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Differentiation of Inverse Trigonometric Functions: A Calculus Lesson, Slides of Calculus for Engineers

A lesson on differentiating inverse trigonometric functions. It includes objectives such as deriving formulas for derivatives, applying these formulas, and solving related problems. Differentiation formulas for inverse sine, cosine, tangent, cotangent, secant, and cosecant functions, followed by several examples demonstrating how to find the derivatives of functions involving inverse trigonometric functions. These examples cover various complexities, including composite functions and simplification techniques, making it a useful resource for students learning calculus. Designed to help students understand and apply differentiation rules effectively. It offers a structured approach to mastering the differentiation of inverse trigonometric functions, enhancing problem-solving skills in calculus.

Typology: Slides

2024/2025

Available from 06/04/2025

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Lesson 9
Differentiation of
Inverse Trigonometric
Functions
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Lesson 9

Differentiation of

Inverse Trigonometric

Functions

OBJECTIVES

  • to derive the formula for the derivatives of the

inverse trigonometric functions;

  • to apply the derivative formulas to solve for the

derivatives of inverse trigonometric functions;

and

  • to solve problems involving derivatives of

inverse trigonometric functions.

DIFFERENTIATION FORMULA

Derivative of Inverse Trigonometric

Function

Derivative of Inverse Trigonometric

Function

( )

( )

( )

( )

( )

( ) dx

du

u u 1

1 csc u dx

d

dx

du

u u 1

1 sec u dx

d

dx

du

1 u

1 cot u dx

d

dx

du

1 u

1 tan u dx

d

dx

du

1 u

1 cos u dx

d

dx

du

1 u

1 sin u dx

d

Differentiation formulas forinverse trigonometric functions:

2

1

2

1

2

1

2

1

2

1

2

1

=−

=

=−

=

=−

=

( ) ( )

1 x sin 2 e 2

1

  1. h x

( )

x^2

x

1 2 e

2 e

2

1 h' x

= ⋅ 2 x

x

1 4 e

e

=

  1. g ( )t sec 5 t csc 5 t

− 1 − 1

g' ( )t 0

5

5t 25t 1

( 1) 5

5t 25t 1

1 g' t 2 2

=

=

x

2

  1. g x cot

= 1

  

 −

 

  

2 2 x

2

x

2 1

1 g' x 2 2

x x

4 1

2

^ ⋅ 

  

= (^) ( )

x 4
g' x

2

8. f( )x x tan ( 3 x)

2 − 1

) x

5

  1. y Sec (csc

− 1

1 x

5 csc x

5 csc

x

5

x

5 cot x

5 csc

y' 2

2

^ − 

  

 

 

 − −

= x

5 cot x

5 1 cot x

5 but, csc

2 2

^ = 

  

  − = 

  

2

'

x

5 y =