Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Oxidation and Reduction Reactions: Understanding Oxidation Numbers and Half Reactions, Lecture notes of Chemical Principles

A study resource for understanding oxidation and reduction reactions, focusing on the concept of oxidation numbers and how to write half reactions. It includes examples and exercises for practicing these concepts.

What you will learn

  • How are oxidation numbers assigned to elements?
  • What is the difference between oxidation and reduction reactions?
  • How do you write half reactions for oxidation and reduction?
  • What is the role of oxidizing and reducing agents in redox reactions?
  • What are the rules for calculating oxidation numbers?

Typology: Lecture notes

2021/2022

Uploaded on 09/12/2022

amlay
amlay 🇺🇸

4.1

(19)

384 documents

1 / 15

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Page 1 of 15 Alscher
Oxidation and Reduction Reactions Workbook
Reference sheets:
The activity series of common metals
Calculating oxidation numbers
Work sheets
1. Oxidation, Reduction, Agents, & Reactions. WS 1
2. Oxidation Numbers Spontaneous Reactions WS 2
3. Oxidation Numbers, Application to Reactions. WS 3
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff

Partial preview of the text

Download Oxidation and Reduction Reactions: Understanding Oxidation Numbers and Half Reactions and more Lecture notes Chemical Principles in PDF only on Docsity!

Oxidation and Reduction Reactions Workbook

Reference sheets:

The activity series of common metals

Calculating oxidation numbers

Work sheets

  1. Oxidation, Reduction, Agents, & Reactions. WS 1
  2. Oxidation Numbers Spontaneous Reactions WS 2
  3. Oxidation Numbers, Application to Reactions. WS 3

The activity series of common metals

Activity series of elements

elements

Lithium Li ®

Li

  • e-

Potassium K ®

K

  • e-

Barium Ba ®

Ba

2+

  • 2e-

Calcium Ca ®

Ca

2+

  • 2e-

Sodium Na ®

Na

  • e-

Magnesium Mg ®

Mg

2+

  • 2e-

Aluminum Al ®

Al

2+

  • 3e-

Manganese Mn ®

Mn

2+

  • 2e-

Zinc Zn ®

Zn

2+

  • 2e-

Chromium Cr ®

Cr

2+

  • 3e-

Iron Fe ®

Fe

2+

  • 2e-

Cobalt Co ®

Co

2+

  • 2e-

Nickel Ni ®

Ni

2+

  • 2e-

Tin Sn ®

Sn

2+

  • 2e-

Lead Pb ®

Pb

2+

  • 2e-

HYDROGEN H

2H

  • 2e-

Copper Cu ®

Cu

2+

  • 2e-

Mercury 2Hg ®

Hg

2

2+

  • 2e-

Silver Ag ®

Ag

  • e-

Mercury Hg ®

Hg

2+

  • 2e-

Platinum Pt ®

Pt

2+

  • 2e-

Gold Au ®

Au

3+

  • 3e-
  • Elements that lie near the top of the list are referred to as active metals.
  • Elements that lie near the bottom of the activity series are very stable and form compounds less readily.

Notice, also, that the transition elements from groups 8B to 1B are near the bottom of the list. The alkali

and alkaline earth metals are at the top. They are most easily oxidized.

  • Any metal on the list can be oxidized by the ions of elements below it. Example: Copper is above silver

in the series. Cu metal can be oxidized by Ag+ to give silver metal and copper ions.

  • The following react vigorously with acidic solutions to give hydrogen gas and cations of the metals, and

hydroxide: Li, K, Ba, Ca, Na.

  • The following react vigorously with water to give hydrogen gas and cations of the metals, and hydroxide:

Li, K, Ba, Ca, Na.

  • The following react with acid to give hydrogen gas and cations of the metal, but not vigorously: Mg, Al,

Zn, Cr, Fe, Cd, Co, Ni, Sn, Pb.

  • The following react slowly with water but readily with steam to give hydrogen gas and cations: Mg, Al,

Zn, Cr, Fe, Cd.

  • The following do not react with acids (HCl, HBr, HI) to give hydrogen: Cu, Hg, Ag, Au, Pt.

Representative elements (The A’s)

  1. Column IA (1) +1 (Except H with a metal, then H = - 1)
  2. Column IIA (2) +
  3. Column IIIA (13) +3 (Normally, however +1 possible near the bottom of the table)
  4. Column IVA (14) +4 to - 4
  5. Column VA (15) +5 to - 3
  6. Column VIA (16) +6 to - 2 (Oxygen is - 2 except when combined with F, or in O 2

or O 2

2 -

  1. Column VIIA (17) +7 to - 1 (Fluorine is - 1 in compounds)
  2. Column VIIIA (18) +8 to 0 (Usually only 0)

Transition elements (The B’s)

Transition Metals IIIB-IIB (3-12). If the B designation is used the values may range from +2 to

the group number. If the other designation is used, the values may range from +2 to the group

number for columns 3-8 and to the group number minus 10 for groups 11 and 12 (treat columns 9

and 10 as if they were 7 and 6 respectively). Exceptions: Hg 2

2+

(Hg = +1) and Au

3+

(Au = +3).

When an element may have a positive or negative oxidation number, it will normally be negative

if it is to the upper right, on the Periodic Table, with respect to the other elements in the compound

or ion.

When it is negative, under these circumstances, it will probably have the most negative of the

possible values noted in the rules above. Note that in Special Rules 4-8 the range of possible values

is always eight. With these elements, the

more probable oxidation states may be determined by counting from highest to lowest by twos.

Worksheet #1 Writing half reactions

  1. Define each: Remember “Oil Rig”: Oxidation is loss (of e

)reduction is gain (of e

a) Oxidation

b) Reduction

c) Oxidizing agent

d) Reducing agent

  1. Write half reactions for each of the following atoms or ions. Label each as oxidation or

reduction. Use the Activity Series Chart.

a) Al

b) Ba

2+

c) Br 2

d) Ca

e) Ga

3+

f) H 2

g) H

Worksheet #2 Finding oxidation numbers

  1. Determine the Oxidation Number of each of the elements that is underlined.

a) NH 3

_____ b) H 2

SO

4

_____

c) ZnSO 3

_____ d) Al(OH) 3

_____

e) Na _____ f) Cl 2

_____

g) AgNO 3

_____ h) ClO 4

_____

i) SO 2

_____ j) K 2

Cr 2

O

4

_____

k) Ca(ClO 3

2

_____ l) K 2

Cr 2

O

7

_____

m) HPO 3

2 -

_____ n) HClO _____

o) MnO 2

_____ p) KClO 3

_____

q) PbO 2

_____ r) PbSO 4

_____

s) K 2

SO

4

_____ t) NH 4

_____

u) Na 2

O

2

_____ v) FeO _____

w) Fe 2

O

3

_____ x) SiO 4

4 -

_____

y) NaIO 3

_____ z) ClO 3

_____

aa) NO 3

_____ bb) Cr(OH) 4

_____

cc) CaH 2

_____ dd) Pt(H 2

O)

5

(OH)

2+

_____

ee) Fe(H 2

O)

6

3+

_____ ff) CH 3

COOH _____

  1. What is the oxidation number of carbon in each of the following substances?

a) CO _____ b) C _____

c) CO 2

_____ d) CO 3

2 -

_____

e) C 2

H

6

_____ f) CH 3

OH _____

  1. For each of the following reactants, identify: the oxidizing agent, the reducing agent, the

substance oxidized and the substance reduced.

a) Cu

2+

(aq)

  • Zn (s)

→ Cu (s)

  • Zn

2+

(aq)

Substance oxidized _____ Substance reduced _____

Oxidizing agent _____ Reducing agent _____

b) Cl 2 (g)

  • 2 Na (s)

→ 2 Na

(aq)

  • 2 Cl

(aq)

Substance oxidized _____ Substance reduced ____

Oxidizing agent _____ Reducing agent _____

Substance oxidized _______ Oxidizing agent ________

Cr 2

O

7

2 —

+ClO 2

→Cr

3+

+ClO 4

Substance reduced ________ Oxidizing agent ________

O

3

+H

2

O+SO

2

®SO

4

2 —

+O

2

+2H

Substance oxidized __________ Reducing agent __________

As 2

O

3

+NO

3

+H

2

O+H

→H

3

AsO 4

+NO

Substance reduced __________ Reducing agent __________

  1. Circle each formula that is able to lose an electron

O

2

Cl

Fe Na

Redox Half Reactions and Reactions WS #

Define each

(g)

Oxidation - loss of electrons

(g)

Reduction - gain of electrons

(g)

Oxidizing agent - causes oxidation by undergoing reduction

(g)

Reducing agent - causes reduction by undergoing oxidation

Write half reactions for each of the following atoms or ions. Label each as oxidation or reduction.

  1. Al ® Al

3

+ 3e

-

oxidation

  1. Ba

2+

+ 2e

® Ba reduction

  1. Ca ® Ca

2+

+ 2e

-

oxidation

  1. Ga

3+

+ 3e ® Ga reduction

5. H

2

® 2H

+

+ 2e

-

oxidation

6. 2H

+

+ 2e ® H 2

reduction

Balance each spontaneous redox equation. Identify the entities reduced and oxidized. State the

reducing agent and the oxidizing agent.

  1. Al & Zn

2+

i. 2Al + 3Zn

2+

→ 2Al

3+

+ 3Zn

ii. oxidized reduced

iii. reducing agent oxidizing agent

2. F

2

& O

2 -

i. 2F 2

+ 2O

2 -

→ 4F

-

+ O

2

ii. reduced oxidized

iii. oxidizing agent reducing agent

3. O

2

& Ca

i. 2Ca + O 2

→ 2Ca

2+

+ 2O

2 -

ii. oxidized reduced

iii. reducing agent oxidizing agent

  1. Al

3+

& Li

aa) NO 3

5 bb) Cr(OH) 4

cc) CaH 2

- 1 dd) Pt(H 2

5

(0H)

2+

ee) Fe(H 2

O)

6

3+

+3 ff) CH 3

COOH 0

(g)

What is the oxidation number of carbon in each of the following substances?

a) CO 2 b) C 0

c) CO 2

4 d) CO 3

2 -

e) C 2

H

6

- 3 f) CH 3

OH - 2

(g)

For each of the following reactions, identify: the oxidizing agent, the reducing agent, the

substance oxidized and the substance reduced.

a) Cu

2+

(aq)

  • Zn (s)

--------> Cu (s)

  • Zn

2+

(aq)

Substance oxidized Zn Substance reduced Cu

2+

Oxidizing agent Cu

2+

Reducing agent

Zn

b) Cl 2 (g)

  • 2 Na (s)

--------> 2 Na+ (aq)

  • 2 Cl

(aq)

Substance oxidized Na Substance reduced Cl 2

Oxidizing agent Cl 2

Reducing agent

Na

WS # 3 Spontaneous and Non-spontaneous Redox Reactions

Describe each reaction as spontaneous or non-spontaneous.

  1. Au
  • Fe

-----> Fe

  • Au nonspontaneous (two oxidizing

agents)

  1. Pb + Fe

------> Fe

  • Pb

spontaneous

  1. Cl 2

+ F

------> F

2

  • 2Cl

nonspontaneous (see exp 9)

2 I

+Cl 2

® 2 Cl

+I

2

spontaneous(see exp 9)

  1. Pb
  • Fe

------> Fe

  • Pb nonspontaneous

Can you keep 1 M HCl in an iron container. If the answer is no, write a balanced equation for the

reaction that would occur. No, iron is above hydrogen in the activity series. The metal will

react with acid

Fe + 2H

+

--------> Fe

2+

+ H

2

Can you keep 1 M HCl in an Ag container. If the answer is no, write a balanced equation for the

reaction that would occur.

Yes. There is no reaction. Silver is below hydrogen in the activity series

Can you keep 1 M HNO 3

in an Au container. If the answer is no, write a balanced equation for the

reaction that would occur. (Remember, HNO 3

consists of two ions H

and NO 3

Yes. There is no reaction.

Circle each formula that is able to lose an elecron

O

2

Cl

-

Fe Na

Determine the oxidation number for the element underlined.

PbSO 4

6 ClO 3

HP 0

3

2 -

3 Na 2

O

2

CaH 2

- 1 Al 2

(SO

4

3

NaIO 3

5 C

4

H

12

Al

3+

  • Zn ---------> Al + Zn

2+

Substance oxidized Zn Oxidizing agent Al

3+

Cr 2

O

7

2 -

  • ClO 2
  • ------------>

Cr

3+

  • ClO 4

Substance reduced Cr 2

O

7

2 -

Oxidizing agent Cr 2

O

7

2 -

State the Oxidation Number of each of the elements that is underlined.

a) NH 3

- 3 b) H 2

SO

4

c) ZnCO 3

4 d) Al(OH) 3

e) Na 0 f) Cl 2