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Chem 101 Quiz 4: Resonance & Lewis Dot Structures, Geometric Shapes, Schemes and Mind Maps of Chemistry

A quiz from a chemistry 101 class, consisting of three parts. In the first part, students are required to draw three resonance structures for the cyanate and fulminate ions, and assign formal charges to each atom. In the second part, students are introduced to new elements named after famous singers and are asked to determine their lewis dot structures and geometric shapes. In the third part, students are given bond energy data and are required to calculate the ∆ho for a given reaction.

Typology: Schemes and Mind Maps

2021/2022

Uploaded on 09/12/2022

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NAME: _________________________________ Form 2 (yellow)
November 26, 2001 QUIZ #4 CHEM 101
1) The cyanate ion NCO-, has the least electronegative atom carbon in the center. The very
unstable fulminate ion, CNO-, has the nitrogen in the center.
a) Draw three resonance Lewis dot structures for each ion and assign formal charge to
each atom. (Use back if necessary).
cyanate:
N C O
.. ..
+1
[]
..
..
-2
N C O
.. ..
..
0
[]
..
-1
0- 0-
N C O
.. ..
-1
[]
..
..
00-
fulminate:
C N O
.. ..
+1
[]
..
..
-3
C N O
.. ..
..
+1
[]
..
-2
+1 - 0-
C N O
.. ..
-1
[]
..
..
-1 +1 -
b) On the basis of formal charge and electronegativity circle the resonance structure which
is the most reasonable.
2) Some new elements have been discovered in my laboratory so I am naming them after myself.
Here are the names and some properties of the elements:
New Element Number of valence electrons Element always obeys
octet rule
Rt = Robertium 4 Yes
Mc = McCreadyium 6 No
Bn = Bowmanium 7 Yes
We have also discovered some new molecules. It is your job to determine the Lewis dot
structures and geometric structures of these new molecules using the information in the table.
a) RtBn4
Hybridization around central atom: ___sp3__ Shape: tetrahedral_
b) McBn2 Hybridization around central atom: __sp3___ Shape: bent
c) McBn4 Hybridization around central atom: __dsp3__ Shape: sawhorse
3) Given the bond energy data on the board, calculate the Horxn for the following reaction.
CH4(g) + 2H2O(g) ! CO2(g) + 4H2(g)
Horxn = 4(D of C-H) + 4(D of O-H) – 2(D of C=O) - 4(D of H-H)
= 4(413 kJ) + 4(467 kJ) - 2(799 kJ) - 4(432 kJ) = 194 kJ
Rt Bn
Bn
..
..
..
SN = 4
LP = 0
Bn
..
..
.. ..
..
..
Bn
..
..
..
Mc
..
Bn
Bn
Bn
..
..
..
..
..
.. ....
..
Bn
..
..
..
SN = 5
LP = 1
Mc BnBn
..
..
..
.. ..
..
SN = 4
LP = 2
..
..
pf2

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NAME: _________________________________ Form 2 (yellow) November 26, 2001 QUIZ #4 CHEM 101

  1. The cyanate ion NCO-, has the least electronegative atom carbon in the center. The very unstable fulminate ion, CNO - , has the nitrogen in the center. a) Draw three resonance Lewis dot structures for each ion and assign formal charge to each atom. (Use back if necessary). cyanate:
N C O

[ ]

.. ..^ -

N C O

0 [ ]

N C O

[ ]

0 0 -

fulminate:

C N O

[ ]

.. ..^ -

C N O

+ [ ]

C N O

[ ]

-1 +1 -

b) On the basis of formal charge and electronegativity circle the resonance structure which is the most reasonable.

  1. Some new elements have been discovered in my laboratory so I am naming them after myself. Here are the names and some properties of the elements: New Element Number of valence electrons Element always obeys octet rule Rt = Robertium 4 Yes Mc = McCreadyium 6 No Bn = Bowmanium 7 Yes We have also discovered some new molecules. It is your job to determine the Lewis dot structures and geometric structures of these new molecules using the information in the table. a) RtBn (^4)

Hybridization around central atom: __sp^3 __ Shape: tetrahedral

b) McBn Hybridization around central atom: __sp^3 ___ Shape: bent

c) McBn (^4) Hybridization around central atom: __dsp^3 __ Shape: sawhorse

  1. Given the bond energy data on the board, calculate the ∆Horxn for the following reaction.

CH 4 (g) + 2H 2 O(g)! CO 2 (g) + 4H 2 (g)

∆Horxn = 4(D of C-H) + 4(D of O-H) – 2(D of C=O) - 4(D of H-H) = 4(413 kJ) + 4(467 kJ) - 2(799 kJ) - 4(432 kJ) = 194 kJ

Rt Bn Bn

SN = 4 Bn LP = 0

.. ....^

Bn

Mc

Bn Bn

Bn

Bn

SN = 5 LP = 1

Bn Mc Bn

.. SN = 4

.. LP = 2

NAME: _________________________________ Form 2 (yellow) November 26, 2001 QUIZ #4 CHEM 101

  1. The cyanate ion NCO-, has the least electronegative atom carbon in the center. The very unstable fulminate ion, CNO - , has the nitrogen in the center. a) Draw three resonance Lewis dot structures for each ion and assign formal charge to each atom. (Use back if necessary) cyanate:
N C O

[ ]

.. ..^ -

N C O

0

[ ]

N C O

[ ]

0 0 -

fulminate:

C N O

[ ]

.. ..^ -

C N O

+

[ ]

C N O

[ ]

-1 +1 -

b) On the basis of formal charge and electronegativity circle the resonance structure which is the most reasonable.

  1. Some new elements have been discovered in my laboratory so I am naming them after one of my favorite singers. Here are the names and some properties of the elements: New Element Number of valence electrons Element always obeys octet rule El = Elvisium 4 Yes An = Aaronium 5 No Py = Presleyium 7 Yes We have also discovered some new molecules. It is your job to determine the Lewis dot structures and geometric structures of these new molecules using the information in the table. a) ElPy 4 Hybridization around central atom: __sp^3 __ Shape: tetrahedral

b) AnPy 3 Hybridization around central atom: __sp^3 __Shape: trigonal pyramidal

c) [AnPy 4 ] - Hybridization around central atom: __dsp^3 __ Shape: sawhorse

  1. Given the bond energy data on the board, calculate the ∆Horxn for the following reaction.

CH 4 (g) + 2H 2 O(g)! CO 2 (g) + 4H 2 (g)

∆Horxn = 4(D of C-H) + 4(D of O-H) – 2(D of C=O) - 4(D of H-H) = 4(413 kJ) + 4(467 kJ) - 2(799 kJ) - 4(432 kJ) = 194 kJ

El Py Py

SN = 4 Py LP = 0

.. ....^

Py

An Bn Bn

SN = 4 Bn LP = 1

.. ....^

An

Py Py

Py

Py

SN = 5

[ ] LP = 1