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Intermediate Rigging Exam | Questions and Verified Answers | Latest 2025/ 2026 Update, Exams of Engineering

Intermediate Rigging Exam | Questions and Verified Answers | Latest 2025/ 2026 Update | 100% Correct | GRADED A

Typology: Exams

2024/2025

Available from 06/20/2025

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Intermediate Rigging Exam | Questions and
Verified Answers | Latest 2025/ 2026 Update |
100% Correct | GRADED A
.
Question:
What is the distance from an uncompacted soil
Answer:
1.5 ×depth
Question:
What is the distance from compacted soil
Answer:
1×depth
Question:
How far past tracks must mats be
Answer:
2'
Question:
Name 2 methods for cribbing
Answer:
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff

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Intermediate Rigging Exam | Questions and

Verified Answers | Latest 2025/ 2026 Update |

100% Correct | GRADED A

Question:

What is the distance from an uncompacted soil

Answer:

1.5 ×depth

Question:

What is the distance from compacted soil

Answer:

1×depth

Question:

How far past tracks must mats be

Answer:

Question:

Name 2 methods for cribbing

Answer:

  1. area of float ×3= blocking area
  2. crane capacity ÷5= blocking area

Question:

How level must cranes be

Answer:

1% or .57°

Question:

What is the formula for leverage

Answer:

Weight × distance = weight × distance

Question:

How far must you type off the crane

Answer:

2' from the counter weights

Question:

What is the wind speed that stops hoisting operations

Answer:

Question:

What is the best tag line to use for work near powerlines

Answer:

Polypropylene

Question:

What does it mean when you have localized narrowing of outside diameter of wire rope

Answer:

Broken core

Question:

What is RRL

Answer:

Right regular lay

Question:

What is EIPS

Answer:

Extra improved plow steel

Question:

What is IWRC

Answer:

Independent wire rope core

Question:

What percentage of diameter can wire rope not go below

Answer:

Question:

Gross capacity is the same as

Answer:

Allowable line pull

Question:

Gross capacity- deductions equals

Answer:

Net capacity

Question:

What is the capacity for crane on outriggers, tire, track

Answer:

Outriggers= 85% Tires=75% Tracks=75%

Question:

How many broken wires are required to make a standard running rope unusable

Answer:

3 per strand per lay, 6 random per lay

Question:

How many broken wires are required to make a rotation resistant running rope unusable

Answer:

2 per strand per 6 rope diameters, 4 per strand per 30 rope diameters

Question:

How many broken wires are required to make a standing rope at end fittings unusable

Answer:

Question:

How many broken wires are required to make a standing rope at mid area unusable

Answer:

Question:

How many broken wires are required to make a wire rope sling unusable

Answer:

5 per strand per lay, 10 random per lay

Question:

What is the sling stress for 90°

Answer:

Question:

What is the sling stress for 60°

Answer:

Question:

What is the sling stress for 45°

Answer:

Question:

What is the sling stress for 30°

Answer:

Question:

What is the safety factor for standard wire rope

Answer:

Question:

How must eye bolts be placed on a load

Answer:

Parallel

Question:

What is the minimum depth an eye bolt must be

Answer:

1.5×diameter of bolt

Question:

You must reject a bean clamp if

Answer:

15% of normal opening eye bent worn eye capacity unreadable

Question:

Reject plate clamps if

Answer:

Changes in opening or teeth Cracks Loose or damaged rivets Lift eye damaged Excessive rust Capacity unreadable

Question:

Reject chains if

Answer:

15% wear 5% stretch

Question:

What do you drop the cranes capacity to for tandem lift

Answer:

Question:

What is a sheet bend used for

Question:

What is SLL

Answer:

Safe load limit

Question:

What is WLL

Answer:

Working load limit

Question:

Sling tension

Answer:

Weight÷ #of slings×load angle factor

Question:

What is the design factor for Shackles over 150

Answer:

Question:

What do swivel rings need

Answer:

Torque value

Question:

How do you find the load factor and weight distribution

Answer:

Sling tension= Sling length (L)÷ sling height (H)× share of load weight L÷H× share of load weight

Question:

How to find start of loads from known runs

Answer:

  1. length run side 1 (R1)+ R2= total span (TS)
  2. R2÷TS= Percentage (P)
  3. P×W= share of load on side A
  4. R1+R2=TS
  5. R1÷TS=P 6)P×W= share on side B

Question:

How to figure center of gravity from known weights

Answer:

  1. W1+W2= total weight (TW)
  2. W2÷TW=P
  3. P×span (S)= center of gravity (CG) in ft from A
  4. W1+W2=TW

5 times the load

Question:

Gross capacity

Answer:

Capacity in the load chart

Question:

Net capacity

Answer:

Gross minus deductions