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Perpendicular Lines: Finding Slope and Equations, Exercises of Linear Algebra

Examples and exercises on how to find the slope and equation of perpendicular lines. Perpendicular lines are those that intersect at a right angle and have slopes that are the negative reciprocal of each other. various examples with different slopes and points, and shows how to use the point-slope form to find the equation of a line that is perpendicular to a given line.

Typology: Exercises

2021/2022

Uploaded on 09/12/2022

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16-week Lesson 17 (8-week Lesson 13) Perpendicular lines
1
Example 1: The two lines given below are perpendicular. What do you
notice about the slopes of those two lines?
๐’๐Ÿ and ๐’๐Ÿ have slopes that are the negative reciprocal of each
other (๐’๐Ÿ ๐’Ž = ๐Ÿ’
๐Ÿ‘, ๐’๐Ÿ ๐’Ž = โˆ’ ๐Ÿ‘
๐Ÿ’). This is true not just for these two
lines which are perpendicular, but for all perpendicular lines.
Perpendicular lines:
- two lines that intersect at a right angle (90ยฐ)
- the slopes of the lines are the negative reciprocal of each other
(opposite signs, flipped over)
o if two lines are perpendicular, and the slope of the first line is ๐‘š,
the slope of the second line is โˆ’1
๐‘š
-5
-4
-3
-2
-1
0
1
2
3
4
5
-5 -4 -3 -2 -1 0 1 2 3 4 5
Two points
that ๐‘™1
passes
through:
(0,โˆ’2),(3,2)
Slope of ๐‘™1:
๐‘š = โˆ†๐‘ฆ
โˆ†๐‘ฅ =4
3
Two points
that ๐‘™2
passes
through:
(โˆ’4,4),(0,1)
Slope of ๐‘™2:
๐‘š = โˆ†๐‘ฆ
โˆ†๐‘ฅ =โˆ’3
4
To find the
slope of ๐‘™1
(the blue
line) or ๐‘™2
(the red line),
simply pick
any two
points that ๐‘™1
passes
through, and
then find the
vertical
change
divided by
the
horizontal
change
(๐‘š = โˆ†๐‘ฆ
โˆ†๐‘ฅ)
๐‘™1
๐‘™2
pf3
pf4
pf5

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Example 1 : The two lines given below are perpendicular. What do you

notice about the slopes of those two lines?

๐Ÿ

and ๐’

๐Ÿ

have slopes that are the negative reciprocal of each

other (๐’

๐Ÿ

๐Ÿ’

๐Ÿ‘

๐Ÿ

๐Ÿ‘

๐Ÿ’

). This is true not just for these two

lines which are perpendicular, but for all perpendicular lines.

Perpendicular lines:

  • two lines that intersect at a right angle (90ยฐ)
  • the slopes of the lines are the negative reciprocal of each other

(opposite signs, flipped over)

o if two lines are perpendicular, and the slope of the first line is ๐‘š,

the slope of the second line is โˆ’

1

๐‘š

0

1

2

3

4

5

-5 -4 -3 -2 -1 0 1 2 3 4 5

Two points

that ๐‘™

1

passes

through:

( 0 , โˆ’ 2 ), ( 3 , 2 )

Slope of ๐‘™

1

:

๐‘š =

โˆ†๐‘ฆ

โˆ†๐‘ฅ

=

4

3

Two points

that ๐‘™

2

passes

through:

( โˆ’ 4 , 4

) ,

( 0 , 1

)

Slope of ๐‘™

2

:

๐‘š =

โˆ†๐‘ฆ

โˆ†๐‘ฅ

=

โˆ’ 3

4

To find the

slope of ๐‘™

1

(the blue

line) or ๐‘™

2

(the red line),

simply pick

any two

points that ๐‘™

1

passes

through, and

then find the

vertical

change

divided by

the

horizontal

change

(๐‘š =

โˆ†๐‘ฆ

โˆ†๐‘ฅ

)

๐‘™

1

๐‘™

2

Example 2: Find the slope of a line that is perpendicular to the line

2

3

๐‘ฅ โˆ’ 4. Enter exact answers only (no approximations).

When a linear equation is expressed in slope-intercept form, like

2

3

๐‘ฅ โˆ’ 4 , the slope is simply the coefficient of ๐‘ฅ. So in this case the

slope is

2

3

In order to be perpendicular to the line ๐‘ฆ =

2

3

๐‘ฅ โˆ’ 4 , any other line must

have a slope that is the negative reciprocal of that. So perpendicular lines

must have a slope of โˆ’

Example 3 : Find the slope of a line that is perpendicular to the line

9 ๐‘ฅ โˆ’ 4 ๐‘ฆ = 5. Enter exact answers only (no approximations).

Example 6 : Find the equation of the line that passes through the point

๐ด( 7 , โˆ’ 3 ) and is perpendicular to the line 2 ๐‘ฅ โˆ’ 5 ๐‘ฆ = 8. Enter exact

answers only (no approximations), and write the equation in slope-

intercept form (๐‘ฆ = ๐‘š๐‘ฅ + ๐‘), if possible.

Example 7 : Find the equation of the line with a ๐‘ฆ-intercept of 2 , that is

perpendicular to the ๐‘ฆ-axis. Enter exact answers only (no

approximations), and write the equation in slope-intercept form

(๐‘ฆ = ๐‘š๐‘ฅ + ๐‘), if possible.

Keep in mind that horizontal lines have a slope of zero and are of the form

๐‘ฆ = #, while vertical lines have an undefined slope and are of the form

The ๐‘ฆ-axis is a vertical line. A line

perpendicular to the ๐‘ฆ-axis would be a

horizontal line. That means its slope would

be zero.

Example 8 : Find the equation of the line with an ๐‘ฅ-intercept of 5 , that is

perpendicular to the line 5 ๐‘ฅ + 9 ๐‘ฆ =

1

8

. Enter exact answers only (no

approximations), and write the equation in slope-intercept form

, if possible.

On this problem Iโ€™ll start by converting the linear equation 5 ๐‘ฅ + 9 ๐‘ฆ =

1

8

from general form to slope-intercept form so I can identify its slope.

Now that I know the slope of the given line is โˆ’

5

9

, I know that in order for

another line to be perpendicular to the given line, its slope must be the

negative reciprocal of that (

9

5

). So I now have the slope of the line Iโ€™m

trying to find (๐‘š =

9

5

). And since the line Iโ€™m trying to find has an ๐‘ฅ-

intercept of 5 , I also have a point that I can use ( 5 , 0 ). So now Iโ€™ll plug

this information into point-slope form:

1

1