts with 44.8 L of CO at STP and reacts with an excess of O 2 , how many moles of CO 2 would one obtain at STP?

ANS: 2.00 mol of CO (^2)

  1. If one were to start with 1.50 moles of CO, how many liters of O 2 at STP would be required to completely react with the CO?

ANS: 17 L of O 2

  1. If one were to react 45 L of CO at 400EC and 1.00 atm with an excess O 2 , how many liters of CO 2 at 400EC and 1.00 atm are produced?

ANS: 45 L of CO (^2)

(Still referring to the equation: 2CO + O 2! 2CO 2 )

  1. If one were to react 30.0 L of O 2 which has a partial pressure of 1.50 atm at 298 K with an excess of CO, how many liters of CO 2 would be produced if the final temperature were 600EC and the pressure of the CO 2 were 5.00 atm.?

ANS: 53 L of CO (^2)

How many grams of CO would be consumed under these conditions?

ANS: 103 g of CO

You will need to review Dalton's Law in order to answer the following questions. (Ptotal = ΣPindividual)

  1. If, at 0EC, one were to have 3.50 atm of gas consisting of 1.20 atm of CO, 0.50 atm of O 2 and the rest CO 2 , what is the pressure of CO 2?

ANS: 1.8 atm of CO 2

  1. A 500 mL flask at 20EC contains 25 mL of liquid water. The rest of the flask is filled with air. The total pressure of the gases is 1.000 atm. What is the pressure of the water? What is the pressure of the dry air?

ANS: 0.0230 atm water

ANS: 0.977 atm air

  1. A box at 19EC contains 25 mL of pure liquid water in a beaker and 25 mL of pure ethanol in a separate beaker. The rest of the gases in the box is air. Assume the vapor pressures of the water and ethanol have come to equilibrium in the gas but no cross contamination has occurred. The total pressure of the gases is 1.000 atm. What is the pressure of the water? What is the pressure of the ethanol? What is the pressure of the air?

ANS: 0.0217 atm water

ANS: 0.0526 atm ethanol

ANS: 0.926 atm air

  1. In a 45 L container there is water liquid, CO gas and O 2 gas. The container is at 29 EC. The total pressure is 1.00 atm and the CO pressure is 300 torr. After reacting to form CO 2 , what would be the pressure of each gas at 29EC if there is no volume change?

ANS: 0.00 atm of CO ANS: 0.395 atm of CO 2

ANS: 0.368 atm of O 2 ANS: 0.0395 atm of H 2 O

  1. 10.0 g of ethanol is contained in a 275.5 mL flask. This flask is heated to 100EC and the ethanol vapor sweeps all the air out of the flask. The pressure is 750 torr. How many moles of ethanol is contained in the flask? How many grams of ethanol is this? (The molecular weight of ethanol is 46.0 g mol -^1 .)

ANS: 0.00888 mol ethanol

ANS: 0.408 g ethanol

  1. 10.0 g of an unknown compound is contained in a 275.5 mL flask. This flask is heated to 100EC and the compound's vapor sweeps all the air out of the flask. The pressure is 750 torr. After this treatment, the flask is cooled and 0.510 g of the unknown compound condenses out in the flask. How many moles of this compound is contained in the flask? What is the molecular weight of this compound?

ANS: 0.00888 mol

ANS: 57.4 g mol -^1