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A comprehensive set of review questions and answers for the abo-m master in ophthalmic optics certification exam. It covers key concepts in ophthalmic optics, including optical centers, surface types, toric surfaces, dioptric midpoints, and lens power calculations. Designed to help students prepare for the exam and achieve a passing score.
Typology: Exams
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Course Title and Number: (ABO-M) Ophthalmic Optics Certification Exam Title: ABO-M Certification Exam Exam Date: Exam 2025- 2026 Instructor: ____ [Insert Instructor’s Name] _______ Student Name: ___ [Insert Student’s Name] _____ Student ID: ____ [Insert Student ID] _____________
Ophthalmic Optics 1 - Exam 1 Review Questions and Answers | 100% Pass Guaranteed | Graded A+ | 2025- ABO-M Master in Ophthalmic Optics Certification Exam ABO American Board of Opticianry Read All Instructions Carefully and Answer All the Questions Correctly Good Luck: -
Reference Point
an axis that lies in the (same/different) plane but (does/doesn't) pass through the center of curvature of the arc.: same, doesn't. I.e. take a cross section of the lens perpendicular along the axis.
both front and back surfaces will have a true optical axis: F. Only 1 line can be normal. Otherwise its plano.
value calculated?: It is the spherical equivalent of the CLC. SE = sph + cylinder/
they?: Verticies. Points on front and back that line with optical axis Need Writing 🤔Help? We've Got You Covered! ✍ 100% NO A I or Plagiarism Guaranteed🤔 Ctrl + Click Here To 📑ORDER NOW 📑 Follow Link 🤔 ORDER NOW 🤔 🎓 TO GET INSTANT EXPERT HELP 🎓 🤔 ORDER NOW 🤔
back surface. Will this reduce or increase meridonial mag?: Minus. Reduce.
image sizes in each eye.: Plus.
Re-write in cross cyl form:: +1.00 x 180/+2.00 x 090 +1.00@090/+2.00@
obliquely crossed cylinders (OCC's) with equal powers are superimposed?: Halfway between the two.
in axis meridian?: +4.00D -> the meridian that is most plus / least neg is the axis meridian. The power meridian is the meridian with cyl.
of a refractive surface?:
a -3.00 D cylinder axis 090°. (NOT THE RESULTING POWER CROSS!): -5.00 -3.00 x 090
Where will the glasses be the thickest?: Lateral: Temporal Vertical: ???
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Front
surfaces on front?: Plus
the BC be located?: On the side containing the segment.
is to be ground in plus cylinder form, what front and back curves would be used if a base curve of +6.00D was chosen? Assume +6.00 @ 90 for the surface containing toricity to start with.:
base curve of +5.00D and is ground in minus cylinder form, what front and back curves would be used?:
specifically designed to minimize which 2 aberrations?: Oblique astigmatism & Curvature of field.
when Rxing?: Ordering replace- ments. Ordering duplicates.
BC's when Rxing?: 1. To match BC in previous Rx. 2. To reduce ghosting and reflections. 3. To get a flatter thinner lens. 4. To avoid lash crash. Need Writing 🤔Help? We've Got You Covered! ✍ 100% NO A I or Plagiarism Guaranteed🤔
power of the lens?: Different materials have different indices.
power of a lens, based on a lens clock reading?:
lens clock reads falsely high or low?: >1 = falsely low.
lens clock reads falsely high or low?: < 1 = falsely high
the lens being measured has an index, n=1.523. The lens clock dial reads +5.00D when the curvature of the front surface of the lens is measured. What is the true power of the front surface?: Conversion factor: 0.53/0.523 = 0. F true = 5.00(0.986) = +4.93D
Front
power?: Back. Front power is only measured with high plus or multifocals.
system of a lensometer, and what kind of telescope does it use?: 1. The ocular+objective eyepieces (Keplari- an). 2. The reticle Need Writing 🤔Help? We've Got You Covered! ✍ 100% NO A I or Plagiarism Guaranteed🤔
a sph-cyl lens with a lensometer?: The skinny lines. (sph surface power)
amount of target movement when performing lensometry?:
far does the target move in measuring a +1.00 D lens?: (0.05 x 0.05) x 1.00 = 2.5mm Calculate focal length of 20D lens, square it, and then multiply by Fv
How far does the target move if the power drum moves from +20D to -20D reading?: fs = 1/20 = 0.05m Fv = 40D (0.05 x 0.05) x 40 = 100mm
How far does the target move between the two meridians if the std. lens is +25 D?: fs = 1/25 = 0. Fv = 6D (0.04 x 0.04) x (6) = 9.6mm
line focuses 5 mm behind the plano position. The triple line focuses 6.25 mm in front of the plano position. The axis indicator reads 45° What is the Rx?: Behind plano: use (-) value In front of plano: use (+) value Solve for Fv in two parts: Sph: (+0.00625)/(0.05 x 0.05) = Fv -> +2.50D Cyl: (-0.005)/(0.05 x 0.05) = Fv -> -2.00D Need Writing 🤔Help? We've Got You Covered! ✍ 100% NO A I or Plagiarism Guaranteed🤔
determined by measuring the difference between what 2 factors?: Difference in power between the distance carrier and the segment.
are spherical only!
Axis wheel is set at 045 degrees The sphere reading is - 2.00D The cylinder reading is +2.50 D What is Rx in minus cyl?: +2.50 -4.50 x 045 Shelby! Is this correct?
index = softer lens and vice versa
index = lower abbey value (more chromatic dispersion)
The higher the number, the less dispersion
Higher index = more reflection
lens:: P = 100g ( n -1 ) / d
ET - s Pl on one surface: CT = s1 + ET
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