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Midterm Exam 1 - Geometry and Topology. | MATHS 441, Exams of Mathematics

Material Type: Exam; Class: Geometry and Topology.; Subject: MATHEMATICAL SCIENCE; University: Ball State University; Term: Fall 2009;

Typology: Exams

2009/2010

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Midterm Exam I
Part II: TAKE HOME
MATHS 441
Dr. Fischer
Due: September 25, 2009
6. Let X, Y Rn. When you ask four different students as to when a function
f:XYshould be called continuous, you might get four seemingly different
answers. For example:
(i) Audra might say: fis continuous if for every xXand every > 0 there
is a δ > 0 such that d(f(x), f (z)) < whenever zXand d(x, z)< δ”;
(ii) Cameron might say: fis continuous if for every xXand every sequence
(xk) in Xwhich converges to x, the sequence (f(xk)) converges to f(x)”;
(iii) David might say: fis continuous if for every subset CYwhich is
closed in Y, the set {xX|f(x)C}is a closed in X”;
(iv) Jie might say: fis continuous if for every subset UYwhich is open
in Y, the set {xX|f(x)U}is open in X”.
Prove that all of the above statements are in fact equivalent.
7. Let XRn.
Prove that Xis compact if and only if Xis both closed in Rnand bounded.
8. Suppose Xand Yare two compact surfaces. Prove that X#Yis independent
of the direction along which one glues the two boundary circles together.
9. Consider the following compact surfaces, each represented by a plane model.
X:a b1cda1e f1g1e1h1ibd1c1i1f g h
Y:e d e f a1b c1d1f a c1b
Z:bec1d1f g1e1d1a1b f g1c1a1
Find the normal form and the alternative normal form for each of these surfaces.
10. Consider the following cut-and-paste move on a plane model for a surface X,
which has 4 or more edges: Focus on two adjacent edges, say aand b, which
are not being identified. Cut off a triangle, two of whose edges are aand b, and
the third of which is your cut x. Locate the other edge labeled a±1and glue the
triangle back along the two a-edges. Based on this procedure, derive two rules:
(i) If Xis represented by abAaB, then Xis also represented by ...
(ii) If Xis represented by abAa1B, then Xis also represented by ...
Show that, using only “cancellations” and moves of the above type, one can
either transform the plane model into one where all vertices are identified to
one point, or else Xis homeomorphic to S2.
[Hints are attached!]
pf3

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Midterm Exam I

Part II: TAKE HOME

MATHS 441 Dr. Fischer

Due: September 25, 2009

  1. Let X, Y ⊆ Rn. When you ask four different students as to when a function f : X → Y should be called continuous, you might get four seemingly different answers. For example:

(i) Audra might say: “f is continuous if for every x ∈ X and every  > 0 there is a δ > 0 such that d(f (x), f (z)) <  whenever z ∈ X and d(x, z) < δ”; (ii) Cameron might say: “f is continuous if for every x ∈ X and every sequence (xk) in X which converges to x, the sequence (f (xk)) converges to f (x)”; (iii) David might say: “f is continuous if for every subset C ⊆ Y which is closed in Y , the set {x ∈ X | f (x) ∈ C} is a closed in X”; (iv) Jie might say: “f is continuous if for every subset U ⊆ Y which is open in Y , the set {x ∈ X | f (x) ∈ U } is open in X”.

Prove that all of the above statements are in fact equivalent.

  1. Let X ⊆ Rn. Prove that X is compact if and only if X is both closed in Rn^ and bounded.
  2. Suppose X and Y are two compact surfaces. Prove that X#Y is independent of the direction along which one glues the two boundary circles together.
  3. Consider the following compact surfaces, each represented by a plane model.

X : a b−^1 c d a−^1 e f −^1 g−^1 e−^1 h−^1 i b d−^1 c−^1 i−^1 f g h Y : e d e f a−^1 b c−^1 d−^1 f a c−^1 b Z : b e c−^1 d−^1 f g−^1 e−^1 d−^1 a−^1 b f g−^1 c−^1 a−^1

Find the normal form and the alternative normal form for each of these surfaces.

  1. Consider the following cut-and-paste move on a plane model for a surface X, which has 4 or more edges: “Focus on two adjacent edges, say a and b, which are not being identified. Cut off a triangle, two of whose edges are a and b, and the third of which is your cut x. Locate the other edge labeled a±^1 and glue the triangle back along the two a-edges.” Based on this procedure, derive two rules:

(i) If X is represented by abAaB, then X is also represented by ... (ii) If X is represented by abAa−^1 B, then X is also represented by ...

Show that, using only “cancellations” and moves of the above type, one can either transform the plane model into one where all vertices are identified to one point, or else X is homeomorphic to S^2.

[Hints are attached!]

Hints:

  1. Do a tour-de-France-style proof: (i) ⇒ (ii) ⇒ (iii) ⇒ (iv) ⇒ (i).
  2. First explain why X cannot be compact if it is not closed. [Ask yourself: if a sequence (xk) converges to a point x, what convergence statement can you make about any subsequence (x′ k) of the sequence (xk)?] Similarly, explain why X cannot be compact if it is not bounded. Now suppose X is closed and bounded. Let us suppose that n = 2 so that X is a subset of the plane. [The general proof for X ⊆ Rn^ is entirely analogous.] You wish to show that X is compact. To this end, let a sequence (xk) in X be given. It is your goal to extract a subsequence (x′ k) of (xk) which converges to some point x of X. Since X is bounded, you can surround it by a square. If you subdivide this square into four equal squares, then one of these four subsquares must contain infinitely many elements of the sequence (xk) [Why?]. Subdivide this subsquare further and apply the same logic to it. Carefully explain why, as you keep going, you can trace a subsequence of (xk) which converges to some x ∈ R^2. [It might help to look at what is going on in each coordinate separately.] Then explain why x ∈ X.
  3. Let X′^ and Y ′^ denote the surfaces X and Y with the interior of a disk removed, respectively. To prove the assertion it suffices to prove that there is a homeo- morphism h : X′^ → X′^ which reverses the orientation of its boundary circle, so that attaching X′^ to Y ′^ in one direction is the same as attaching it in the other direction. Split your proof into two parts.

(a) Suppose X is non-orientable. Show, using a plane model of the form x 1 x 1 x 2 x 2 · · · xmxm, how the disk that has been removed from X can be isotoped through the surface X and back onto itself while reversing the direction on its boundary circle. Then explain why such an isotopy yields the desired homeomorphism h : X′^ → X′. (b) Suppose X is orientable. Start with a round plane model of the form

x 1 y 1 x− 1 1 y− 1 1 x 2 y 2 x− 2 1 y− 2 1 · · · xnynx− n 1 y− n 1 , which is centered at the origin of R^2. Assume that the disk which has been removed from X is also centered at the origin. Show that one can always strategically place the given edge labels around the plane model so that the function f (x, y) = (x, −y) (which is reflection through the x-axis) yields the desired homeomorphism h : X′^ → X′. Do not reflect the plane model identifications, but only the points of the plane model. Make sure you show that you can arrange the labels so that this reflection takes points, which get glued together, again to points, which get glued together, and that it never glues together any points which were not glued together to begin with. (Draw one picture where n is even, and one where n is odd.)

  1. The normal form of a compact surface is either nT 2 (n > 0) or nP 2 (n > 1), depending on which the surface is homeomorphic to. The alternative normal form is one of nT 2 #S^2 , nT 2 #P 2 , or nT 2 #K^2 with n > 1.