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mathematical_physics_2007_19.pdf, Study Guides, Projects, Research of Mathematical Physics

mathematical_physics_2007_19.pdf

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Pre 2010

Uploaded on 01/19/2023

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40
DIFFERENTIAL AND INTEGRAL
OPERATIONS
which you will prove at the end of the chapter. Write
v
as
(2.100)
-
V=VXA-V@.
Then we can write:
-
v
.v
=
-V2@
-
v
x
v
=
v
x
v
x
K.
ii.v=
ii-
(VXA-ED),
(2.101)
Since the divergence, curl, and normal component are all specified if and
@
are
specified, Helmholtz’s Theorem says
v
is also uniquely specified. Notice the
contribution to
v
that comes from has no divergence since
v
*
(v
X
;Ir>
=
0.
This
is called the rotational or solenoidal part
of
the field and is called the vector
potential. The portion of
X
v@
=
0.
This is called the irrotational part of the field and
@
is
called the scalar potential.
which arises from
@
has
no
curl, because
EXERCISES
FOR
CHAPTEX
2
1.
Consider the two-dimensional scalar potential function
CP(x,y)
=
x3
-
3y2x.
Make a plot
of
the equipotential contours for three positive and three negative
values for
CP.
Find
v@
.
Show that the
v@
field lines are given by setting
3x2y
-
y3
equal to a series
of constants.
Plot six representative
V@
field lines. Be sure to indicate the direction
of
the
field and comment on its magnitude.
Find
V
*
VCP,
the divergence
of
the
v@
vector field, and show that
your
field lines
of
part (d) agree with
this
divergence.
electric dipole
p
is located at the origin
of
a Cartesian system. This dipole
__
creates an electric potential field
@@)
given
by
where
F
is
the position vector,
F
=
ni4.
Let
(a)
Sketch the equipotential lines,
@
=
constant.
(b)
Find the electric field,
a
=
-v@.
(c)
Sketch the electric field lines.
=
p&.
pf3

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40 DIFFERENTIAL AND INTEGRAL OPERATIONS

which you will prove at the end of the chapter. Write v as

V = V X A - V @.

Then we can write:

v. v = -V2@

v x v = v x v x K.

ii.v=i i - ( V X A - E D ) , (2.101)

Since the divergence, curl, and normal component are all specified if and @

are specified, Helmholtz’s Theorem says v is also uniquely specified. Notice the

contribution to v that comes from has no divergence since^ v^ *^ (v^ X^ ;Ir>^ =^ 0. This is called the rotational or solenoidal part of the field and is called the vector

potential. The portion of X v@ = 0.

This is called the irrotational part of the field and @ is called the scalar potential.

which arises from @ has no curl, because

EXERCISES FOR CHAPTEX 2

1. Consider the two-dimensional scalar potential function

CP(x,y) = x3 - 3y2x.

Make a plot of the equipotentialcontours for three positive and three negative

values for CP.

Find v@.

Show that the v@ field lines are given by setting 3x2y - y3 equal to a series

of constants. Plot six representative V@ field lines. Be sure to indicate the direction of the field and comment on its magnitude.

Find V * VCP, the divergence of the v@ vector field, and show that your

field lines of part (d) agree with this divergence.

electric dipole p is located at the origin of a Cartesian system. This dipole

_ _

creates an electric potential field @@) given by

where F is the position vector, F = ni4. Let

(a) Sketch the equipotential lines, @ = constant.

(b) Find the electric field, a = -v@.

(c) Sketch the electric field lines.

= p&.

EXERCISES (^41)

3. Perform the line integral

/ d F X v ,C

where C is the contour shown below

Y

1 C

- 1

and (a) V = v,&,.

(b) v = V&.

(c) v = v,r VOY

(a) 7, (fA)= f ( T - K ) + A. V j.

F 2 T X2 + y 2 + - ,&+

4. Use subscript/summation notation to verify the following identities:

(b) V X v X A = V ( V. - A ; )- V 2 A. (c) v x (fA)= f ( V X A ) + V f X A.

(f) = fVg + gvf.

(g) V(A.B) = A x ( V x B ) + B x ( V X X ) + ( A. V ) B + ( B 3 ) A.

(d) V - ( ( A X B ) = B * ( V X A ) - A * ( T X B ).

(e) A X (VxB) = (VB). A - (A.V)B.

(h) X V , f = 0.

(i) V. (V x A) = O.

5. Calculate the work done by following a straight line path from the Cartesian point (1, 1) to (3,3), if the force exerted is given by

F = (x - y)Cx + (x + y ) $.

Can this force be derived from a scalar potential? Pick any other path that goes from ( 1 , l ) to (3,3) and calculate the work done.