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mathematical_physics_2007_12.pdf, Study Guides, Projects, Research of Mathematical Physics

mathematical_physics_2007_12.pdf

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PLOTTING
SCALAR
AND
VECTOR
FIELDS
19
~
Electric field lines
Equipotentials
Figure
2.1
Equipotentials
and
Electric Field Lines
of
Two
Parallel Line Charges
Usually we want to construct surfaces
of
constant
CP,
which
in
this
case are cylinders
nested around the line charges. Because there is symmetry in the
z
direction, these
surfaces can
be
plotted in two dimensions
as
the dashed, circular contours shown in
Figure
2.1.
The centers of these circles are located along the x-axis from
1
<
x
<
03
for positive values of
<P,
and from
--M
<
x
<
-
1
for negative values
of
CP.
CP
=
0
lies on the y-axis, which you can
think
of as a circle
of
infinite radius with its center
at infinity.
If
the contours have evenly spaced constant values of
<P,
the regions of
highest line density show where the function
is
most rapidly varying with position.
2.1.2
Plotting
Vector
Fields
Because vectors have both magnitude and direction, plots for their fields
are
usually
much more complicated than for scalar fields. For example, the Cartesian components
of the electric field of the preceding example can be calculated to be
A
vector field
is
typically
field vector at every point in
(2.2)
I
"[
x2
-
y2
-
1
[(x
-
1)2
+
y2][(x
+
1)2
+
y2]
7E0
(2.3)
I.
"[
2XY
7rE0
[(x
-
1)2
+
y2][(x
+
1)2
+
y2]
drawn by constructing lines which are tangent to the
space. By convention,
the
density of these field lines
pf3

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PLOTTING SCALAR AND VECTOR FIELDS^19

~ Electric field lines Equipotentials

Figure 2.1 Equipotentials and Electric Field Lines of Two Parallel Line Charges

Usually we want to construct surfaces of constant CP, which in this case are cylinders

nested around the line charges. Because there is symmetry in the z direction, these

surfaces can be plotted in two dimensions as the dashed, circular contours shown in

Figure 2.1. The centers of these circles are located along the x-axis from 1 < x < 03

for positive values of <P, and from --M < x < - 1 for negative values of CP. CP = 0

lies on the y-axis, which you can think of as a circle of infinite radius with its center at infinity. If the contours have evenly spaced constant values of <P, the regions of highest line density show where the function is most rapidly varying with position.

2.1.2 Plotting Vector Fields

Because vectors have both magnitude and direction, plots for their fields are usually much more complicatedthan for scalar fields. For example, the Cartesian components of the electric field of the preceding example can be calculated to be

A vector field is typically field vector at every point in

(2.2)

"[ I

x2 - y2 - 1 7 E 0 [(x^ -^ 1)2^ +^ y2][(x^ +^ 1)2^ +^ y2]

(2.3)

I.

"[ 2 XY

7rE0 [(x^ -^ 1)2^ +^ y2][(x^ +^ 1)2^ +^ y2]

drawn by constructing lines which are tangent to the space. By convention, the^ density of these field lines

20 DIFFERENTIAL AND INTEGRAL OPERATIONS

indicates the magnitude of the field, while arrows show its direction. If we suppose

an electric field line for Equations 2.2 and 2.3 is given by the equation y = y ( x ) , then

With some work, Equation 2.4 can be integrated to give

x2 + 0 , - c)2 = 1 + 2, (^) (2.5)

where c is the constant of integration. This constant can be varied between --03 and -03 to generate the entire family of field lines. For this case, these lines are circles centered on the y-axis at y = c with radii given by I/=. They are shown as the solid lines in Figure 2.1. The arrows indicate how the field points from the positive to the negative charge. Notice the lines are most densely packed directly between the charges where the electric field is strongest.

2.2 INTEGRALOPERATORS

2.2.1 Integral Operator Notation

The gradient, divergence, and curl operations, which we will review later in this chapter, are naturally in operator form. That is, they can be represented by a symbol that operates on another quantity. For example, the gradient of @ is written as v@. Here the operator is v, which acts on the operand @ to give us the gradient. In contrast, integral operations are comonly not written in operator form. The integral of f ( x ) over x is often expressed as

which is not in operator form because the integral and the operand f(x) are inter- mingled. We can, however, put Equation 2.6 in operator form by reorganizing the terms in this equation:

Now the operator d x acts on f ( x ) to form the integral, just as the v operator acts on @ to form the gradient. In practice, the integral operator is moved to the right, passing through all the terms of the integrand that do not depend on the integration variable. For example,

/ d x x2(x + y ) y 2 = y 2 / d x x2(x + y ). J J