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Law of Sines and Cosines Worksheet, Study Guides, Projects, Research of Law

This resource was created by Tallahassee Community College Learning Commons. MAC 1114. Trigonometry Applications : Law of Sines and Cosines Worksheet.

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This resource was created by Tallahassee Community College Learning Commons
MAC 1114
Trigonometry Applications : Law of Sines and Cosines Worksheet
Law of Sines (ratio) 𝒔𝒊𝒏 𝑨
𝒂= 𝒔𝒊𝒏 𝑩
𝒃=𝒔𝒊𝒏 𝑪
𝒄
Case 1: given ASA
A = 50o, B = 68o, c = 230.
Hint: angles are usually given in Capital letters and sides in small letters.
1. You can find C. (hint: sum of all angles in a triangle = 180)
2. Set up the ratio using the side given and one of the other angles.
______ = _______ and solve for the missing side.
3. You can repeat this if you need to know all of the sides.
Case 2: given SAA
B = 10o, C = 100o, c = 115
You have enough information to set up a ratio.
_______ = _______ (solving for b); continue if you need to find the other side.
Keep in mind you can find A by using the fact that the sum of all angles in a triangle = 180o.
Case 3: SSA (no solution)
a = 20, c = 45, A = 125o
Set up the ratio to solve for C
______ = ______ ;when you do this you get sin C =1.84 > 1 so outside of the
range for sine values! Therefore, this problem has no solution.
Case 4: given SSA (one solution)
A = 110o, c = 15, a = 28
Set up the ratio for this one using the appropriate ratio.
______ = ______ ; this will give you sin C = .503 or C = 30o or 150o
Let’s try 30o: B = 180 (110 + 30)= 40oLet’s try 150o: B = 180 (110 + 150)= -80o X (can’t draw a
triangle with a negative angle) so we reject this one. Thus, there is only one solution to this problem.
When to Use:
ASA and SAA is
given
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This resource was created by Tallahassee Community College Learning Commons

MAC 1114

Trigonometry Applications : Law of Sines and Cosines Worksheet

Law of Sines (ratio)

Case 1: given ASA A = 50o, B = 68o, c = 230. Hint: angles are usually given in Capital letters and sides in small letters.

  1. You can find C. (hint: sum of all angles in a triangle = 180)
  2. Set up the ratio using the side given and one of the other angles. ______ = _______ and solve for the missing side.
  3. You can repeat this if you need to know all of the sides. Case 2: given SAA B = 10o, C = 100o, c = 115 You have enough information to set up a ratio. _______ = _______ (solving for b); continue if you need to find the other side. Keep in mind you can find A by using the fact that the sum of all angles in a triangle = 180o. Case 3: SSA (no solution) a = 20, c = 45, A = 125o Set up the ratio to solve for C ______ = ______ ;when you do this you get sin C =1.84 > 1 so outside of the range for sine values! Therefore, this problem has no solution. Case 4: given SSA (one solution) A = 110o, c = 15, a = 28 Set up the ratio for this one using the appropriate ratio. ______ = ______ ; this will give you sin C = .503 or C = 30o^ or 150o Let’s try 30o: B = 180 – (110 + 30)= 40o^ Let’s try 150o: B = 180 – (110 + 150)= - 80 o^ X (can’t draw a triangle with a negative angle) so we reject this one. Thus, there is only one solution to this problem. When to Use: ASA and SAA is given

This resource was created by Tallahassee Community College Learning Commons Case 5: SSA (2 solutions) a = 26, c = 15, C = 29o _______ = _______ ; solve for A, this will give you 57.2o^ or 122.8o Let’s try 75.2o: B = 180 – (57.2 + 29) = 93.8o Let’s try 150o: B = 180 – (122.8+ 29) = 28.2o Since there are two legitimate values for B, we will have two triangles. Use each B to find the rest of the missing pieces for the two triangles.

Law of Cosines a^2 = b^2 + c^2 – 2bc cos(a)

b^2 = a^2 + c^2 – 2ac cos(b)

c

2

= a

2

+ b

2

  • 2ab cos(c) Case 1: SSS a = 21.2 ft., b = 24.6 ft. and c = 12 ft. since you don’t know any angle just pick 1 to find first! After you find one angle, you can switch back to law of sines or use the cosine again. Case 2: SAS C = 134o, a = 20 and b = 8. Hint: find c first and then you can switch back to law of sines. Applications
  1. A car travels east 1 hour at 40 mi/hr. the turns northeast and travels for 30 minutes longer. How far is it from its starting point?
  2. A cell phone tower is supported by two guy wires (165 ft. and 180 ft.) on opposite sides. Each wire is attached to the top of the tower and anchored to the ground. The shorter wire makes an angle of 67o with the ground. How far apart are the anchor points? Answers 1. 56 miles, 2. 55.5 ft When to Use: when you know 2 sides and the angle between them or if you know all 3 sides.