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Solving Percent Problems using Proportions, Lecture notes of Pre-Calculus

How to solve percent problems using proportions instead of the basic percent equation. It provides examples and step-by-step instructions for writing and solving proportions to find the amount or percentage of a base. This method is useful for various types of percent problems.

Typology: Lecture notes

2021/2022

Uploaded on 09/12/2022

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Percent Problems: Proportion Method
To solve percent problems using proportions
Problems that can be solved using the basic percent equation can also be solved
using proportions.
The proportion method is based on writing two ratios. One ratio is the percent ratio,
written as 100
percent . The second ratio is the amount-to-base ratio, written as base
amount .
These two ratios form the proportion:
base
amountpercent =
100
To use the proportion method, first identify the percent, the amount, and the Base (the
base usually follows the phrase “percent of”).
Example 1: What is 23 % of 45?
45100
23 n
=
23(45) = 100n
1035 = 100n
100
100
100
1035 n
=
10.35 = n
Example 2: What percent of 25 is 4?
25
4
100
=
n
25n = 100(4)
25n = 400
%16
25
400
25
25 === n
n
Math 0300
Student Learning Assistance Center - San Antonio College
1
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Percent Problems: Proportion Method

To solve percent problems using proportions

Problems that can be solved using the basic percent equation can also be solved using proportions.

The proportion method is based on writing two ratios. One ratio is the percent ratio,

written as 100

percent (^). The second ratio is the amount-to-base ratio, written as base

amount (^).

These two ratios form the proportion:

base

percent (^) = amount 100

To use the proportion method, first identify the percent, the amount, and the Base (the base usually follows the phrase “percent of”).

Example 1: What is 23 % of 45?

(^23) = n

23(45) = 100n

1035 = 100n

(^1035) = n

10.35 = n

Example 2: What percent of 25 is 4?

n =

25n = 100(4)

25n = 400

25 n = = n =

Math 0300

Student Learning Assistance Center - San Antonio College 1

Example 3: 12 is 60% of what number?

n

60n = 100 (12)

60n = 1200

60 n =

n = 20

To solve application problems

Example 4: An antiques dealer found that 86 % of the 250 items that were sold for under $1000. How many items sold for under $1,000?

Strategy To find the number of items that sold for under $1000, write and solve a proportion, using n to represent the number of items sold (amount) for less than $1000. The percent is 86% and the base is 250.

Solution

100 250

(^86) = n

86(250) = 100 n

21,500 = 100 n

21 , (^500) = n

215 = n

215 items sold for under $1,000.

Math 0300

Student Learning Assistance Center - San Antonio College 2