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Mole-Mass Relationships in Chemical Reactions, Study notes of Stoichiometry

One mole of NaCl contains 6.022 x 1023 NaCl formula units. ... Molar mass of NaCl = atomic mass of Na (22.99 amu) + the atomic mass of Cl (35.45 amu) 22.99 ...

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Chapter 3. Stoichiometry: Mole-Mass Relationships in
Chemical Reactions
1
The mole (or mol) represents a certain number of objects.
SI def.: the amount of a substance that contains the same
number of entities as there are atoms in 12 g of carbon-12.
Exactly 12 g of carbon-12 contains 6.022 x 10 23 atoms.
One mole of H 2O molecules
contains 6.022 x 10 23 molecules.
1 mole contains 6.022 x 10 23 entities (Avogadro’s number)
Concept 1. The meaning and usefulness of the mole
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Chapter 3. Stoichiometry: Mole-Mass Relationships in Chemical Reactions

  • The mole (or mol) represents a certain number of objects.
  • SI def.: the amount of a substance that contains the same number of entities as there are atoms in 12 g of carbon-12.
  • Exactly 12 g of carbon-12 contains 6.022 x 10 23 atoms.
  • One mole of H 2 O molecules contains 6.022 x 10 23 molecules.
  • 1 mole contains 6.022 x 10 23 entities (Avogadro’s number)

Concept 1. The meaning and usefulness of the mole

2

  • One mole of NaCl contains 6.022 x 10 23 NaCl formula units.
  • Use the mole quantity to count formulas by weighing them.
  • Mass of a mole of particles = mass of 1 particle x 6.022 x 10^23
  • The mass of an atom in amu is numerically the same as the mass of one mole of atoms of the element in grams.
  • One atom of sulfur has a mass of 32.07 amu; one mole of S atoms has a mass of 32.07 g.

Mass of 1 H atom: 1.008 amu x 1.661 x10-24^ g/amu = 1.674 x10-24^ g

Mass of 1 mole of H atoms: 1.674 x10-24g/H atom x 6.022 x10^23 H atoms = 1.008 g

PT

  • To obtain one mole of copper atoms (6.02 x 10 23 atoms), weigh out 63.55 g copper.

PT

•The molar mass ( M ) of a substance is the mass of one mole of entities (atoms, molecules, or formula units) of the substance.

  • Molar mass has units of grams per mole (g/mol).

Concept 3. The relations among amount of substance (in moles), mass (in grams), and number of chemical entities

Problem : (a) How many grams of silver, Ag, are in 0. mol Ag? (b) How many atoms of Ag are in 0.0342 mol Ag?

7

Plan : (a) To convert moles Ag to grams Ag, use the molar mass of Ag from the periodic table. (b) To convert moles to number of atoms, use Avogadro’s number.

Solution : (a) Converting from moles of Ag to mass:

(b) Converting from moles of Ag to number of atoms:

= 2.06 x 10^22 atoms Ag

PT

Problem : Iron is a most important metal in our society. How many iron atoms are present in a piece of iron weighing 95.8 g?

8

Plan :

Solution : Converting from mass of Fe to moles:

Converting from moles of Fe to number of atoms:

PT

Problem : How many moles and formulas are in 41.6 g ammonium carbonate?

Solution : Calculating molar mass:

Dividing by the mass of one mole of glucose gives the element’s mass fraction; multiplying this fraction by 100% gives the mass percent.

(b) Determining the mass of carbon.

Plan : To find the mass of C in the glucose sample, multiply the mass of the sample by the mass fraction of C from part (a)

Solution :

•A preliminary formula based on the data is Zn (^) 0.21P (^) 0.14O (^) 0..

•Convert the fractional subscripts to whole numbers. :

  1. Divide each subscript by the smallest subscript:
  2. If any subscripts are still not integers, multiply through by the smallest integer that will turn all the subscripts into integers.

The conventional way to write this formula is Zn 3 (PO 4 ) 2 ; the compound is zinc phosphate, a dental cement.

Skill 3-4 : Analysis of a sample of ionic compound gave: 2.82 g Na, 4.35 g Cl, and 7.83 g O. What is the empirical formula and name of the compound? Plan :

Solution : Find moles of elements:

From the moles of each element, construct a preliminary formula and convert to integer subscripts. (^) PT

Molecular Formulas

  • The actual number of moles of each element in the smallest unit of the compound. •In water (H 2 O), ammonia (NH 3 ), methane (CH 4 ), and ionic compounds, the empirical and molecular formulas are identical. •In some cases the molecular formula is a whole-number multiple of the empirical formula.
  • Using the empirical formula to obtain the molecular formula.

Hydrogen peroxide has the empirical formula HO (17.01g/mol) Dividing its molar mass (34.02 g/mol) by the empirical formula mass gives the whole-number multiple:

The molecular formula is H 2 O 2.

Skill 3-5 : Lactic acid ( M = 90.08 g/mol) contains 40.0 mass % C, 6.71 mass % H, and 53.3 mass % O. (a) Determine the empirical formula of lactic acid. (b) Determine the molecular formula.

Plan : Assume 100 g lactic acid to express each mass % as grams. Convert grams to moles and find the empirical formula.

Solution : Express mass % as grams; assume 100 g lactic acid:

Similarly, there are 6.71 g H and 53.3 g O. Converting from grams of elements to moles: