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Momentum vs. Wavevector, Schemes and Mind Maps of Classical Mechanics

Consider a quantum-superposition of two plane-waves: The interference pattern can move! – How does this `wavepacket' then move? ,σ› evolve in time?

Typology: Schemes and Mind Maps

2021/2022

Uploaded on 09/12/2022

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Momentum vs. Wavevector
Instead of momentum, it is often convenient
to use wavevector states:
h
P
K=
kkkK =
)( kkkk
=
δ
π
2
xki
e
kx =
1=
+
kkdk
[ ] iKX =,
[ ] 0, =KP
k=hpp=hk
Wavevector definition:
Important commutators:
Eigenvalue equation:
Relation to momentum eigenstates:
kp
pck h=
=
Normalization
Closure
Wavefunction
pf3
pf4
pf5
pf8
pf9
pfa

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Momentum vs. Wavevector

• Instead of momentum, it is often convenient

to use wavevector states:

h

P

K =

K k = k k

k k ( k k )

ik x

e

x k =

dk k k

[X , K] =i [P , K]= 0

p p p p k k k k k k

h h

h h

∴ k = h p

p = h k

Wavevector definition:

Important commutators:

Eigenvalue equation:

Relation to momentum eigenstates:

p k

k c p

=h

Normalization

Closure

Wavefunction

Wavefunction in K-space

  • What is the wavefunction in K-basis?

( )

( , ) ( )

2

0

2

0

e k k

k t k t e k k

m

k t

i

m

k t

i

= −

= =

δ

ψ ψ

h

h

k

k

ψ( k,t )

Let ψ( 0 ) = k

2

0

( t ) e k

t

M

k

i

h

Then: ψ =

`Motion’ in QM

  • The answer is that in QM motion is in

interference effect

  • Consider a quantum-superposition of two

plane-waves:

  • The interference pattern can move!

= +

− −

0

2

0

2

2

2

1

( )

2

0

2

0

t e k e k

t

M

k

t i

M

k

i

h h

ψ

π π

ψ

2 2

( , )

0

0

0

0

2

2

= +

t

M

k

t i k x

M

k

ik x

e e

x t

h h

= + − t

M

k

k x

2

3

1 cos

2

1 h

π

This is a moving

`standing wave’

= − t

M

k

k x

2

3

2

1

cos

1

h

π

= + +

2 2

1

2

1

( , )

0

0

0

0

t

M

k

t i k x

M

k

i k x

e e

x t

h h

π

ψ

Wavepacket formation

  • Measurement of position must produce a

`localized’ state

  • How does this `wavepacket’ then move?

Physical versus non-physical states:

  • States like |x

〉 and |k

〉 have 〈 ψ| ψ〉= ∞

  • All physical states must have 〈 ψ| ψ〉= 1
  • CONCLUSION 1: states such as |x

〉 and |k

are non-physical, and can therefore only be

used as intermediate states in calculations

  • CONCLUSION 2: Since a measurement of X

produces the nonphysical state |x

〉, such a

measurement must be impossible

  • However, real detectors have finite resolution
    • call the resolution σ
    • Result of measurement is therefore:
    • After measurement, state vector is projected

onto this subspace, as

  • This state will be a `wavepacket’ with width σ

= ± σ

0

x x

ψ ψ

σ

σ

dx x x

x

x

=

0

0

Phase and Group Velocities

  • We can see that the phase velocity is
  • What does the probability density look like?
  • We see that the center of the wavepacket

moves at the velocity

  • We call this the `group velocity’
  • We can see that the group velocity correlates

with the velocity of a classical particle having

the same momentum

m

p

v

p

2

=

( )

( )

( )

2

2

2

0

( )

1

( , )

t

x x t

e

t

x t

σ

π σ

ψ

=

t

m

p

x t x

( )= +

( ) 1

= +

σ

σ σ

m

t

t

h

m

p

v

g

=

ψ( x , t ) = π σ +

i h t

m σ

e

x

p

0

t

m

x

0

2

2 σ

2

i h t

m σ

2

  • i

p

0

x

p

0

t

2 m

h

Wavepacket Spreading

  • The width of the Gaussian wavepacket is:
  • Thus the timescale for wavepacket spreading is:
    • For t << t

s

we can ignore spreading

  • For t >>t

s

the size of the wavepacket grows

linearly in time:

  • Thus `spreading’ at the velocity:
  • The smaller the wavepacket, the faster it will

spread!

( ) 1

= +

σ

σ σ

m

t

t

h

σ( t ) ≈ σ

h

m σ

t

s

=

t

m

t

σ

σ

h

( ) ≈

m σ

v

s

h

=

t

Δx

t=t

s

Δx = v

s

t

Δx = σ

( )

( ) 1 /

s

σ t = σ + t t

Wavepacket for a Baseball

  • Here we have m = 1 kg
    • Let us still consider the center-of-mass of the electron

to be localized by neutron diffraction to .1 nanometer

  • So the wavepacket will only start spreading after

10

14

s = 30 million years

  • After which it will start to spread at a rate of 10

m/s.

  • In another 30 million years, it will have doubled in

size

  • Note: the age of the universe is 13 billion years
  • In that time it will have reached 10 nm.
  • So classical mechanics (i.e. well-

defined/deterministic position and momentum)

should do pretty well

s

kgm s

m kg m

t

s

10

10

1 10

=

= =

h

σ

s

m

kg m

kgm s

m

v

s

10

1 10

10

=

= =

σ

h 1 nm

300 million years