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Chem 1075 Chapter 17: Oxidation and Reduction Reactions - Prof. Beverly A. Kelley, Assignments of Chemistry

A study guide for chem 1075, chapter 17, focusing on oxidation and reduction reactions. It includes learning goals, suggested homework exercises, and answers. Students will learn to assign oxidation numbers, identify what is being oxidized or reduced, and determine oxidizing and reducing agents. The document also includes extra practice problems.

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Pre 2010

Uploaded on 08/16/2009

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Chem 1075 Chapter 17 Oxidation and Reduction Learning Goals / Study Guide
Suggested Homework:
Key Concepts (p. 487): 1, 2, 3 (Answers in Appendix H)
Exercises (p. 488): 1, 3, 5, 7, 9, 11, 13, 15, 17, 63
Learning Goals:
1. Be able to assign oxidation numbers to elements, ions, atoms in compounds, atoms in polyatomic ions.
2. Be able to determine what is being oxidized or reduced in a redox reaction.
3. Be able to determine the oxidizing agent and reducing agent for a redox reaction.
4. OMIT Sec. 17.3, 17.4 Balancing redox reactions
5. OMIT Sec. 17. 5 Spontaneous reactions
6. OMIT Sec. 17.6, 17.7 Electrolytic & Voltaic cells
Extra Practice:
1. Assign the oxidation numbers to each atom in the following reaction:
Cl2(g) + 2 NaF(s) —> 2 NaCl(aq) + F2(g)
2. Determine what is being oxidized: _________ is being oxidized from _____ to _____
3. Determine what is being reduced: __________is being reduced from _____ to _____
4. The oxidizing agent would be ______________
5. The reducing agent would be ______________
6. The oxidation number for Br would be greatest in which formula?
HBrO2HBrO HBrO3HBrO4
7. Calculate the oxidation number on S in S4O62-.
Answers: 1. Cl2 = 0, NaF has Na+ and F1-, NaCl has Na1+ and Cl1-, F2 = 0; 2. F1- is being oxidized from 1- to
0; 3. Cl2 is being reduced from 0 to -1; 4. The oxid agent is Cl2; 5. The red agent is F1- or NaF; 6. HBrO2
has
Br=+3; HbrO has Br=+1; HBrO3 has Br=+5; HBrO4 has Br=+7; 7. S = +5/2 or 2.5 (can have some
fractional oxidation number)
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Chem 1075 Chapter 17 Oxidation and Reduction Learning Goals / Study Guide

Suggested Homework:

Key Concepts (p. 487): 1, 2, 3 (Answers in Appendix H) Exercises (p. 488): 1, 3, 5, 7, 9, 11, 13, 15, 17, 63

Learning Goals:

  1. Be able to assign oxidation numbers to elements, ions, atoms in compounds, atoms in polyatomic ions.
  2. Be able to determine what is being oxidized or reduced in a redox reaction.
  3. Be able to determine the oxidizing agent and reducing agent for a redox reaction.
  4. OMIT Sec. 17.3, 17.4 Balancing redox reactions
  5. OMIT Sec. 17. 5 Spontaneous reactions
  6. OMIT Sec. 17.6, 17.7 Electrolytic & Voltaic cells

Extra Practice:

  1. Assign the oxidation numbers to each atom in the following reaction:

Cl 2 (g) + 2 NaF(s) —> 2 NaCl(aq) + F 2 (g)

  1. Determine what is being oxidized: _________ is being oxidized from _____ to _____
  2. Determine what is being reduced: __________is being reduced from _____ to _____
  3. The oxidizing agent would be ______________
  4. The reducing agent would be ______________
  5. The oxidation number for Br would be greatest in which formula?

HBrO 2 HBrO HBrO 3 HBrO 4

  1. Calculate the oxidation number on S in S 4 O 6 2-.

Answers: 1. Cl 2 = 0, NaF has Na+^ and F1-, NaCl has Na1+^ and Cl1-, F 2 = 0; 2. F1-^ is being oxidized from 1- to 0; 3. Cl 2 is being reduced from 0 to -1; 4. The oxid agent is Cl 2 ; 5. The red agent is F1-^ or NaF; 6. HBrO 2 has Br=+3; HbrO has Br=+1; HBrO 3 has Br=+5; HBrO 4 has Br=+7; 7. S = +5/2 or 2.5 (can have some fractional oxidation number)

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