Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Mass of unknown metal sulfate = 0.323 g Mass of precipitated ..., Exercises of Chemistry

Mass of precipitated BaSO4 = 0.433 g. Contains all of the SO4. 2- in the unknown metal sulfate sample. We need the molar mass of the metal in order to ...

Typology: Exercises

2021/2022

Uploaded on 09/12/2022

anjushri
anjushri 🇺🇸

4.8

(14)

243 documents

1 / 4

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Mass of unknown metal sulfate = 0.323 g
Mass of precipitated BaSO4= 0.433 g Contains all of the SO42- in the unknown metal sulfate sample
We need the molar mass of the metal in order to identify it.
molar mass = mass in a given sample
moles in a given sample
If we find:
the mass of the metal in 0.323 g sample
the number of moles that the metal’s mass represents
Then we can find the molar mass of the metal
We can calculate both the mass and the moles of the metal from the mass of precipitated BaSO4.
To arrive at the moles of the metal, we need to calculate the moles of SO42-
Moles of sulfate =
233.38 g BaSO4
1 mol BaSO4
0.433 g BaSO4= 0.0018553 mol SO42-
××1 mol BaSO4
1 mol SO42-
If we assume M2SO4:
and relate it to the moles of metal via the formula of the compound, which depends on the charge of the metal cation:
M2SO4for M+
MSO4for M2+
M2(SO4)3for M3+
Moles of M = 2 mol M = 0.0037106 mol M
×
0.0018553 mol SO42-
1 mol SO42-
What is the metal in the unknown metal sulfate?
pf3
pf4

Partial preview of the text

Download Mass of unknown metal sulfate = 0.323 g Mass of precipitated ... and more Exercises Chemistry in PDF only on Docsity!

Mass of unknown metal sulfate = 0.323 g

Mass of precipitated BaSO

4

= 0.433 g Contains all of the SO

4

2-

in the unknown metal sulfate sample

We need the molar mass of the metal in order to identify it.

molar mass =

mass in a given sample

moles in a given sample

If we find:

  • the mass of the metal in 0.323 g sample
  • the number of moles that the metal’s mass represents

Then we can find the molar mass of the metal

We can calculate both the mass and the moles of the metal from the mass of precipitated BaSO

4

To arrive at the moles of the metal, we need to calculate the moles of SO

4

2-

Moles of sulfate =

233.38 g BaSO

4

1 mol BaSO

4

0.433 g BaSO

4

= 0.0018553 mol SO 4

2-

×

×

1 mol BaSO

4

1 mol SO 4

2-

If we assume M

2

SO

4

and relate it to the moles of metal via the formula of the compound, which depends on the charge of the metal cation:

M

2

SO

4

for M

MSO

4

for M

2+

M

2

(SO

4

3

for M

3+

Moles of M =

2 mol M

= 0.0037106 mol M × 0.0018553 mol SO

4

2-

1 mol SO

4

2-

What is the metal in the unknown metal sulfate?

To calculate the molar mass of M, we also need the mass of M in the unknown sample.

Since the unknown sample mass is composed of M and SO

4

2-

, we can get the mass of M by subtracting the mass of SO

4

2-

from the sample mass.

We already calculated the moles of SO 4

2-

, so we convert it to mass:

Mass of SO

4

2-

=

96.06 g SO

4

2-

= 0.17822 g SO 4

2-

×

0.0018553 mol SO

4

2-

1 mol SO

4

2-

Mass of M = ‒ 0.17822 g SO 4

2-

0.323 g M

2

SO

4

= 0.14478 g M

0.0037106 mol

molar mass of M

mass of M in 0.323 g sample

moles of M in 0.323 g sample

0.14478 g

= 39.0 g/mol M is potassium (K)

Alternatively, since we have a finite set of possibilities, we can calculate the mass % of sulfate (or mass

% metal) for each possibility. Then we can identify the metal by matching the mass % for our unknown

with one of the possibilities.

  • In that case, we don’t need to assume a cation charge (hence the formula) for our unknown, since

we calculate the experimental mass % directly from the data, without assuming a specific formula.

Mass of sulfate =

96.06 g SO

4

2-

1 mol SO

4

2-

0.0018553 mol SO 4

2-

×

= 0.1782 g SO

4

2-

Mass % of sulfate =

0.1782 g

0.323 g

which would match the sulfate mass % in K

2

SO

4

(pre-calculated, along with the other possible metal sulfates).

Do you remember how to calculate mass % of an element (or that of a polyatomic ion) from the chemical formula?

×

Mass of SO

4

2-

Mass of sample

×