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Infrared Spectroscopy and Spect practice questions and solutions.
Typology: Quizzes
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Chapter 12 practice
A) 1 - pentene
B) 2 - pentene
methyl
pentene
D) 2,3-dimethyl- 2 - pentene
E) 2,4-dimethyl- 2 - pentene
A) 1 - pentanol
B) 2 - butanol
C) diethyl ether
D) octane
E) (E)- 2 - pentene
A) the stiffness of the bond and the electronegativity of the atoms
B) the electronegativity of the atoms and the nuclear charges of the atoms
C) the masses of the atoms and the stiffness of the bond
D) the nuclear charges of the atoms and the atomic radii
E) the electronegativity of the atoms and the masses of the atoms
and M+2 peaks of approximately equal intensity?
A) 3 - bromopentane
pentanol
C) pentane
D) 3 - chloropentane
E) 3 - iodopentane
A) 1 - butanol B) octane C) diethyl ether D) 2 - hexyne E) benzene
B and
B, with
B being about 4 times more abundant. In the
mass spectrum of trimethylborate [(CH 3
A) the peaks at m/z 103 and m/z 104 have equivalent intensities
B) the peak at m/z 103 has an intensity which is 4 times that of the m/z 104 peak
C) the peak at m/z 103 has an intensity which is 1/4 the intensity of the peak at m/z 104
D) none of the above
cm
in the IR?
B) butane C) but- 1 - ene D) CH 3
A) X-rays
B) radio waves
C) microwaves
D) ultraviolet light
E) infrared light
A) hλ B) c/λ C) hc/λ D) 1/λ
and a strong
absorption at 1640 cm
A) 2n B) 2n - 2 C) 3n D) 3n - 3 E) 3n - 6
Which IR band is typically more intense, the C ≡ C stretch or the C ≡ N stretch? Explain briefly.
How does the O
and CH 3
pentene
fingerprint
inversely
; vinylic CH stretch above 3000 cm
) would indicate complete reaction of the alcohol starting
material.
The C ≡ N stretch tends to be more intense because stretching resulting in a greater change in the bond dipole.
Because of the unusually strong hydrogen bonding in carboxylic acids, the broad O-H stretch is shifted to about 3000
cm
centered on top of the usual C-H absorption. This broad O-H absorption gives a characteristic overinflated
shape to the peaks in the C-H region.
O absorption in conjugated carbonyl appears at lower wavenumber