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Homework Solutions - Introduction Linear Algebra | MATH 247, Assignments of Linear Algebra

Material Type: Assignment; Class: Introduction Linear Algebra; Subject: Mathematics & Statistics; University: California State University - Long Beach; Term: Spring 2003;

Typology: Assignments

Pre 2010

Uploaded on 08/18/2009

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Newberger Math 247 Spring 03
Homework solutions: Section 2.8 #31-36
31. Suppose Fis a 5 ×5 matrix whose column space is not equal to
R5. What can you say about Nul F?
Start your explanations with the assumptions (the suppose part).
Since the column space of Fis not equal to R5,Fdoes not have a
pivot in every row. Since Fis square, we know Falso does not have
a pivot in every column. This means that the homogeneous equation
Fx=0has non-trivial solutions. Since Nul Fis the solution set to
the homogeneous equation, we can deduce that Nul Fcontains nonzero
vectors, or in other words, Nul F6={0}.
32. If Ris a 6 ×6 matrix and Nul Ris not the zero subspace, what
can you say about Col R?
Start your explanation with the assumptions (the if part). Since
Nul Ris not the zero subspace, we know that the homogeneous equation
Rx=0has nontrivial solutions. This means that Rdoes not have a
pivot in every column. Since Ris square, this also means that Rdoes
not have a pivot in every row, so the columns of Rdo not span all of
R6. Thus Col Ris not equal to R6.
33. If Qis a 4 ×4 matrix and Col Q=R4, what can you say about
solutions of equations of the form Qx=bfor bin R4?
Start with the assumptions (the if part). Since Col Q=R4, the
span of the columns of Qis all of R4, so Qhas a pivot in every row.
Furthermore, since Qis square, Qalso has a pivot in every column.
This means that Qx=bhas a unique solution for all bin R4. Keep
straight in your mind that a pivot in every row means the solution
always exists, and a pivot in every column means that when there is a
solution, that solution is unique.
34. If Pis a 5 ×5 matrix and Nul Pis the zero subspace, what can
you say about solutions of the equations of the form Px=bfor bin
R5?
Start with the assumptions (the if part). Since Nul Pis the zero sub-
space, the homogeneous equation Px=0has only the trivial solution,
which means that Phas a pivot position in every column. Since Pis
square, Palso has a pivot in every row. Thus Px=bhas a unique
solution for every bin R5. Keep straight in your mind that a pivot in
1
pf2

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Newberger Math 247 Spring 03 Homework solutions: Section 2.8 #31-

  1. Suppose F is a 5 × 5 matrix whose column space is not equal to R^5. What can you say about Nul F?

Start your explanations with the assumptions (the suppose part). Since the column space of F is not equal to R^5 , F does not have a pivot in every row. Since F is square, we know F also does not have a pivot in every column. This means that the homogeneous equation F x = 0 has non-trivial solutions. Since Nul F is the solution set to the homogeneous equation, we can deduce that Nul F contains nonzero vectors, or in other words, Nul F 6 = { 0 }.

  1. If R is a 6 × 6 matrix and Nul R is not the zero subspace, what can you say about Col R?

Start your explanation with the assumptions (the if part). Since Nul R is not the zero subspace, we know that the homogeneous equation Rx = 0 has nontrivial solutions. This means that R does not have a pivot in every column. Since R is square, this also means that R does not have a pivot in every row, so the columns of R do not span all of R^6. Thus Col R is not equal to R^6.

  1. If Q is a 4 × 4 matrix and Col Q = R^4 , what can you say about solutions of equations of the form Qx = b for b in R^4?

Start with the assumptions (the if part). Since Col Q = R^4 , the span of the columns of Q is all of R^4 , so Q has a pivot in every row. Furthermore, since Q is square, Q also has a pivot in every column. This means that Qx = b has a unique solution for all b in R^4. Keep straight in your mind that a pivot in every row means the solution always exists, and a pivot in every column means that when there is a solution, that solution is unique.

  1. If P is a 5 × 5 matrix and Nul P is the zero subspace, what can you say about solutions of the equations of the form P x = b for b in R^5?

Start with the assumptions (the if part). Since Nul P is the zero sub- space, the homogeneous equation P x = 0 has only the trivial solution, which means that P has a pivot position in every column. Since P is square, P also has a pivot in every row. Thus P x = b has a unique solution for every b in R^5. Keep straight in your mind that a pivot in 1

2

every row means the solution always exists, and a pivot in every column means when there is a solution, that solution is unique.

  1. What can you say about Nul B when B is a 5 × 4 matrix with linearly independent columns?

Since B has linearly independent columns, B has a pivot in every column. This means that the homogeneous equation Bx = 0 has only the trivial solution, so Nul B = { 0 } where 0 denotes the zero vector in R^4.

  1. What can you say about the shape of an m × n matrix A when the columns of A form a basis for Rm?

If the columns of A form a basis for Rm, the columns of A must span R^5 (so A must have a pivot in every row), and the columns must be linearly independent (so A must have a pivot in every column). Thus in this case m = n. Thus A is a square matrix.