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Net Ionic Equations, Lecture notes of Chemistry

A net ionic equation shows only the reacting species in a chemical reaction, and does not include spectator ions. Assume that all reactions take.

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2021/2022

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Types of Chemical Equations
For the reaction between each of the following substances, first draw an ion box and
find the products of these double replacement reactions. Then, write a balanced
chemical equation, showing all species present as well as their states. Use your data
booklet on page 4 to find out which species is aqueous or insoluble. Finally, write a
balanced net ionic equation. A net ionic equation shows only the reacting species in a
chemical reaction, and does not include spectator ions. Assume that all reactions take
place in water and that all reacting substances are ionic.
1. Sodium hydroxide and iron (III) chloride
Ion Box
Cation
Anion
Products
Na+
OH-
NaCl (aq)
Fe3+
Cl-
Fe(OH)3(s)
Balanced chemical equation:
3NaOH(aq) + FeCl3(aq) 3NaCl(aq) + Fe(OH)3(s)
Complete ionic equation: Aqueous solutions break into anions and cations
3Na+(aq) + 3OH-(aq) + Fe3+(aq) + 3Cl-(aq) 3Na+(aq) +3Cl-(aq) + Fe(OH)3(s)
Net Ionic equation: Remove spectator ions
3OH-(aq) + Fe3+(aq) Fe(OH)3(s)
Spectator ions: Na+, Cl-
2. Potassium sulphide and copper (II) nitrate
Ion Box
Cation
Anion
Products
K+
S 2-
KNO3(aq)
Cu2+
NO3-
CuS(s)
Balanced chemical equation:
K2S(aq) + Cu(NO3)2(aq) 2KNO3(aq) + CuS(s)
Complete ionic equation:
2K+(aq) + S2-(aq) + Cu2+(aq) + 2NO3-(aq) 2K+(aq) + 2NO3-(aq) + CuS(s)
Net ionic equation:
S2-(aq) + Cu2+(aq) CuS(s)
Spectator ions: K+, NO3-
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Types of Chemical Equations For the reaction between each of the following substances, first draw an ion box and find the products of these double replacement reactions. Then, write a balanced chemical equation, showing all species present as well as their states. Use your data booklet on page 4 to find out which species is aqueous or insoluble. Finally, write a balanced net ionic equation. A net ionic equation shows only the reacting species in a chemical reaction, and does not include spectator ions. Assume that all reactions take place in water and that all reacting substances are ionic.

  1. Sodium hydroxide and iron (III) chloride  Ion Box Cation Anion Products

Na +^ OH -^ NaCl (aq)

Fe 3+^ Cl -^ Fe(OH) 3 (s)

Balanced chemical equation: 3NaOH(aq) + FeCl 3 (aq)  3NaCl(aq) + Fe(OH) 3 (s) Complete ionic equation: Aqueous solutions break into anions and cations 3Na+(aq) + 3OH-(aq) + Fe3+(aq) + 3 Cl-(aq)  3Na+(aq) +3Cl-(aq) + Fe(OH) 3 (s) Net Ionic equation: Remove spectator ions 3OH-(aq) + Fe3+(aq)  Fe(OH) 3 (s) Spectator ions: Na+, Cl-

  1. Potassium sulphide and copper (II) nitrate  Ion Box Cation Anion Products K +^ S^ 2 - (^) KNO 3 (aq) Cu2+^ NO 3 -^ CuS(s) Balanced chemical equation: K 2 S(aq) + Cu(NO 3 ) 2 (aq)  2KNO 3 (aq) + CuS(s) Complete ionic equation: 2K+(aq) + S^2 - (aq) + Cu2+(aq) + 2NO 3 - (aq)  2K+(aq) + 2NO 3 - (aq) + CuS(s) Net ionic equation: S^2 - (aq) + Cu2+(aq)  CuS(s) Spectator ions: K+, NO 3 -
  1. Ammonium sulphate and barium chloride  Ion Box Cation Anion Products NH 4 +^ SO^4 2 - (^) NH 4 Cl(aq) Ba2+ Cl - BaSO 4 (s) Balanced chemical equation: (NH 4 ) 2 SO 4 (aq) + BaCl 2 (aq)  2NH 4 Cl(aq) + BaSO 4 (s) Complete ionic equation: 2 NH 4 +-(aq) + SO 42 - (aq) + Ba2+(aq) + 2 Cl - (aq)  2NH 4 +(aq) + 2Cl-(aq) +BaSO 4 (s) Net Ionic equation: SO 42 - (aq) + Ba2+(aq)  BaSO 4 (s) Spectator ions: NH 4 +^ and Cl-
  2. Lithium phosphate and calcium bromide  Ion Box Cation Anion Products Li+^ PO 43 -^ LiBr(aq) Ca2+^ Br-^ Ca 3 (PO 4 ) 2 (s) Balanced chemical equation: 2Li 3 PO 4 (aq) +3CaBr 2 (aq)  6LiBr(aq) + Ca 3 (PO 4 ) 2 (s) Complete ionic equation: 6Li+^ (aq) + 2PO 43 - (aq) +3Ca2+(aq) +6Br-(aq)  6Li+(aq) + 6Br-(aq) + Ca 3 (PO 4 ) 2 (s) Net Ionic equation: 2PO 43 - (aq) +3Ca2+(aq)  Ca 3 (PO 4 ) 2 (s) Spectator ions: Li+, Br-
  3. Silver nitrate and sodium sulphide Ion Box Cation Anion Products Ag+^ NO 3 -^ NaNO 3 (aq) Na+^ S^2 -^ Ag 2 S(s) Balanced chemical equation: 2AgNO 3 (aq) + Na 2 S(aq)  2NaNO 3 (aq) + Ag 2 S(s) Complete ionic equation: 2Ag+(aq) + 2NO 3 - (aq) + 2 Na+(aq) +S^2 - (aq)  2 Na+(aq) + 2NO 3 - (aq) + Ag 2 S(s)
  1. Potassium carbonate and strontium nitrate  Ion Box Cation Anion Products K+^ CO 32 -^ KNO 3 (aq) Sr2+^ NO 3 -^ SrCO 3 (s) Balanced chemical equation: K 2 CO 3 (aq) + Sr(NO 3 ) 2 (aq)  2KNO 3 (aq) + SrCO 3 (s) Complete ionic equation: 2K+(aq) + CO 32 - (aq) + Sr2+(aq) + 2NO 3 - (aq)  2K+(aq) + 2NO 3 - (aq) + SrCO 3 (s) Net Ionic equation: CO 32 - (aq) + Sr2+(aq)  SrCO 3 (s) Spectator ions: K+^ and NO 3 -