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Instructions on how to determine the equation of oblique asymptotes for given functions using long division. It includes examples of functions with oblique asymptotes and their corresponding graphs. The document also explains the concept of vertical and x-intercepts and their significance in graphing functions.
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MHF4U: Advanced Functions
J. Garvin
Slide 1/
In addition to horizontal and vertical asymptotes, a function may have oblique asymptotes. Oblique asymptotes are sometimes called โslantโ asymptotes because they have the form y = ax + b, where a 6 = 0. A function will have an oblique asymptote if the degree of the numerator is one greater than that of the denominator. A function will never have both oblique and horizontal asymptotes.
J. Garvin โ Oblique AsymptotesSlide 2/
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Example Determine the equation of the oblique asymptote for f (x) = x
x , and graph the function.
Use long division to determine the equation of the oblique asymptote.
x x)^ x^2 โ 1 โ x^2
The equation of the oblique asymptote is y = x. J. Garvin โ Oblique AsymptotesSlide 3/
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There is a vertical asymptote at x = 0, as given by the denominator. There is no f (x)-intercept, since setting x = 0 causes a division by zero error. Since x^2 โ 1 is a difference of squares, f (x) has x-intercepts at ยฑ1. These points, along with the asymptotes, give us enough information to accurately sketch the graph, but we can test values of x close to the vertical asymptote to get a better picture. As x โ 0 from the left, f (x) โ โ, and as x โ 0 from the right, f (x) โ โโ.
J. Garvin โ Oblique AsymptotesSlide 4/
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Example Graph f (x) = x
(^2) + 2x โ 3 x + 1.
x + 1 x + 1
x^2 + 2x โ 3 โ x^2 โ x x โ 3 โ x โ 1 โ 4
There is an oblique asymptote with equation y = x + 1.
There is a vertical asymptote at x = โ1, since the denominator is zero when x = โ1. Setting x = 0 gives an f (x)-intercept of โ3.
Since f (x) factors as f (x) = (x^ โ x^ 1)( + 1x^ + 3) , there are x-intercepts at 1 and โ3. As x โ 0 โ, f (x) โ โ, and as x โ 0 +, f (x) โ โโ. In the notation above, x โ kโ^ means โas x approaches k from the leftโ, while x โ k+^ is from the right.
J. Garvin โ Oblique AsymptotesSlide 7/
J. Garvin โ Oblique AsymptotesSlide 8/
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Example
Graph f (x) = x
(^2) + 2x x + 2.
In this case, note that f (x) = x( xx + 2+ 2) = x, where x 6 = โ2.
Thus, the graph of f (x) is the same as the graph of y = x, but with a point discontinuity at x = โ2. It is generally a good idea to check for the same root in both the numerator and denominator before doing any extra work.
J. Garvin โ Oblique AsymptotesSlide 9/
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J. Garvin โ Oblique AsymptotesSlide 10/
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A More Complex Example
Graph f (x) = x
(^3) โ 2 x (^2) โ x + 2 x^2 โ x โ 6.
Let f (x) = g h^ ((xx)).
By the FT, g (1) = g (2) = g (โ1) = 0, and h(โ2) = h(3) = 0.
Therefore, f (x) = (x^ โ(x^ 1)( + 2)(x^ โ^ x2)( โx 3)^ + 1).
There are vertical asymptotes at x = โ2 and x = 3. The x-intercepts are at 1, 2 and โ1. The f (x)-intercept is at โ 13.
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Use long division to determine the equation of the oblique asymptote. x โ 1 x^2 โ x โ 6 )^ x^3 โ 2 x^2 โ x + 2 โ x^3 + x^2 + 6x โ x^2 + 5x + 2 x^2 โ x โ 6 4 x โ 4 There is an oblique asymptote with equation y = x โ 1.